0 like 1 dislike
20k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 20k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
** **** * *** **
int main()
{
* * * * * *** * * ** * * ***
** *** * * * ** **** %f *** *** ** ***** * ** * *
* * * *** *** * * * = (b*b-4*a*c);
* **** ** * * * ** = (-b + sqrt(D))/(2*a);
***** **** ** ** = (-b - sqrt(D))/(2*a);
* * *** ** ** * *** * *** = -b/(2*a);
* * * * *** * * ** * * **** =sqrt(-D)/(2*a);
* ** ********** * *** * *
** * * * ** *** *
* *** * * **** * ** * * * * * * * * ** ** * * * ****** * of %.2fx^2 + %.2fx + %.2f = 0 are real and * ** * ***** *
* ***** * ** ** ** *** * * * ** * *** * ** ** * = %.2f\nx2 = %.2f",x1,x2);
* * * ** * ** ** * *

** * * * * ** ***** * * **** if(D==0)
** **** **** ** ***
* **** ** * * * ** * * **** * * * * ** * ** ******* ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * **** *** ***** **** *** * * ** * * *** ******* ***** = x2 = %.2f",x1);
*** * * *** * ** * * *
* * * ** *** * * *** *** ** ** *
******** *** * * ****
* ** * ** *** * * * * ** ***** **** *** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** *** * * ** * *
* ** *** ** **** ****** ** ****** ** * * ** * * **** * = **** *** ** ** * *** * *
** ** ** * * ** * ** ** *** * *** *** * *** ** * ** = * *** ** ** * * * *
** * * * * * ***** *
** *** ** *** ** * * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * **

int main()
{
* ** *** *** * * ** n, i;

**** * * * ***** * ******** ***** * ** * &n);

** ** ** * * **** * ** * **** = 1; i <= n; ++i)
* ***** ** * ** * * **
* *** ** * * ***** *** * ** * * * * * ** ** * % i == 0)
** *** ** ** * ** * * ** *** ** * ** * * ****** ** * ** ** * * ******** ** ** ** ", i);
* * * *** * ** **

