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AD 20161201 第二次期中考 第二題
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時鐘上有時針有分針，分針每一分鐘跳一次，分針每跳一次時針也會前進相對應的角度。請設計一程式，由使用者輸入一個時間，程式會計算出時針與分針間的夾角後輸出。
輸入說明：輸入包含兩個正整數，兩個數之間由一個空白隔開，第一個數字代表時，第二個數字代表分。
輸出說明：請輸出時針與分針間較小的那個夾角。
輸入範例：
12 31
輸出範例
170.5
[Exercise]
Coding (C)
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asked
Dec 1, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
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ID: 18068 -
Available when:
2016-12-01 18:30:00
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Due to:
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Dec 1, 2016
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Hidden content!#include<stdio.h>
#include<string.h>
** * ** *** * * **
int main()
{
*** *** * ****** * **** * * * * m,h;
* * * * * **** ** * * * *** * ** ** * * ** * ** * *
* * * * * *** ** * * * * * *
* * ** * * * * ** **** ***** * * ***
** ** * * ** * ** * * ** * * * *
*** *** * ** * * * * * ** * * * * *
* * * * * ** * * * * * * * m=h-m;
* ** * * * ** * * * ** ** * * ***
* ** * * *** ** * *** **
}
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Dec 1, 2016
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410421238
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Hidden content!#include * * * * ** * *
#include * * * * * *
int main()
{
** * * * * ** ** * clock24, min, clock12, clockp, minp, ang;
* ** ** * **** * * * ** * * ** * * ** * ** * *
* **** ** ** * * * ** *** * * * * *** * ** * * * *
* * ** * ** * * ** * *** * (clock24 >= 12)
** * *** * **** * * * ** * * ** * ** ******* ** * * * ** = clock24 - 12;
* * * * ** * ** ** * * * * = * * ** * 30) + (min * 0.5));
* * * * * * ** * * * * * = (min * 6);
* ** *** * ** * ** * = clockp - minp;
* * * * ** * * * ** * * (ang < 0)
* * * ** *** * *** *
* * ** ** * * *** ** * * ** ** * ** * * *** * = -ang;
* * ** * * ** ** ** * * * *
** **** * *** * * * ** (ang > 180)
* * * * ** * * * * * *
* * **** * ** ** ** ** * * * **** * * ** * = 360 - ang;
** ** ** * *** * ** * * *
* * *** *** * **** **** * * ** * * ** * * ang);
* * * * * * * * *** ** * * * 0;
}
answered
Dec 1, 2016
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410314217
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* ** ** ** * * * ** *** * hr = 0;
* * * * * ** *** * * * * * min = 0;
* * * ** * * * ** ** ** * ** %d", &hr, &min);
** * * ** * * * * ** ** * * ** angle = 0;
* ** * * **** * * * ** * * * >= 12)
** * * *** * * * *
* * ** * *** * * * * * **** ** * * **** ** *** * = hr - 12;
* ** ** * ** * * * ** * * * *
* ** ** * ** ***** * ** m_an = 0;
* ** * ** * * * ** h_an = 0;
** * * * * ** * * ** ** ** = min * 6;
* * * * * ** ** * * * * ** = hr * 30 + min * 0.5;
* **** * * ** * * * * * > h_an)
* ** ** * * * * * * ** *
** * ** *** * * *** * * * * ** * * ** * = m_an - h_an;
* * ** ***
** ** * * * * * * *** **
** ** ** **** ** * * * *
* * * ** * * *** * * * * * * * * ** ** * = h_an - m_an;
* ** ***** * ** * ** *
* **** * * ***** * * * > 180)
*** ** * * * *** * * *
** **** ** ** * *** * ** * * ** * *** * * * *** * = 360 - angle;
* * * * * * * *
* * * * ** * *** * *** * * ** ** ** * ** * angle);
** * *** * ** * * * * ****** * * ** * * *
* * * * * * ** * * * ***** ** * 0;
}
answered
Dec 1, 2016
by
kyle wen
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** * *** * ** **** * * * ** a,b,c1,c2;
