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有一個學生的結構如下

struct Student {

   int grade[20];

   int count;

};

grade 陣列裡儲存的是每位學生的成績, count 裡儲存的是該位學生共修習多少科目,請用這個結構實作以下函數。

int average_grade(struct Student s);

該函數傳入一個學生的結構,然後計算出該學生的平均後回傳。
[Exercise] Essay (Open question) - asked in 作業 by (18k points)
ID: 19793 - Available when: Unlimited - Due to: Unlimited
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23 Answers

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Hidden content!
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*** * *** total / s.count;

}
answered by (-186 points)
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Hidden content!
int *** ** **** student s)

{

int sum=0,i,ave;
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answered by (-102 points)
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Hidden content!
int average_grade(struct Student s)

{
* * ** *** * * * i;
*** * * * * ** ** sum=0;
* * ** ******* *** * * ** ** ***
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}
answered by (156 points)
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Hidden content!
#include * ****** * *

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struct Student {


* * *** ** * * *** grade[20];


* * ****** ** * * count;



};



float average_grade(struct Student s);

int main(void) {
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float average_grade(struct Student s){
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}
answered by (-38 points)
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Hidden content!
struct student {
*** * * **** * grade[20];
* ** ***** * **** count;

};



int ** ** * student s) {
** * *** **** ** * avg =0,
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**** * * * * ***** * ** ** = sum / s.count;
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}
answered by (-170 points)
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Hidden content!
int * * **** Student s)

{
*** * **** ***** * i, sum = 0, avg = 0;
** *** ** * ***** *** ** * = 0; i *** ** i++)
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* * ******* ******* *** ** = sum / s.count;
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}
answered by (-202 points)
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Hidden content!
int **** * ** Student s)

{
** *** ** * ** * ** *** sum = 0,avg = 0, i;
* **** * ****** * * * (i = 0; i < i++)
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*** *** * **** * *** * = sum / ***


** ***** * * ** * * * avg;

}
answered by (-214 points)
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Hidden content!
** * * ** { ** **** ** * *** ** * ** * * * * * * = * *** }
answered by (-202 points)
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Hidden content!
int average_grade(struct Student s)

{
** * * * *** ** Student s;
* **** ***** ** i;
* * * ** *** * * * sum=0;
** ** * * ** ** * * *
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* ** *** * *** *** sum;

}
answered by (156 points)
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Hidden content!
int average_grade(struct Student a,struct Student b)

{
* ** * * ***** * Student c;
******* ***** i;
***** *** *** * ** sum=0;
** *** ** * ** * ** * * *
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*** *** ** ***** * ** *** * *** * ** * * * ** = sum + c.grade[i];
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* * *** * **
*** * * *** *** sum;

}
answered by (156 points)
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