[Exercise 7] ASCII Identification

Question

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Please write a program that can identify a value's characteristic based on ASCII table. It must identify:

0-9 is a digit
A-Z is a capital character
a-z is a small character
Besides those conditions, it shows '%c is unknown'.

Kindly use the given template to finish the task. Be advised that your outputs must be exactly the same as the shown outputs below.

Example(Template)

#include <stdio.h>
#include <stdlib.h>

/* run this program using the console pauser or add your own getch, system("pause") or input loop */

int main(int argc, char *argv[]) {
	char a;
	printf("Define:\n");
	scanf("%c",&a);
	
// Your condition starts from here
	
	return 0;
}

Input#1

Define:
6

Output#1

6 is a digit

Input#2

Define:
A

Output#2

A is a capital character

Input#3

Define:
f

Output#3

f is a small character

Input#4

Define:
/

Output#4

/ is unknown

Suggestion

It's time to use your favourite table: ASCII

[Exercise] Coding (C) - asked Oct 27, 2017 in Chapter 3: Branching, Looping and Functions by nat236919 (5.9k points)
ID: 29618 - Available when: Unlimited - Due to: Unlimited | 925 views

17 Answers

Page:

YT Chiu · Answer 1 · 2018-01-12 22:25:09

Hidden content!
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}

100/100 answered Jan 12, 2018 by YT Chiu (221 points)

Baigeldiev · Answer 2 · 2017-12-15 01:29:49

Hidden content!
#include     * * *  * 
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/* run this program using the console pauser or add your own getch,  *   *  **  * * * * *  or input loop */

int main(int argc, char *argv[]) {
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}

50/100 answered Dec 15, 2017 by Baigeldiev (183 points)

Baigeldiev · Answer 3 · 2017-12-15 01:28:20

Hidden content!
#include <stdio.h>
#include    * *** * * * *

/* run this program using the console pauser or add your own getch, * *** **  * *  *** ***** or input loop */

int main(int argc, char *argv[]) {
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}

answered Dec 15, 2017 by Baigeldiev (183 points)

The Judge · Answer 4 · 2017-12-14 11:46:02

Hidden content!
#include   ***   * ****
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/* run this program using the console pauser or add your own getch, **   ***  *  * *** ** or input loop */

int main(int argc, char *argv[]) {
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}

100/100 answered Dec 14, 2017

Namuun_1029 · Answer 5 · 2017-12-13 15:36:09

prog.c:28:2: error: stray '#' in program
}#include <stdio.h>
  ^
prog.c:28:11: error: expected '=', ',', ';', 'asm' or '__attribute__' before '<' token
}#include <stdio.h>
           ^
In file included from prog.c:29:0:
/usr/include/stdlib.h:826:20: error: unknown type name 'wchar_t'
extern int mbtowc (wchar_t *__restrict __pwc,
                    ^~~~~~~
/usr/include/stdlib.h:830:31: error: unknown type name 'wchar_t'
extern int wctomb (char *__s, wchar_t __wchar) __THROW;
                               ^~~~~~~
/usr/include/stdlib.h:834:25: error: unknown type name 'wchar_t'
extern size_t mbstowcs (wchar_t *__restrict __pwcs,
                         ^~~~~~~
/usr/include/stdlib.h:838:10: error: unknown type name 'wchar_t'
    const wchar_t *__restrict __pwcs, size_t __n)
          ^~~~~~~
prog.c:33:5: error: redefinition of 'main'
int main(int argc, char *argv[]) {
     ^~~~
prog.c:5:5: note: previous definition of 'main' was here
int main(int argc, char *argv[]) {
     ^~~~

Bilegjargal · Answer 6 · 2017-12-13 15:15:27

Hidden content!
#include ***  * *    ** **
#include  *   *** *  

int main(int argc, char *argv[]) {
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}

