[Exercise 7] ASCII Identification

Question

6.9k views

Please write a program that can identify a value's characteristic based on ASCII table. It must identify:

0-9 is a digit
A-Z is a capital character
a-z is a small character
Besides those conditions, it shows '%c is unknown'.

Kindly use the given template to finish the task. Be advised that your outputs must be exactly the same as the shown outputs below.

Example(Template)

#include <stdio.h>
#include <stdlib.h>

/* run this program using the console pauser or add your own getch, system("pause") or input loop */

int main(int argc, char *argv[]) {
	char a;
	printf("Define:\n");
	scanf("%c",&a);
	
// Your condition starts from here
	
	return 0;
}

Input#1

Define:
6

Output#1

6 is a digit

Input#2

Define:
A

Output#2

A is a capital character

Input#3

Define:
f

Output#3

f is a small character

Input#4

Define:
/

Output#4

/ is unknown

Suggestion

It's time to use your favourite table: ASCII

[Exercise] Coding (C) - asked Oct 27, 2017 in Chapter 3: Branching, Looping and Functions by nat236919 (5.9k points)
ID: 29618 - Available when: Unlimited - Due to: Unlimited | 6.9k views

17 Answers

Page:

YT Chiu · Answer 1 · 2018-01-12 22:25:09

Hidden content!
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}

100/100 answered Jan 12, 2018 by YT Chiu (221 points)

Baigeldiev · Answer 2 · 2017-12-15 01:29:49

Hidden content!
#include  * *  ***  ** **
****   *** **  * * * 

/* run this program using the console pauser or add your own getch,  *******   ****** * or input loop */

int main(int argc, char *argv[]) {
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**      ****** * * **     **  **  *   **    *  *   ** *** *
*     ** **    *** **  ****** *  * ***    * *  
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* * ** *** *  * *     *  *** 
* **   *      * *  *  *  **** *  0;
}

50/100 answered Dec 15, 2017 by Baigeldiev (183 points)

Baigeldiev · Answer 3 · 2017-12-15 01:28:20

Hidden content!
#include <stdio.h>
#include **  **  ***    

/* run this program using the console pauser or add your own getch, *    *** *   *   ***   or input loop */

int main(int argc, char *argv[]) {
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**  * *  *  ******** * ** if( n == 66 )
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*  ****    *** * **   *
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}

answered Dec 15, 2017 by Baigeldiev (183 points)

The Judge · Answer 4 · 2017-12-14 11:46:02

Hidden content!
#include  *  *** *   *
 ***      *****  *

/* run this program using the console pauser or add your own getch, *** *** *  **    *  or input loop */

int main(int argc, char *argv[]) {
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*   ** *     ***    *  * *  ***      ** * *  **  ****** *  
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*  *** * *****  ** *****   * c **   'A' **  *** * c <= 'Z' ) // c is a capital letter 
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** * ** * *     *  * * *  ** 
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}

100/100 answered Dec 14, 2017

Namuun_1029 · Answer 5 · 2017-12-13 15:36:09

prog.c:28:2: error: stray '#' in program
}#include <stdio.h>
  ^
prog.c:28:11: error: expected '=', ',', ';', 'asm' or '__attribute__' before '<' token
}#include <stdio.h>
           ^
In file included from prog.c:29:0:
/usr/include/stdlib.h:826:20: error: unknown type name 'wchar_t'
extern int mbtowc (wchar_t *__restrict __pwc,
                    ^~~~~~~
/usr/include/stdlib.h:830:31: error: unknown type name 'wchar_t'
extern int wctomb (char *__s, wchar_t __wchar) __THROW;
                               ^~~~~~~
/usr/include/stdlib.h:834:25: error: unknown type name 'wchar_t'
extern size_t mbstowcs (wchar_t *__restrict __pwcs,
                         ^~~~~~~
/usr/include/stdlib.h:838:10: error: unknown type name 'wchar_t'
    const wchar_t *__restrict __pwcs, size_t __n)
          ^~~~~~~
prog.c:33:5: error: redefinition of 'main'
int main(int argc, char *argv[]) {
     ^~~~
prog.c:5:5: note: previous definition of 'main' was here
int main(int argc, char *argv[]) {
     ^~~~

Bilegjargal · Answer 6 · 2017-12-13 15:15:27

Hidden content!
#include ** **  ** * *  *** 
#include  *   ** * *  * 

int main(int argc, char *argv[]) {
 * *  *****  ***** ** * ******  ** * a;
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   * ***** **  **      ** ***
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*  ** *** * ****  **   * ****   *  *** ** ***       * * ** ** %c is a digit", a);

*  *****  ** * * *** *  *
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   **** **  ** *****  **  *** *****  **     * ** *   * * *     %c is a small * ****** * **  ** a );

** ** **  **   *  *  *   *** *** **  * *  ** ***** *  *  *
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**  *  * * * *   *  * ** ** a >= 'A' && a <= 'Z' )  
*  * ** **  ** **  ***     *   * *     *   *    * ****
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*  **  ** *   * *     * ** * *  
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*   *  *      ** * * * * *  *   *** *  ** *   ********* ** *
*  * * * * * * * *    * ****
 **  * ** * ** **** *     *  *  0;
}

