1 like 0 dislike
4.6k views
請設計一個程式,利用迴圈輸出文字菱形。

p.s. 輸入皆為奇數

範例輸入1:

5

範例輸出1:

  *

 ***

*****

 ***

  *
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15388 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

reshown by | 4.6k views
0 2
Called for Help
0 0
#include <stdio.h>
#include <stdlib.h>

int main()

{
    int a,n,m,k;
    scanf("%d",&a);
    for(n=1;n<=a;n=n+2)
    {
        for(k=(a-n)/2;k>0;k--)
        {
            printf(" ");
        }
        for(m=1;m<=n;m=m+1)
        {
            printf("*");
        }
        printf("\n");
    }
    for(n=a-2;n>0;n=n-2)
    {
        for(k=(a-n)/2;k>0;k--)
        {
            printf(" ");
        }
        for(m=1;m<=n;m=m+1)
        {
            printf("*");
        }
        printf("\n");
    }
    return 0;
}

42 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>



int main()

{
* * ** * * ***** * * num,i,j;
***** *** ** * * * *** *** ** ****
** * *** ** * * *** (j=1; j<=num/2+1; j++)
* ** *** *** * * * *
* * ******** * * * ** * * * * *** (i=0; i<num/2+1-j; i++)
* ** * *** ** * ** ** * * ** * ** * *** ** ** * * ** ");
* ******** *** * **** ** * * * * * (i=0; i<(j-1)*2+1; i++)
*** * ** ***** *** *** * ** * ** * ***** ** * * ** *** *** ** *
********* * * ** * ****** * * * ** *** *** ** * * ***
* * *** * ******* ***
* * * * ** * * (j=num-(num/2+1); j>0; j--)
* * * *** * ****** * *
* * * * ** * ** * * * ** *** ***** (i=0; i<num/2+1-j; i++)
* * * **** * * *** * * * *** *** ** * * ** * *** * ");
* ****** *** * * * * ** * * ** (i=0; i<(j-1)*2+1; i++)
*** * ** ** ******* * * ** *** *** ***** *** *** ** * * * * ** **
*** ** ** ** ** * * ********** * * * ** ** *
** * *** ******** *

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
* ***** ******** *



int main()

{
** * ** * ** *** ** n, j, k;


* * ** * **** ** * * ** **** * * , &n);
** ** ** ***** ** * = 1; j <= n / 2 + 1;j ++)
* **** *** **
** *** * * * * ** *** ** * *** * = 0;k < n / 2 + 1 - j;k ++)
* * ** ** * **** * * * * * ** * ** ******* ** *** ** ");
*** * * * ** *** ****** *** **** ** ** ** ** * < (j-1) * 2 + 1;k ++)
** * **** ** * ** * *** * *** * *** **** * * * * **
* * ** ****** * * *** *** ** *** * * ***** ******** *** ** *
*** * **
******* * * * **** = n - (n / 2 + 1); j >= 0;j --)
* * *** **** * *
** * *** * * *** ** *** *** * = 0;k < n / 2 + 1 - j;k ++)
*** *** ** * ** * *** *** * * * * ** ** **** ** ** ***** *** **** ");
** *** * * * ** ** ** ** ** * ** * *** < (j-1) * 2 + 1;k ++)
*** * **** *** * * * *** * ** * * * * * * * ** * *
**** *** *** ** **** * ** * * * * * * **
*** ** * * ** ****
* **** *** * * 0;

}
answered by (-114 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.195.61
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15475 - Available when: Unlimited - Due to: Unlimited
| 13 views
0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15447 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.2k views
1 like 0 dislike
37 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15446 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 4.1k views
1 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15442 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 2.1k views
1 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15440 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 2.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users