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請設計一程式,由使用者輸入N個數字,求這些數字的平均。使用者輸入的第一個數字N代表接下來會有多少個數字要求平均,接下來的N個數字就是需要計算平均的數。輸出請輸出到小數點後六位。

sample input:

10 1 2 3 4 5 6 7 8 9 10

sample output:

5.500000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15378 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

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#include <stdio.h>
#include <stdlib.h>

int main()

{
    int a,n;
    float c;
    scanf("%d",&a);
    int b[a];
    for(n=0;n<a;n++)
    {
        scanf("%d",&b[n]);
    }
    for(n=0;n<a;n++)
    {
        c=c+b[n];
    }
    printf("%.6f",c/a);
    return 0;
}

102 Answers

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Hidden content!
int main()

{
* * *** * * a;
* ** ** ** * *** * * * * * ** * *

   int num[a],i;
**** ** ************ * ** *******
* * ** * ** * ** ** * *** * ** * ** ** ** ***** ** ** **** *
* * * * *** ** sum,ave;


*** * ** ** * *** * * * ** * **** *
* ** ** * **** * * ** * * * *

ave=sum/a;
** * * ** * * *** **** *

}
answered by (-124 points)
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Hidden content!
#include <stdio.h>



int main()

{
** *** ****** ** * * N;
* ** *** ** *** * * ** * * * ***** * ****
* ** ** ** **** ** * ********** num[N],i;
* * * **** ** *** ave,sum=0;
* * * * *** ** * *** (i=0; i<N; i++)
** ** * * * *** * **
**** *** ** * * *** * ** *** * * * ****** **** *** ** * * *
** * * ** *** *
*** * *** * * ** * (i=0; i<N; i++)
**** **** *** * * ** **
** * * ** * * * ** *** *** *********** **** ** *** = sum + num[i];
* *** * ** *** **
** ** * ** *** ** **** * = sum / N;
* * *** * ** ** ** *** ** *** * ** *



}
answered by (-162 points)
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