100/100 answered Dec 13, 2017 by Bilegjargal (220 points)
edited Dec 14, 2017 by Bilegjargal

lee,jiun-hong · Answer 7 · 2017-12-12 22:45:33

Hidden content!
#include<stdio.h>

int main(int argc, char *argv[]){
* * * ** *****   ** *** *  a;
********   *   *  *********** *  *   * ** *  ***
  ****    *     ****   *      **  ****  *  &a);

* *    *   ** **   *** *  ** *   *****************  * ** *  {
   *   *  ********   **     * ***   *    * *  * ****  *   **** is a digit", a);
 *  *** ** ** ********** * *** 
* **   * **   ** **    ** *** *** *  *   ** ***  *    **  *   {
*    *    *    **** *  *    ****** * ****   ***     * **     *          is a capital character", a);
     * **  * ** **** *  ***
*** * *  *  *** *  ***     * *    ** **   ** * **     *    **   * *  {
*  ****   ****  *** *     * * *** ****  ** ** ***      * * ***** ** is a small character", a);
**   ** ** ******** *  *** 
*    ** ***** **** **    *     {
 ***     **   ******  *    *  * * ** **   *  * * *  *  **    * *  is unknown", a);
   ****   * * *  *    ***  ** *  
}

100/100 answered Dec 12, 2017 by lee,jiun-hong (273 points)

410630017 · Answer 8 · 2017-12-10 21:42:41

Hidden content!
*  *   *    *    * 
  *** * *  * *   ** *  **  

** * *  ** ** *** *  **     * *  or  * *     * *** * *  ** **** *    *   * or ***  *   */

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   * *** **  * ***  * c;
*   *   *   *** *   *  *   
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* **     ******      ** **
** ***    * *  *** 
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* ***  *        
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** ** *     ** ***** 
**   * ***  *** if( c  * **   'a'  * * *  ***  c **  *  * 'z' ) 
* *          * ***  *    *   **   * **   *  *** %c is a **      * *** *  c );

** *** **  *** *  * **   **   
*** * * *    *   **   * **    
***  **   c   *  *    ** *   ***    c  **  * 'Z' ) // c is a  * *  ** * 
*   * *  **  ****  *** *  *  * *  
**    **  *  **  ** * ** **  ********* *** ** %c is a  * ** * *  c );
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* ***  * ***** *  ** *    *** ** * 
**  *    * *  * 
*** *** *** *** *  ** 0;
}

100/100 answered Dec 10, 2017 by 410630017 (153 points)
reshown Dec 17, 2017 by nat236919

410630017 · Answer 9 · 2017-12-10 21:42:38

Hidden content!
 * **      *****  * * 
 **** *   * *** *   *   

 *  *  ** * * * * ***   **** *  * or      *  ** * *   *    *  *    or **    * */

   *  * **  *  *  *     * * {
  *   *  ******    * c;
 ** ***  *  ***   *      
     * *    **  **    *  *
  * *   * **  * *  * **  * **
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* **  * *   * * c = ****  
**** *  ** ***  
**  **** **  **  *** **** ***   *  * ** is %c    **** c);
**  *  * *   * 
****         *   if( c    *  * '0'    *  *  *** * c * ** * '9' ) // we **  all the  *  are in ***     in the ** *  * *
* *   *      *** *   *  * *  ** ****  * **  **  * ***    %c is a  * *    * * c);

*** *** * *  **  
      *  * * *  if( c ****   'a' *    * *  c   * *  'z' ) 
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* **  *     * ** * **   *  * 
 ***  ****  *            *   *  * 
*** **  *  *  * c  ***  *** **   ** ***** c * **   'Z' ) // c is a     *  
 **** **  ****   *** * * **** 
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*  * **  *    * *    *     *  * 
***   *****     * ==  **
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 * **   * ***  * **   *** 
*  **   ****  
*  *    *  * ** * * *  0;
}

100/100 answered Dec 10, 2017 by 410630017 (153 points)

emilie · Answer 10 · 2017-11-01 15:12:05

Hidden content!
  ***     *   ** * 
 **   ***  ** *   * 

/* run this ***    * *  the  * ** *  or add your own * * *   *** ******  *  or input loop */

int *  *  * ** char   *** {
   * * * *  ** * char a;
  *  *    * *     *** * ******   * *   *
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  ** *   *   **   * ** **
**   ** * * *  *** *   ****    *** *** *  is a  *    **  a);
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* *   ** *   *** else  *  ***  *
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   **  **  ****  }
** ** * * ** *   else * *** **  * * 
  **   *** *  ** *  **   * **    **   is a    *   ** ***   * a);
    * *   * }
**  * *  ** *** * else{
*   *  * *         *  *  **  *  *  **** *  *  is * *** ***    
 *   *   *  ** * }
// Your * ** * *    from here
 *  *   **  *   
**** * *  *     *    0;
}

100/100 answered Nov 1, 2017 by emilie (290 points)
reshown Dec 17, 2017 by nat236919

[Exercise 7] ASCII Identification

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