100/100 answered Dec 13, 2017 by Bilegjargal (220 points)
edited Dec 14, 2017 by Bilegjargal

lee,jiun-hong · Answer 7 · 2017-12-12 22:45:33

Hidden content!
#include<stdio.h>

int main(int argc, char *argv[]){
*  *  *   *** **  *          a;
   *   *   **   *****   *  *    ** **  * *** *  **  * 
**** ** * *   ** * ** *  **********   **  * **      * &a);

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*   **** * ** * *** ****      
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  ***   *  ****** *   ***  *** 
**    **   ** * **  * ***   ***   ***  *    *** *   * *  * * * {
* ** *  **** *  * *  *  *  ** * ** ***** *  *  * * ** * **    is a small character", a);
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 ******    *****  **   * ** **  **    * *   *   ** * *   *  **   *** *** is unknown", a);
** * ** * *   * *     *  * * * 
}

100/100 answered Dec 12, 2017 by lee,jiun-hong (273 points)

410630017 · Answer 8 · 2017-12-10 21:42:41

Hidden content!
* * *** *      ***   
*  *      * * ** ** ** 

*         * **   *  *    *   **          or *  **   *  ** * *** *  *  ******   or  ***   * */

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**  *** *   * * 
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* *  * * **   * **** *  *    
* ***  *  *  *  *   ** c *   ** * ** * *  *   **   c *  'Z' ) // c is a   **      
** *   * * *       * *  
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**   * * ** *    *   * ==  
***    ****  
**    **  *   ** *** *  **** ***   ** *** *****     *   %c is *** **   * * *   

  ** *      *  *  * *    *    * *  
***  *       *** 
*** * *  ** * * *  0;
}

100/100 answered Dec 10, 2017 by 410630017 (153 points)
reshown Dec 17, 2017 by nat236919

410630017 · Answer 9 · 2017-12-10 21:42:38

Hidden content!
** *  * *  * * *** * 
   * *  * * **   * *   * 

**  **   ** *  ** * * * **    **    or  ** * * ** ****  *  ****  *  *** *  or *    *** */

   *     *     * * * *  {
  ****    *       c;
*  *  *   **     *      *
* ** *  *   * *  ***   ** **
****   **        * ** ** * 
  * * *  ** * * 
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* *** *** c =  * * 
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***    ****** **      *** ***  * * ***** is %c ** ***** c);
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  * *****  ****    *   ***    * *   *  *** * %c is a *     **   * c);

*  ***    *    
**   * *  * * if( c *** * * 'a' * * **    c  * * * 'z' ) 
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***   * *  * ***   **  ***   *   
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* ***      **   ** *  *  *     *     **     ****   %c is a ***** **    c );
    ** ***    **       ****    
  ***   *     *  == *  
* ***   *  *  
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  * **      ** **    * **     
*  *  *   **   *  
* **   * **   *  0;
}

100/100 answered Dec 10, 2017 by 410630017 (153 points)

emilie · Answer 10 · 2017-11-01 15:12:05

Hidden content!
*    ****** *   *
* ***   ** *        * 

/* run this    *   *   the   *  * or add your own       **  * * *    ****** * *** or input loop */

int  **  **   char ** **  {
* * *    ****   char a;
* *     ***   ***  *  *** *   *   * *
* * **** * * *  * *   ***  **  **  *  *  **  * 
**** **  ** ** 
* * ****  *    **  *   *  ***
*     *** * ***  ** *** *  * *   *** * *    is a       * * *  a);
* ** ***  *  * *  }
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**  ** *  ***** else  **  **
 **** * ** ** ** **  **** **   *  * *** *  ** ** is a **   ** *  *  a);
 ** *   * * }
   *  * **  * * else{
* ** *   ** *  ** *  *** *   ***** ** is    *   ***  *  
 *    *   ***** * }
// Your    * * **  from here
*  * * **   ******** 
 * *  * *  * * *  0;
}

100/100 answered Nov 1, 2017 by emilie (290 points)
reshown Dec 17, 2017 by nat236919

[Exercise 7] ASCII Identification

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