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有一個學生的結構如下

struct Student {

   int grade[20];

   int count;

};

grade 陣列裡儲存的是每位學生的成績, count 裡儲存的是該位學生共修習多少科目,請用這個結構實作以下函數。

int average_grade(struct Student s);

該函數傳入一個學生的結構,然後計算出該學生的平均後回傳。
[Exercise] Essay (Open question) - asked in 作業 by (18k points)
ID: 19793 - Available when: Unlimited - Due to: Unlimited
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23 Answers

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Hidden content!
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}
answered by (-186 points)
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Hidden content!
int * ** student s)

{

int sum=0,i,ave;
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answered by (-102 points)
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Hidden content!
int average_grade(struct Student s)

{
*** ** * ** i;
*** * * ** * * * * sum=0;
* ** * ** * * ** **** ** **** **
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** * * * * ** sum;

}
answered by (156 points)
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Hidden content!
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struct Student {


* ** **** **** *** * * grade[20];


** * * *** ** * * count;



};



float average_grade(struct Student s);

int main(void) {
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float average_grade(struct Student s){
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}
answered by (-38 points)
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Hidden content!
struct student {
** ** * **** *** grade[20];
** *** * * ****** count;

};



int ******* * student s) {
* * * *** ** * ** * * avg =0,
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** * ** * * * = sum / s.count;
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}
answered by (-170 points)
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Hidden content!
int ***** ** *** * Student s)

{
* * ** **** ***** * *** i, sum = 0, avg = 0;
**** * **** *** ** ** * = 0; i * * * ** i++)
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* * *** * * * ***** * = sum / s.count;
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}
answered by (-202 points)
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Hidden content!
int ** ** * * ** Student s)

{
** ** ****** * * *** ** sum = 0,avg = 0, i;
* * ** ** * * ** ** * * * (i = 0; i < * * i++)
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** * * **** * ** ** ** = sum / *


** ** * * ** * *** * ** avg;

}
answered by (-214 points)
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Hidden content!
** ** ** * *** { * * * *** ** * * ** * *** = * ** ** * ** }
answered by (-202 points)
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Hidden content!
int average_grade(struct Student s)

{
* * * **** * Student s;
* * * * *** *** i;
** * * * *** * sum=0;
***** *** * * * ** * **
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** * ** ** * * * * * * **
** * * ** * * *
* * ** *** *** ** ** * sum;

}
answered by (156 points)
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Hidden content!
int average_grade(struct Student a,struct Student b)

{
*** * *** ** *** * * Student c;
** * * ** * * i;
***** * ** *** sum=0;
**** ** ** *** * * * *
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*** * ****** * * * * * * * ** *** = sum + c.grade[i];
* ** * * ** ** **** ** * *
* *** * ** ** ** ***
* ** * ** * * * sum;

}
answered by (156 points)
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