* * * * * ** * * * * * x,y;
** ** ** * * * * * * * * * ** * ** * * *** **
** * * ** ** * * * * * **
* *** *** * * * * * ** * * *
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* ** * * * * * * * * * * * * ** * *** ****** * *
* ** ** * ** ** * * * * * * 0;
}
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Dec 1, 2016
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410214219
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * ** * * hr = 0;
*** * ** * * * *** *** ** * min = 0;
* ** * ** * * *** * ** * * ** ** %d", &hr, &min);
* ** ** * * * ** * ***** angle = 0;
* * * * * **** * * **** >= 12)
** * * * * * * * * * **
** * * **** * * * *** * *** * * * * * * * * * = hr - 12;
* * ** * * * * *
* * ** * ** *** ** ** * * ** * * m_an = 0;
*** *** ** ** * ** ** * * h_an = 0;
* * * * * * * * * *** * ** = min * 6;
* * * * * *** ** ** * * * = hr * 30 + min * 0.5;
* ** * * * * ** ** ** * * > h_an)
* ** * * * * * * * ** * **
* ** * ** * ** ** * * * * * ** * * * * ** * ** * * = m_an - h_an;
* ** * * ** * ** * * * *
* * * ** * *** ** *
* ** * * *** ** * * * **
* * * ** *** * * * * * * ****** ** ** ** ** = m_an - h_an;
* ** * *** ** * ** * *
* * * * * * ** * * * * * > 180)
* ** * ** * * ** * ***
* * * ** ** * * * *** * * ** * ** * **** * * = 360 - angle;
* * * **** * *
* *** * * ** ** * * * * * ** * * * angle);
* * *** * * ** * ** * * * * * *** * *
* ** * ** * ** *** * * **** 0;
}
answered
Dec 1, 2016
by
kyle wen
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Hidden content!#include **** * * ** *** *
#include * * * * *** * *
#include * *** * * *
int main(int argc, char *argv[]){
* *** * * ** ** * * *** * ** * * *** *
* * * ** * * *
* * ** * * * * * ** * * **** * ** * * * * ** * * * * *
* * ** ** ** *** * * * * = b*6;
* * ** * * *** * * = a*30;
*** *** *** *** * * * * * * += 30*sb/360;
* * * *** * * * * ** > 360)
* * ** ** * * * * * * * * ** *** * * = sa-360;
** ** * * * * = * *** ** * *
* * ** * * * ** > 180)
* *** * * * ***** *** * ** * * * * * * * * * = s-180;
* * **** * ****** *
* ** * ** * * ** * * ** * * ** * * *** * *
**** ** * ** * * * * * ** *
* * ** ** ** 0;
}
answered
Dec 1, 2016
by
Dhgir.Abien
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* ** ** ** * * ** small , big , angle ;
* * * * * * * * ** * * ** hr , min ;
* * *** * * **** ** * * ** * ** %d",&hr,&min);
* * ** ** * ** ** * * * * *** * *
* * * * * * * ** * * * * **** ** * * * ** * = hr % 12;
** * * ** * ***** ** *** * * = hr*30 + min*0.5;
* ** * ** **** * * ** ** * = min*6 ;
* ** * * * ** * * * * *** **
* ** * * ** ** * * * * *
* * * ** * * * ** ** * * *** * * * ** * *** * * = big - small ;
**** * * ** * *
** * * * ** ** ** * * * * ** * ** * ** * * = small - big ;
** * * ** * ** * * *** * ** * *
* * * ***** ** * *** ** * * * * * * * ** ** *** * *** ** * * * *** *
* * * ** ** * ** *
* ** * * * ***** * * * * * * * ** ** ** *** ** * * ***** * **** *
* ** * * * * *** * * *
** * * ** * ** *** * * * ** * * * * ***
* ** * * ** * **** * * * * 0;
}
answered
Dec 1, 2016
by
Phoenix666
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * ** * * ** ** * * * * ** small , big , angle ;
* * * ** * * * * ** ** * ** * hr , min ;
* * *** ** * * ** ** * %d",&hr,&min);
* * * * * * **** ** * *** * * *
* *** * *** * * * * ** * * * * * * * * = hr % 12;
** * * * * * * * * **** = hr*30 + min*0.5;
* * ** * *** = min*6 ;
* * ** * * * * * * ** * *
* * * * * * ** * * ** ** ***** *
