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AD 20161201 第二次期中考 第二題
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時鐘上有時針有分針，分針每一分鐘跳一次，分針每跳一次時針也會前進相對應的角度。請設計一程式，由使用者輸入一個時間，程式會計算出時針與分針間的夾角後輸出。
輸入說明：輸入包含兩個正整數，兩個數之間由一個空白隔開，第一個數字代表時，第二個數字代表分。
輸出說明：請輸出時針與分針間較小的那個夾角。
輸入範例：
12 31
輸出範例
170.5
[Exercise]
Coding (C)
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asked
Dec 1, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
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18k
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ID: 18068 -
Available when:
2016-12-01 18:30:00
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Due to:
2016-12-01 21:00:00
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Dec 1, 2016
by
Shun-Po
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Hidden content!#include<stdio.h>
#include<string.h>
** * ** * * * * *
int main()
{
* * ** ** * *** * * * * * * m,h;
* ** * * ** * * *** * * * * ** * * ** * * *
* ** ** * ****** ** * * * * * *
* * * *** ** * * * *** * ** * **** * * * *** *
*** * *** ** ** ** * ** * * * * *
* *** * ** * * * * * * ** * ** * * * *
** * ** * * ** * * ** * m=h-m;
* * * * ** * ** * ** * * * * ** * ** *
* * * **** * * * *
}
answered
Dec 1, 2016
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410421238
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Hidden content!#include * ** * **** *
#include ** * ** * *
int main()
{
* * ** *** * * * * * clock24, min, clock12, clockp, minp, ang;
** * ** * ** ** * * ** * * * * * * * ** * *
** * * * * * *** * * * * * * *** * * * ** * **
* *** *** * * * ****** ** * (clock24 >= 12)
* ** ** * * ** * ** ** * * * ** * * ** * ** *** * = clock24 - 12;
* * * * * * ** * * * * = * ** * 30) + (min * 0.5));
* * * ** ** * ** ** * * * = (min * 6);
* * * ***** ** * * * ** = clockp - minp;
** ** *** **** * * * ** * *** (ang < 0)
**** ** ** * * * * * * * *
* ** ** * * *** ** * * * ** * * ** * * *** * ** * * * ** = -ang;
* ** * ** * * **
* * * **** * * * (ang > 180)
* * * ** * * * ** * *
**** * * *** *** ** *** * ** * * * * * * * * * * * * = 360 - ang;
* * * **** * * * * ** * *
* * * ** * * ** * ****** * **** * * * ** * ang);
* *** * *** *** * ** ** * * * * * 0;
}
answered
Dec 1, 2016
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410314217
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * **** * * * ***** ** * * * hr = 0;
* ** * ** * **** ** ** **** * * ** min = 0;
*** * * **** * **** * * ** * * * * * %d", &hr, &min);
* ** **** * **** ** * ** angle = 0;
** *** ***** * * * * ** ** >= 12)
*** * ****** * ** * *
* ** * * * * * * ** ** * * * ** * * **** * = hr - 12;
** ** *** * * ** * * *
* * ** * * * *** ** ** m_an = 0;
** * ** * * *** * * * * h_an = 0;
* * ** * * * * * ** * = min * 6;
* * * * * * * * * * ** = hr * 30 + min * 0.5;
* *** ** * * * * * * ** * ** > h_an)
* ** * * * * * * ** * * *
** * * ** * * * ** * * * * * *** ** * * = m_an - h_an;
* * * *** * ** * * * * *
* * ** * * * * * * * **
* * ** * * **** * ** *
* * * * *** * * ** * * * * * * * * **** * * = h_an - m_an;
** ** ** *** * * * **** *** *
*** ** ** * ** * * * * * * ** > 180)
* * * *** * * **** * * *
* * * * * ** * ** * *** ** ** *** * * * * = 360 - angle;
*** *** * * * * * * *
* * * * * * * * * **** * * * * * ** * * * **** ** angle);
* ***** ** ** * * *** * * ** * ** * * *
* * * * * * * * ** * 0;
}
answered
Dec 1, 2016
by
kyle wen
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * ** ** *** * * * * ** ** ** * a,b,c1,c2;
