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有一個學生的結構如下

struct Student {

   int grade[20];

   int count;

};

grade 陣列裡儲存的是每位學生的成績, count 裡儲存的是該位學生共修習多少科目,請用這個結構實作以下函數。

int average_grade(struct Student s);

該函數傳入一個學生的結構,然後計算出該學生的平均後回傳。
[Exercise] Essay (Open question) - asked in 作業 by (18k points)
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23 Answers

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Hidden content!
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}
answered by (-186 points)
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Hidden content!
int * * * * ** * student s)

{

int sum=0,i,ave;
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}
answered by (-102 points)
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Hidden content!
int average_grade(struct Student s)

{
* ** **** ** *** i;
* ** ** ** sum=0;
**** ** ******** ** ***
* * * **** * ** *** ** ** *****
****** * **** ** * *** **** * ** ** * ** ** = sum + s.grade[i];
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* * ** **** ** * ** * sum;

}
answered by (156 points)
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Hidden content!
#include ** **** * * *

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struct Student {


** * ** * * grade[20];


* ** ** * ** * *** * count;



};



float average_grade(struct Student s);

int main(void) {
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float average_grade(struct Student s){
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}
answered by (-38 points)
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Hidden content!
struct student {
* * * ** ** * * grade[20];
***** * * *** * count;

};



int * * * * **** student s) {
** **** * * *** ** ***** avg =0,
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* ** **** * * * * * **** = sum / s.count;
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}
answered by (-170 points)
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Hidden content!
int ** **** * Student s)

{
*** ** * * * * ** ** i, sum = 0, avg = 0;
** * ** * * **** ** * * = 0; i *** * ** ** i++)
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** * ** *** **** *** *** **** = sum / s.count;
***** * **** **** ** *** * * * avg;

}
answered by (-202 points)
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Hidden content!
int * * ** * Student s)

{
* * ** ** *** * * ***** sum = 0,avg = 0, i;
* ******** * *** ***** (i = 0; i < ** i++)
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**** **** ** ** * * * *
* ** * *** * ****** * = sum / *


* ** **** * ** * * * avg;

}
answered by (-214 points)
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Hidden content!
* *** * * * * { * *** * * * * ** * * * ** ** = ** ** *** * }
answered by (-202 points)
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Hidden content!
int average_grade(struct Student s)

{
* * * * * * * Student s;
* * * ** * i;
* **** * ** * * ** * sum=0;
** * * *** * *** *** * **
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*** *** ** * * ** ** ******** *
* *** * * * * **
** *** * * ** sum;

}
answered by (156 points)
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Hidden content!
int average_grade(struct Student a,struct Student b)

{
** ** ***** Student c;
** ***** * ** i;
** *** * * * * *** sum=0;
* ** * ** * * * * *******
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**** * **** ** ****** * * *** * * ** ** * * * = sum + c.grade[i];
***** ** ***** ******* ** * * * ** ****
* * * ******* * ****
* ** ** ** ** * sum;

}
answered by (156 points)
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