* * * * * *** * * ** * * * ** * * * ** * = big - small ;
* * * * * * ** * * * *
* *** * ** * * ** *** * * * * * = small - big ;
* * * * ****** *** * * * ** **** * * * ***
* * * * * ** **** * * * *** * * ** ** * ** * * * ** * ** * * ** * * *
* ** * * ** * * * *
* * * ** ** *** **** * ** * * * * * * * * * * * * ** * * * *
*** * * * ** * * ** *
* * *** *** * ***** * * * ** * *
* ** * * ** ** * * 0;
}
answered
Dec 1, 2016
by
Phoenix666
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * ** * ** * ** * * * * * * i, j, a;
** * * ** ** b,c,d,e,f,q,w;
** * * * * **** * * ** * ** * * * * * * * * ** ***
** * * * ** ** * * ** * * * * * * * * *
** * *** ** * * * = j*6;
* * * *** * *** * * = i*30+j*0.5;
* ****** * * ** ** * * = b-a;
** * * * * * * * = b+360-a;
e = a-b;
f = a-b+360;
* ** * * ** * *** * * < 0)
* * * **** *** * * * * ** ** * *
* * * *** ** * ** * < 0)
* ** * * * ** * * * * ** *** *
* * * ** ** ** *** * ** < 0)
** ** ** ** ** * ** * ***** * * ** *
* * * * ** ** * *** * < 0)
* ** ** * * * * * ** *** ** * *
** * ** **** * * *** * ** < d)
*** * ** * * * * * * * **** * **** * = c;
** *** ** ** * **** * * **
** * ** * **** ** * * ** * * * * *** * * * * ** = d;
* * * * * * * * * * * * * < f)
* * * *** * * **** * * ** * * * * * * * *** * = e;
* * * * * ** * *
* * ** * *** * * ** * * * ** * ** ** = f;
* * * * * * ** < f)
*** * * * * * * * * * ** * * ** * *** * * * * * *** * * * **
** *** *** * * * * ** * *
* * * * * * ** * * * * * ** * ***** ** ** * ** ** *
* * ** ** * * * * * **** ** ** * * * ** ***** *
* * ** * * ** * ** 0;
}
answered
Dec 1, 2016
by
楊傑宇
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Hidden content!#include * * *** ** *
#include **** ** * *
#include * *** * **
int main(int argc, char *argv[]){
* * * * * * * * * * *** a,b,sa,sb,s;
** * * * ** * *
* * ****** * ** * * * * *** ** * * * * * * **
* * * ** *** * * ** * = b*6;
* * *** * * *** * * * = a*30;
* * * *** * * *** **** * ***** ** * ** * * * * * * ** ** ***
* * **** * *** *** ** * * * = * *** *** * *
* * * **** *** * * * * * ** ** * * * * * **
** * ** * * * > 180)
* * * * ** *** * * ** * * * ** * * ** * * * * = s%180;
* * * * * * * ** * ** * *
* ** ** * * *** ** * * ** ** ** ** ** * * **
** **** * * * ** * * * *
**** * * *** * ** 0;
}
answered
Dec 1, 2016
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Dhgir.Abien
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AD 20161201 第二次期中考 第五題
[Exercise]
Coding (C)
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asked
Dec 1, 2016
in
2016-1 程式設計(一)AD
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Shun-Po
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ID: 18074 -
Available when:
2016-12-01 18:30:00
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AD 20161201第二次期中考 第四題
[Exercise]
Coding (C)
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ID: 18072 -
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AD 20161201 第二次期中考 第三題
[Exercise]
Coding (C)
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ID: 18069 -
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AD 20161201 第二次期中考 第一題
[Exercise]
Coding (C)
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2016-1 程式設計(一)AD
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ID: 18065 -
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AD 20161201 第二次期中考公告
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