[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
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  * *****  * **  * ** * *          *     * * your input:"); //DO NOT CHANGE
 **         *  * **  * *  ** *  ***   ** ** *  * *    
    
 * ** **   *** * ** * ** *    Your conditions start from here
* **  **** * * ***** *    *** **   = 'A'; a <= 'Z'; a++){
 **** **  **  ****    * * ** ***** * **  *** **  * * ****  ***   **   * ***
 *  * *   **    *   *  ** *   *** *  *    ** * ** ** *** **** *  *   a == 'A'||a=='E'||a=='I'||a=='O'||a=='U'){
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**  ***   ** *** * **  * * *  ** *     *** *  **      *      **  **** a);
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**** *    * * ***  **  * *** *  ** * ****   *  *** *** * *  ***   * * *  **
**  ***  ***  * ****** ****   0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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  *** ***** ** **      **  ****   ** **   *  *   
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  *  *****   *  ****  ** ** *    *   * *  *  * * * *
*  *  * *    * *  * *****  * *** 

*****        *      * ****  *    0;
}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include **  *  ** ******** 
#include *  *   **    **

int main(int argc, char *argv[]) {

*     ****** char a;
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*   ******  * *      * **  * * * **  *  **   else
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* *** *   *** **         * * ******* *  ****   a++;
 **    ** **  *  }

  *      ****** return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include   *  ** * ** *** 
#include  * ** **   *  *

int main(int argc, char *argv[]) {

   **   *    * char a;
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*** * ** **  **  
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**   ***** ****     ****  **  *   **   *  * ** a++;
*   *    **  * }

* * ** *   * return 0;
}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include   **  *  * * *
*   * * *  ****    * 

int main(int argc, char *argv[]) {

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* ****    ***  
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* **  *  *     *  **  ***   *  ***   else
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*   *** * ** * }

*   **** * **    return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include  **  *** *  *
#include  **  ******** 

int main(int argc, char *argv[]) {

** ** ** **   int a;
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*   *** **   **   ** ***  * *** *    *  *  * * **** *  * * * * ***  *  *   *      ** *
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  *    ** ** ** }

*  *  *  *****  return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include * *  ***  **   *
*** *  ******    ** * ***

int main(int argc, char *argv[]) {

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   * * ***** *** ***    **  *  *  *** ** a++;
 **   * *     * *** }

  * *  *     **  return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
 ** ****     ***** ***
***  *   *  ** *       ** * 

int        argc, char *  *  {
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*** * * * **** 
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*  *********** *   ** *   * * *  *     *****  if(a == 'A' || a == 'E' || a == 'I' || a == 'O' || a == 'U')
**** *   * * *      *   *   **  * *** ** **  * *** ***        *** 
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**      * * *  * ****   *    a++;
*** *  ** *    }
* **    ** * * 
* * * * ***** * return 0;
}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
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** *  * * *  *****   * **** * * * ***     &a);
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*** * **  * **  * *** **    * **  *   *** * **  * *  *  *   
    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
* * * *  ***** ** *****  a;
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******  * *  * ***     *********  *  *  ******  ** &a);fflush(stdin);
*  * * * **  * ***   ****  *  
*    * *   * * *** * * ******  ******  * **   **** * **  * **      ***      
        *** *  ** *  **      ***   ***** * *        ****** ***   ***   *  * *     * *** *   ||i==69 || i==73 || i==79 ||i==85){
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 ** * ***  ** * * *  * *    ******  * **  * *  ** ****  ** * ** ** * * * ********  ***
* * ***   *****     *  *** **** **  * *  * *  ******  ****   **  *   **  
**  **  ***  *** **** *****   **  *     * **** *   *** *  * *** *      *     * * *   **** ** *** *** **  *   * ***   **  * **  *
*   *  ******** ** *   ***  **       **  **** ** *   **   **  ** **  **   
*  *   *  * **  *  * * * ** * * * *  *  * * *****  ****
*  *  **** *   ** ******* *** 
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output