1 like 0 dislike
4.8k views
請設計一個程式,利用迴圈輸出文字菱形。

p.s. 輸入皆為奇數

範例輸入1:

5

範例輸出1:

  *

 ***

*****

 ***

  *
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15388 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

reshown by | 4.8k views
0 2
Called for Help
0 0
#include <stdio.h>
#include <stdlib.h>

int main()

{
    int a,n,m,k;
    scanf("%d",&a);
    for(n=1;n<=a;n=n+2)
    {
        for(k=(a-n)/2;k>0;k--)
        {
            printf(" ");
        }
        for(m=1;m<=n;m=m+1)
        {
            printf("*");
        }
        printf("\n");
    }
    for(n=a-2;n>0;n=n-2)
    {
        for(k=(a-n)/2;k>0;k--)
        {
            printf(" ");
        }
        for(m=1;m<=n;m=m+1)
        {
            printf("*");
        }
        printf("\n");
    }
    return 0;
}

42 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>



int main()

{
*** * ** ** ** * num,i,j;
** ** * * * *** * ** ** * **
**** **** * * ** * (j=1; j<=num/2+1; j++)
* * ** * ** **** *
****** ** * ** *** *** *** *** * (i=0; i<num/2+1-j; i++)
* * *** * ** * ** ** ****** * * **** ***** * ");
* **** *** ******** * *** * ** * (i=0; i<(j-1)*2+1; i++)
*** * *** *** * ****** * * * ** ****** ***** * * * * * *** ** *** * **
*** * * *** ** ** * * *** * * * * ** ** * *
* ****** * ** * **
* * ** ** * ******** (j=num-(num/2+1); j>0; j--)
** * ** ** **
* ****** * ** * ** * **** (i=0; i<num/2+1-j; i++)
* *** **** ***** ** ** ***** * * * ****** * ** ** * * ");
** ** * * * **** ** * **** * (i=0; i<(j-1)*2+1; i++)
* * * ** * **** ** ** * * * * * *** * * ***** ****** ** ** * * *
* * * * **** * **** * ** ** ** ****** * ** * *
** * * **** * ** **

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
** * ** * * *



int main()

{
* ** * ** ** *** * n, j, k;


* ** * ** ** * * * * * **** , &n);
*** ** * * * = 1; j <= n / 2 + 1;j ++)
* *** * * *
** * * ** ** ** ***** ** * * ******* ** * = 0;k < n / 2 + 1 - j;k ++)
* * * * * ** ***** *** * * *** *** * * * * ** ** ");
* *** *** ***** ***** * ***** * * ** * * ** * * * < (j-1) * 2 + 1;k ++)
* * * ** * *** ** * ** ** ***** * * * ** * * * ** *
**** ** * * * * * * * ***** * * ** ** * *** * * * **
*** * * ** ** **
*** ** ** *** * ** = n - (n / 2 + 1); j >= 0;j --)
* ** *** * *** ****
*** ** * ***** * ** * **** * * ** * * * ** ** = 0;k < n / 2 + 1 - j;k ++)
**** * * ** * * * ** *** *** ** **** *** ***** ** * ");
* ** * * * *** * ** * * * * ** **** < (j-1) * 2 + 1;k ++)
* *** * * * ** * **** * * ** * **** *** ** * * ** *
*** *** ********** * * * ***** *** ***** *** * * **
** * * * *** *
* * * * * * *** ***** 0;

}
answered by (-114 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.39
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15475 - Available when: Unlimited - Due to: Unlimited
| 13 views
0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15447 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.3k views
1 like 0 dislike
37 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15446 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 4.3k views
1 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15442 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 2.2k views
1 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15440 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 2.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users