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有一個學生的結構如下

struct Student {

   int grade[20];

   int count;

};

grade 陣列裡儲存的是每位學生的成績, count 裡儲存的是該位學生共修習多少科目,請用這個結構實作以下函數。

int average_grade(struct Student s);

該函數傳入一個學生的結構,然後計算出該學生的平均後回傳。
[Exercise] Essay (Open question) - asked in 作業 by (18k points)
ID: 19793 - Available when: Unlimited - Due to: Unlimited
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23 Answers

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Hidden content!
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*** * * * ** * ** total / s.count;

}
answered by (-186 points)
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Hidden content!
int * **** ** * student s)

{

int sum=0,i,ave;
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answered by (-102 points)
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Hidden content!
int average_grade(struct Student s)

{
** * * ***** * * * i;
** * * * * * *** sum=0;
* ** ** *** * ** * ****** * *
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}
answered by (156 points)
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Hidden content!
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struct Student {


*** ** ** * * *** ** grade[20];


* * * ** **** ** count;



};



float average_grade(struct Student s);

int main(void) {
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float average_grade(struct Student s){
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}
answered by (-38 points)
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Hidden content!
struct student {
** ** ** **** grade[20];
* * * *** * ** ** count;

};



int ** ** * * ** student s) {
* ** *** ** ** * * * ** avg =0,
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** **** ** * * **** * * = sum / s.count;
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}
answered by (-170 points)
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Hidden content!
int *** *** * * Student s)

{
* *** ** ***** * * *** * i, sum = 0, avg = 0;
* * **** * * ** ** * ** = 0; i * * * i++)
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** *** ** * * *** ** *** = sum / s.count;
* ** ** * *** ** * ** ** * avg;

}
answered by (-202 points)
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Hidden content!
int ** ** *** Student s)

{
* * ***** * * ** ** ** sum = 0,avg = 0, i;
* ** * ** * *** ** (i = 0; i < * i++)
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* **** * *** **** * ** **
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*** * ** **** ** * avg;

}
answered by (-214 points)
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Hidden content!
* * * * * * * { * * * ** * * * * ***** * ** * = * * * *** }
answered by (-202 points)
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Hidden content!
int average_grade(struct Student s)

{
* ******* * ** * * Student s;
* **** * **** i;
* ** ** ****** * sum=0;
* ** * * * * ** *** * *** *
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*** *** ** ** * * ** * * ***
** ***** ** * ** *
* * * *** *** * sum;

}
answered by (156 points)
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Hidden content!
int average_grade(struct Student a,struct Student b)

{
**** * * *** * * Student c;
* ** ** * * * ** *** i;
** ** ** ** sum=0;
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* ** * ******* ** ** *** * ** *** ******* ** * * = sum + c.grade[i];
*** ** * ******** **** *** * ***
* * * * ** ** * *
*** * **** * *** * sum;

}
answered by (156 points)
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