* * ** * *** ** * * * ** * *** x,y;
* * * * * * * * ** ** * * ** * ** *** * * * ** * **
* * ** * * *** ** * *
** * * * * ** * * * * * * *
* * * ** * * * * *
* * * * * ** **** ** ***
**** ** ** **** * * * ** * * *
** *** * *** * * * ** * * * * * * * * * * * * ** * * * ** **
*** *** * ** * ** * ** ** * * * * * *
*** ** * ** * * * * * * ** * **** 0;
}
answered
Dec 1, 2016
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410214219
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * ****** ** *** * *** hr = 0;
** * * * *** ** * * **** min = 0;
* * *** * ** * ** * * *** * ** %d", &hr, &min);
*** ** * * * * ** * * ** angle = 0;
* * *** * * ** * ** * ** * * >= 12)
* * ** * * ** * * ** ** **
*** * * * * * * * * * *** *** ** * ** ** * * * = hr - 12;
** * * * * * ** **** * * * * * *
* * **** * *** *** * * m_an = 0;
* * ** * * * * ** ** * ** ** h_an = 0;
* * * * * * ** * ** = min * 6;
* * * ** ** * ** * * * = hr * 30 + min * 0.5;
***** * ** * **** * ** ** ** > h_an)
**** ** * * ** ** * * *
* ** ** * ** * * * ** * **** * * * * ** ** = m_an - h_an;
* * * * * ** * *** * *
* * ** * **** * ** * * *
* * * * * * ** * * *
* * * * * * ** *** ** ** * * * * ** * * * ** ** * ** = m_an - h_an;
** * *** * *** ** * * *
*** * * * ** ** * * * * * > 180)
** * *** * * **** * ** * ** *
*** * * ** ** * **** * * * * **** * ****** * * * * ** * * = 360 - angle;
* ** ** **** ** * * *
* ** * ** * * * * * ** * * ** * * *** * * ** angle);
* ** * * ** ** ** ** * * * * * * * * **
*** * * * *** * * * * * * 0;
}
answered
Dec 1, 2016
by
kyle wen
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Hidden content!#include * * * * *
#include ** ** * * *
#include ** * * * * *
int main(int argc, char *argv[]){
* * * * * ** ** * * * ** *
** * * ** * * * * *
** * * * * * * * * * *** * * ** * * * ** * * *
* * * * ** ***** * ** = b*6;
* * ** *** * ** * * = a*30;
* * * * * * ** * * * * * * * * += 30*sb/360;
** ** *** * * * ** **** * > 360)
* * * * * **** * * * * ** * * ** * = sa-360;
** ** * *** ** * ** * * = * * * **** *
* * *** * ** ** * * * > 180)
* * *** * * * **** * ** * * ** = s-180;
** ** * * **** * * * *
* * * * * * * ** * * * ** * * * * * * * * * **
*** * * * * *** * ** ** * **
* * * 0;
}
answered
Dec 1, 2016
by
Dhgir.Abien
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * ** * ** * * * *** ** small , big , angle ;
* ** * ** * * * ** hr , min ;
* ** ** * ** * ** * * * ** ** %d",&hr,&min);
* * * * *** ** * * ** * * * ** * *** ** *
* * ** * * ** * * *** ** ** * * * * * *** * ** = hr % 12;
** * * * ** ** *** * = hr*30 + min*0.5;
* ** * * ** * * * *** * * = min*6 ;
* * * **** **** * * *
*** * * * * * ** *** ** * * * * **
* *** * * ** ** * * *** ** ** ** ** ** ** * * * = big - small ;
* * * * ****** * * * * ***
** * * ** * ** ** * * * * **** * *** * * * = small - big ;
* * * ** * * * * * ** ** * * * ** * * *
** * ** * * ** * ***** * **** ** * ** ** * * * * * * ** * * *
* * * * * * *** * * * ** *
* * * * ** ** * * * ******* *** ** * * * * *** * * ** * * *** * ** *
* ** * * * * * * * * * * **
* * * * * * * * ** **** *** ** * * ** *** * *** * *
* * * * ** * * * * ** ** * 0;
}
answered
Dec 1, 2016
by
Phoenix666
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * *** * * * * * * * * *** * small , big , angle ;
* * * * * * ** * hr , min ;
* * * ***** * ** ** * ** ** ** * %d",&hr,&min);
* * * **** * *** * *** ** * * ** * *
* * ** ** ** * * *** * ** ** ** * * ** * ** ** = hr % 12;
*** *** * * ** * * * * * ***** = hr*30 + min*0.5;
* * ** *** *** *** * ** * = min*6 ;
