1 like 0 dislike
3.8k views
請設計一個程式,利用迴圈輸出文字菱形。

p.s. 輸入皆為奇數

範例輸入1:

5

範例輸出1:

  *

 ***

*****

 ***

  *
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15388 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

reshown by | 3.8k views
0 2
Called for Help
0 0
#include <stdio.h>
#include <stdlib.h>

int main()

{
    int a,n,m,k;
    scanf("%d",&a);
    for(n=1;n<=a;n=n+2)
    {
        for(k=(a-n)/2;k>0;k--)
        {
            printf(" ");
        }
        for(m=1;m<=n;m=m+1)
        {
            printf("*");
        }
        printf("\n");
    }
    for(n=a-2;n>0;n=n-2)
    {
        for(k=(a-n)/2;k>0;k--)
        {
            printf(" ");
        }
        for(m=1;m<=n;m=m+1)
        {
            printf("*");
        }
        printf("\n");
    }
    return 0;
}

42 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>



int main()

{
* * * ** * ** num,i,j;
*** * *** **** ** * * * ** **** * * * **
*** ****** * ***** (j=1; j<=num/2+1; j++)
* * ** * * ** *** ** ****
* * * * ** ** **** * **** * * *** * (i=0; i<num/2+1-j; i++)
* * ***** ** * **** *** *** * *** * * ** * ***** * **** * *** ");
* * ** * ** ***** ** ** *** * * (i=0; i<(j-1)*2+1; i++)
* * ** **** ** *** * * ** * * * * *** ******* * *** *
** *** ** * * * * * ** * * ** ***** * ** * * * **
* * **** ** ** * * **
* *** * ** * (j=num-(num/2+1); j>0; j--)
* * *** * * ***
* **** * * * * * * * * * * ** * * * (i=0; i<num/2+1-j; i++)
* *** * ** **** **** * * *** ** *** ** ** ** *** *** * ** * *** ");
** *** * ** * * * ****** ** ** (i=0; i<(j-1)*2+1; i++)
* *** ** **** * ** *** **** **** ** * * * * * ** * * **
*** *** ** * **** * *** ** * * ** ** *
*** ********* ******* **

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
* *** **** ** * * *



int main()

{
**** * * *** ***** * **** n, j, k;


** * * ****** ** * * * ** ** *** , &n);
*** ** * ** * = 1; j <= n / 2 + 1;j ++)
** ** ** *** ** * **
* * ** ** * * ** *** * *** ** = 0;k < n / 2 + 1 - j;k ++)
* ** * *** ****** ****** * ** * ** * * * * ** * ");
* **** * * ** ********* * ** ****** * * < (j-1) * 2 + 1;k ++)
* * *** * * **** * **** *** **** **** ** * * ** ** *** *** * **
*** * **** * ** **** ** *** **** * * ** *** ***
* ** * *
* **** ****** *** * = n - (n / 2 + 1); j >= 0;j --)
**** ** **** ** *
* * * **** ** ** * *** *** **** ** * * = 0;k < n / 2 + 1 - j;k ++)
* **** * * * ** *** * ** ** **** ** *** * ");
* *** * * * ** ** * * ***** ****** * ***** ** < (j-1) * 2 + 1;k ++)
* *** *** * ** ** **** *** * *** ** * * * ** ** **
*** * * * *** * * * ** *** * * *** * ** * ***
* ** * * *** *
*** * *** *** * * 0;

}
answered by (-114 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.133
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15475 - Available when: Unlimited - Due to: Unlimited
| 13 views
0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15447 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 993 views
1 like 0 dislike
37 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15446 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 3.3k views
1 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15442 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.8k views
1 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15440 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users