[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
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******** * * * * **  *  *    **   *****  * your input:"); //DO NOT CHANGE
 *  ** **  ** ***  *** *  ***  *** * *  *  ** * ****  * 
    
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*       ** * ***  * *   ** ** * = 'A'; a <= 'Z'; a++){
*  **  *   * ** *   * * **  **      ****   ** * ** *   *  *  ** ****  * * *
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****     **** * ***  *   * **   *  *****  * ******   
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*  *  * *   * * *  ***        * * 0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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**  * ***  **   *   **   ** * *

*** *     *  ** ** * **** **    *** 0;
}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include * * **    ***  
#include  *    ******  ***  *

int main(int argc, char *argv[]) {

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*  * *  ** ***    * ***  ******         **  a++;
* * * * *      }

  ** *  *   **  *** return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include ** * * ****  * 
#include *  **   ** * **

int main(int argc, char *argv[]) {

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****   *** *   return 0;
}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include  *        * *****
** **  *   *  *** *** ** *  

int main(int argc, char *argv[]) {

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* * *      *  *  *    * *****   *   ** a++;
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*  *** * **    * return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include * * *   * *  * 
#include   *  * * * *  **

int main(int argc, char *argv[]) {

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  * * *  **   *** return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include  **** **   ****
* **    ** *  **  * 

int main(int argc, char *argv[]) {

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**     ** *   ***    ** **** ***   *  * ** ** a++;
* * ***  *  **  }

** ****   ****  return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
*   * ** ***   *** * 
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int * * argc, char  *     {
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*** ***  **        * * ** **  else
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*  * *  **  *  * * *    **  *  ** a++;
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* ** **** **    
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}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
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    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
**********  *  ** *** ***     * a;
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*   *  ****  *  **  ****  *  *   * * * * *   * ** * *  **  **   * **  * **  *** *   *
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 **    * **  *** **** **** **  
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output