[Exercise 7] ASCII Identification

Question

Please write a program that can identify a value's characteristic based on ASCII table. It must identify:

0-9 is a digit
A-Z is a capital character
a-z is a small character
Besides those conditions, it shows '%c is unknown'.

Kindly use the given template to finish the task. Be advised that your outputs must be exactly the same as the shown outputs below.

Example(Template)

#include <stdio.h>
#include <stdlib.h>

/* run this program using the console pauser or add your own getch, system("pause") or input loop */

int main(int argc, char *argv[]) {
	char a;
	printf("Define:\n");
	scanf("%c",&a);
	
// Your condition starts from here
	
	return 0;
}

Input#1

Define:
6

Output#1

6 is a digit

Input#2

Define:
A

Output#2

A is a capital character

Input#3

Define:
f

Output#3

f is a small character

Input#4

Define:
/

Output#4

/ is unknown

Suggestion

It's time to use your favourite table: ASCII

[Exercise] Coding (C) - asked Oct 27, 2017 in Chapter 3: Branching, Looping and Functions by nat236919 (5.9k points)
Available when: Unlimited - Due to: Unlimited | 313 views

17 Answers

Page:

YT Chiu · Answer 1 · 2018-01-12T15:25:09+0000

Hidden content!
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}

100/100 answered Jan 12, 2018 by YT Chiu (221 points)

Baigeldiev · Answer 2 · 2017-12-14T18:29:49+0000

Hidden content!
#include     * **     * *
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/* run this program using the console pauser or add your own getch, **  * *   *******   or input loop */

int main(int argc, char *argv[]) {
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}

50/100 answered Dec 15, 2017 by Baigeldiev (183 points)

Baigeldiev · Answer 3 · 2017-12-14T18:28:20+0000

Hidden content!
#include <stdio.h>
#include  *  *  *** * ***

/* run this program using the console pauser or add your own getch, * *  * * **   ********* or input loop */

int main(int argc, char *argv[]) {
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*** **  **  ***  * 
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}

answered Dec 15, 2017 by Baigeldiev (183 points)

The Judge · Answer 4 · 2017-12-14T04:46:02+0000

Hidden content!
#include  * ** ***** *   
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/* run this program using the console pauser or add your own getch, *** *   ***  ** * *** or input loop */

int main(int argc, char *argv[]) {
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}

100/100 answered Dec 14, 2017

Namuun_1029 · Answer 5 · 2017-12-13T08:36:09+0000

prog.c:28:2: error: stray '#' in program
}#include <stdio.h>
  ^
prog.c:28:11: error: expected '=', ',', ';', 'asm' or '__attribute__' before '<' token
}#include <stdio.h>
           ^
In file included from prog.c:29:0:
/usr/include/stdlib.h:826:20: error: unknown type name 'wchar_t'
extern int mbtowc (wchar_t *__restrict __pwc,
                    ^~~~~~~
/usr/include/stdlib.h:830:31: error: unknown type name 'wchar_t'
extern int wctomb (char *__s, wchar_t __wchar) __THROW;
                               ^~~~~~~
/usr/include/stdlib.h:834:25: error: unknown type name 'wchar_t'
extern size_t mbstowcs (wchar_t *__restrict __pwcs,
                         ^~~~~~~
/usr/include/stdlib.h:838:10: error: unknown type name 'wchar_t'
    const wchar_t *__restrict __pwcs, size_t __n)
          ^~~~~~~
prog.c:33:5: error: redefinition of 'main'
int main(int argc, char *argv[]) {
     ^~~~
prog.c:5:5: note: previous definition of 'main' was here
int main(int argc, char *argv[]) {
     ^~~~

Bilegjargal · Answer 6 · 2017-12-13T08:15:27+0000

Hidden content!
#include *   * ****   ** 
#include  ** * *  *  * *   

int main(int argc, char *argv[]) {
****  * *  *  *   ** ** * ** *  a;
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**     **** **  *   *  *    **   * *  **   *** ***  
* * * *  * * *   *   *  *   **
* ***   * * *** * ** *** *** ** 0;
}

100/100 answered Dec 13, 2017 by Bilegjargal (220 points)
edited Dec 14, 2017 by Bilegjargal

lee,jiun-hong · Answer 7 · 2017-12-12T15:45:33+0000

Hidden content!
#include<stdio.h>

int main(int argc, char *argv[]){
 ***** **** * *******   **    ** a;
**      ** **  * * ** ** *   *** *** ***** * * ***  
 * *      *  *  *           *     **   *  * * * &a);

**    ** *  * *    *  * ** * *** *   * *  **   *  ******    {
****** ** ** *     ** ** ** **   ** *  ** ** * *  *  *** * ***   is a digit", a);
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  *  **   ** **   * ** *   *** ** ***    * *        *  *****   * * {
*  ** *  * **  *   *    *** **** *  **   *** *   ****** **   *  ***  is a capital character", a);
*  * ******  * ** *  * 
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* *  *** *** *  * **** *    ** * ** **  ****** * ****   **    ***  * *  is a small character", a);
  *     *  *** * ******  *
*    **  ** *   * *   *   * *   {
  ****     * ** *   *     * * *   **    * * *  * * * *  ***** is unknown", a);
  * * **  * * *    *  *  ** *
}

100/100 answered Dec 12, 2017 by lee,jiun-hong (273 points)

410630017 · Answer 8 · 2017-12-10T14:42:41+0000

Hidden content!
   *   * ** * *  *  ***
   * * * * **      *** 

*     ** *    *   *   * *   ** or  *    *      **    * * ** *  * *  *****  or  * **  * */

*    *  ** * *   * * * * {
* ** * *     **    * c;
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***  *     ** *    *** * * 
*  ***    ***     * * *
*   ***   ***   
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* ****   **   ** *    **** ** 
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   *       **    * ***     *** 
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** *  * ** *    ***  0;
}

100/100 answered Dec 10, 2017 by 410630017 (153 points)
reshown Dec 17, 2017 by nat236919

410630017 · Answer 9 · 2017-12-10T14:42:38+0000

Hidden content!
  **         *      * *
****  *  * **  **** 

   *  * * **  *        * *     * or   *  *  **  ** *** * *   * ** * ** or  **  *   */

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 * **   * *    * c;
*    **      *  * *  * *   
*** *  *   ***          
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*** **  *  * *   
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***  ***  **  c =  **   
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** * * *** ** * if( c  ***  * '0' *  **  c * *    '9' ) // we ***  all the **   are in   * ** * in the       
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**  * ** ***** 
* * **  ****   if( c  * **** 'a'   *  * *  ***  c ** *  'z' ) 
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** **  * ***       **  **   
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**  *   **  * * ==  *
****   *  ** * 
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   **    *  *  * * * **   ** 
**  **  ** ***  
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}

100/100 answered Dec 10, 2017 by 410630017 (153 points)

emilie · Answer 10 · 2017-11-01T08:12:05+0000

Hidden content!
** **   *  *  ****
******* **** * * * ***** *

/* run this   *      the  *  * * *  or add your own  ****   * *   ***        *     **  or input loop */

int    *     char    * {
**     **   char a;
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*  *** *  *** 
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* *     ****     else  *** ** *
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*** **** *        else  ** *** * **
****** ** *   *  * ** *   *   *   **  **    is a   *   *** *     * * a);
*** *  * ** *  }
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** *   * ***** * }
// Your  **       *   from here
*  **     * * * *  
 * *   * ** *  **    0;
}

100/100 answered Nov 1, 2017 by emilie (290 points)
reshown Dec 17, 2017 by nat236919

[Exercise 7] ASCII Identification

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