** * * ** * * * * ** * ****
* * ** ** * * * ** * * * * * *
* * * *** * * * * * * * * * * * * ** = big - small ;
* ** * * * ** *** ** * ** *
** * ** ** * * ** * * ** * * ** * * * * *** ** * * * * = small - big ;
* ** * * *** ** * ** ** * * * *
* * * ** * ** * ** ** ** * * * * *** * *** ** * ** * * * *** * * *
* ***** * *** *** * *** * *
* ** ** ** * * ** * ** ** * * * * *** *** * * ** * ** *
** * * * * * * **
*** * * * *** * ** *** ** * * ** ** * * * * *
* * * * * * * * * ** ** 0;
}
answered
Dec 1, 2016
by
Phoenix666
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * * * * *** * * * ** i, j, a;
** ** * * * * * * ** b,c,d,e,f,q,w;
* * * * * *** * * ** *** * * * * ** * ** * ******
** * * * * * * * ** * * * ** * ** ** *
* * ** ******* ** * ** * * = j*6;
** * * ** * * ** **** = i*30+j*0.5;
* ***** ** ** * * ** ** ** * * = b-a;
* * * * * * * **** = b+360-a;
e = a-b;
f = a-b+360;
* * ** * * * * ** * * ** < 0)
* * * * * * * * * ** **
* * ***** ** * * ** **** * ** < 0)
* * * ** * * * * ** * *** *
* * * * * * ** *** ** < 0)
* * * * **** * * ** **** *
** ** * * * * * * * < 0)
* * * ** *** ** * * * * * *
* ** ** * ** ** * ** * < d)
*** * * * * ** * * * * ** * * * * * * * **** = c;
* * * * ***** * *** *
* * * * * ** * ** ** ** * * * * * * ** * * = d;
* * * ** * * * * * * **** **** < f)
* *** * * * * * * * * * *** *** = e;
* * * *** *** * * * * *
** * * * ** * * * ** * * * * * * * * * ** * = f;
* ** * * * * ** * < f)
** ** * ** * ***** * * * * * * * * * * * * * * * * * * *
* * *** * * ** * * *** * * *
** * * ** * * *** * ** * * * *** * * * * ** *** * * * * * ***
** * * * ** * ** * * * ** * * *
* * * * * * ** * * *** 0;
}
answered
Dec 1, 2016
by
楊傑宇
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Hidden content!#include ** * * ** * *
#include * * * *
#include * * * * ***
int main(int argc, char *argv[]){
* * * ** * * ** ** **** ** ** * a,b,sa,sb,s;
* *** ** * * * * ** **
* * *** * * *** ******** * ** ****** *** * ** *** * * *
** * * ** ** * * * * ****** ** = b*6;
* * ** * * ** * * = a*30;
** * * * ** * ** * * * *** * * * * * * *** * ** ***
* ***** * ** * * * **** * ** * * = * **** *** *
* * * * ** * * *** *** * * ** * *
* ** * **** ** * ** * *** * * * * > 180)
* * * ** * ** * ** * * * ** * * * ** * = s%180;
*** * * ** * **** * *
** *** ** ** ** ** * * *** * * * ** * ** * *
* * *** * ** * * * * * * *
* *** * * **** * * 0;
}
answered
Dec 1, 2016
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Dhgir.Abien
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AD 20161201 第二次期中考 第五題
[Exercise]
Coding (C)
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asked
Dec 1, 2016
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2016-1 程式設計(一)AD
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Shun-Po
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ID: 18074 -
Available when:
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AD 20161201第二次期中考 第四題
[Exercise]
Coding (C)
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AD 20161201 第二次期中考 第三題
[Exercise]
Coding (C)
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ID: 18069 -
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AD 20161201 第二次期中考 第一題
[Exercise]
Coding (C)
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2016-1 程式設計(一)AD
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ID: 18065 -
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AD 20161201 第二次期中考公告
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