1 like 0 dislike
4k views
請設計一個程式,利用迴圈輸出文字菱形。

p.s. 輸入皆為奇數

範例輸入1:

5

範例輸出1:

  *

 ***

*****

 ***

  *
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15388 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

reshown by | 4k views
0 2
Called for Help
0 0
#include <stdio.h>
#include <stdlib.h>

int main()

{
    int a,n,m,k;
    scanf("%d",&a);
    for(n=1;n<=a;n=n+2)
    {
        for(k=(a-n)/2;k>0;k--)
        {
            printf(" ");
        }
        for(m=1;m<=n;m=m+1)
        {
            printf("*");
        }
        printf("\n");
    }
    for(n=a-2;n>0;n=n-2)
    {
        for(k=(a-n)/2;k>0;k--)
        {
            printf(" ");
        }
        for(m=1;m<=n;m=m+1)
        {
            printf("*");
        }
        printf("\n");
    }
    return 0;
}

42 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>



int main()

{
* * *** *** **** * * num,i,j;
*** * ** **** *** * * * *** * * ** * ***
* * **** ** * ** (j=1; j<=num/2+1; j++)
* ***** ** **** ** **
** * * *** * *** * * *** (i=0; i<num/2+1-j; i++)
* *** *** ** ** **** *** *** ** * * ** * ** * *** ");
** * * * * * * * * ** ** (i=0; i<(j-1)*2+1; i++)
****** * * *** * ** *** * * ***** ** * ******* * * ****** ** *
** ** **** * ** **** * ** * * ** *** ***** ***
******* **** ** * *
* * ** * ** * ** (j=num-(num/2+1); j>0; j--)
* ** ** * ***** *
* * ***** * *** * *** **** ** * * (i=0; i<num/2+1-j; i++)
* * *** **** ** ** *** *** * ** ** * ** **** ** ");
*** ** * * * * *** ** * * *** (i=0; i<(j-1)*2+1; i++)
** * * ** ** * ***** **** ** * * ** * * ***** ** * ** ******
**** ** ** * * *** ** ** *** *** * ****** *
*** *** ** *** * * *

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
** * ** ** * *



int main()

{
* *** * ** ** * n, j, k;


* **** ** *** *** ** * * * , &n);
* * *** * * **** = 1; j <= n / 2 + 1;j ++)
* * ** * * **
*** ** ****** ** ****** * ***** ** = 0;k < n / 2 + 1 - j;k ++)
* ** * * *** ****** * * ** * *** *** ** * * * * *** ");
*** *** * *** * * ** * ** ** * * ** ** < (j-1) * 2 + 1;k ++)
* * * * ** * ** *** **** **** * * ** ** * * * * * * *
* * ****** * ** * *** *** ** ***** ****** * *** **
**** * ***
* *** * * *** *** *** * = n - (n / 2 + 1); j >= 0;j --)
* ***** ***** * *
* ** * ** ** ** ** * ** ***** ** * * * = 0;k < n / 2 + 1 - j;k ++)
* * * ** * * **** * * ** * **** **** * * * *** * * ");
* * ** * * **** * **** ** ** * *** * < (j-1) * 2 + 1;k ++)
** * ** ** **** * ** ** * * * ** * ***** * *
** ***** * *** * ***** * * ***** ** ** ** * **
* ** * **** * *
* * * * *** * * 0;

}
answered by (-114 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.117
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15475 - Available when: Unlimited - Due to: Unlimited
| 13 views
0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15447 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.1k views
1 like 0 dislike
37 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15446 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 3.6k views
1 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15442 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.9k views
1 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15440 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users