** ** * * ** * *** * ** * 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* ** * *
* **** *** **

int main()
{
***** * **** ** ** ** * ****** **** * *
* ** * ******* ** * * * * * *** ** ** *** * * **** *** *
* ** ** * * * * ** ** * = *
*** ** * * * * *** *
**** * ** ** **** ** ** * *
* *** * ** * **** * * ** * **** **
** * * ** **** * * * = -b /(2*a);
* **** ** *** * ** ****** ** ***
* ** ** ** **** * = (-b)/(2*a);
* * *** * ** * * ** * **** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * ** * *** * * **
* ** ** ** * *** **** ** *
*** ** ** * * ** ** ** if(D==0)
***** * ** * ***
* * ** * ** ******** * = (-b + ** **
*** ** **** * * *** ** * * = (-b - ** *******
** * *** *** **** * ** * ******** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * * ** ** *
* *** ** * * ** * * * *** *
* * * ** *** * ** ** * if(D>0)
* ***** *** ****** ** *
**** ** * **** * * ** * = -b/(2*a);
*** ** *** ** ** *** = (-b + *** **
* ** ** * * ****** ** * * = (-b - ** *
*** *** ***** * * ** ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = *** * * * * ** *
** * *** * * *** ** * ***** ***
** * * * *** * ** * ***** 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** *****
#include * *** * ** *
int main()
{
* ***** * * * * ** * **** ** * a,b,c;
* *** ** **** *** * ** * * * * * ** ** *** *** *** * * * ****
** * * ** * * * *
* * * * ** * *** * *** * * ******
*** * ** ** *** *
* ** ** ***** * * * *** * ****** * ** * ** * *** **** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * ***** *** ** + *** * ******** - * ** ** **
*** * **** ** ** *** *
* **** **** * * ** * *
*** *** ** * * * * * * if (b*b-4*a*c==0)
**** ** *** * *** *** *
* *** ** * * ** * * *** * ** * **** * * * ** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * *** ******* + * * **** ***
* ** * * *** * ******* *
* * *** **** * * *
* ** * ** *
** *** * * * * **
* * * ** * * ** * ** ****** ******* **** ** ** ** ** * * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = **** * * *** ** *** **** ****** * * * * ** * *** *
* * * * ** ******* *
* * **** ** ** * * *** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * * * *
#include ** * * ****
int main()
{
***** ****** *** * * * * a,b,c;
* * ** * * * ** * * ***** * * **** * * * ** * ** ***** * ****
*** ** ** * * ** ** *
* ** ***** ** ** * * ****** **** * ** *
***** **** **** ***** ***
**** * *** ** ** * * * **** ** *** *** * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** ** * * * * + * * * * - *** *** * ***
** ** *** * *** *
** * * * * * *******
*** ** ** ** * * *** if (b*b-4*a*c==0)
* ** * ** *** ** * * *
** **** * **** * * ** ** * * ** ** * * * * *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** ** ** * ** + * ** * * *
* ** * *** * ** ** * *** *
* *** * ** ** ** * **
** ** ** * * ****** *
* * * * ** * ** ** *
* **** * * * * * * ***** ** * ** *** *** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= ** *** * * * ** ***** * *** ** * * *** ** *** * * ** *
* ****** ***** ** **
****** * * * ** *** * * * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
* ***** * *** * * * a,b,c,d,x1,x2;
* ** ** * * * **** * * * ** * * ** ** ** ******* * **** ** ******
* *** * * ** ******* * * * **
** *** * *** ** ** * * * * * * *
*** * * * * * * ** ** **
*** * * * * * ****** ****
*** * ** ** ***
** ** *** * *** * ** ** * **** * * * **** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** ** * * **
**** * * * ** * * ***** * ** **** *** * *** ** ** * = %.2f\n",x1);
* ** **** *** *** ** ** * ******* **** *** *** ** ** = %.2f",x2);
* ** * * * * * *** ** **
*** *** * ** * ** *** * if(d==0)
* * ** * * ** ****** * *
* * ** * * * * * * ** * ** ** ** * * ** ** * * *** ***** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * * * *** ***** * * * *** **** ** * *** ***** * * * = x2 = %.2f",x1);
* *** *
*** **** * * ** ***** * **
* * * * * ** *** * ***
** * ** ****** * * *** ** ** * * *** *** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * *** ** *
**** **** ** * * ** ** ******* * ** * **** *** ** = * * * ****** ** * ** * *
** * **** ** * * ** *** * *** *** ** ** * ** * = **** **** ** * * ** ** *
* * *** ** * * ** **
* * * * ** * * * ** * *** 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
* * * *** * ** ** ** * * * *** *** * *** ** * *** aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
***** *** * *** *** * * * ** *** **** ***** ** ** - (4*a*c);
* * ** * *** * ***** ** ***** * ******
* ** *** **** **** ** * **** * ** **** * *** ** * * ***** ** * * ** * * ****
***** *** * ** ** * * * * **** ** *** ** * * * **** * *** * **** (-b+spD)/(2*a);
** * * ** * * ** * * * **** * * * * * ***** * * *** ** * *** * * * * (-b-spD)/(2*a);
* * *** * ** ** *** ** *** * *** ** * ** * *** * * ** ** **** (x1==x2){
* ** * ** * * ***** **** * * ** ** * ** ** * *** * * ** *** * * * **** * ** ** ** * ** * ** *** * * **** ** * * * * X=%d\n", x1);
** *** * * * ** *** * * * ** * * ** * * ***** * * *****
* * * **** ** * ** * * ** ****** * ** *** * * **** * *** * ** {
**** * * * *** ** *** * *** ** *** ** *** * **** * * ** ** * * ** *** *** * ** * * ** * ** ** * * *** * ** * * *** ** * X=%d或%d\n", x1, x2);
** ****** *** ** ** ** * * **** * ** * * * * ** * ***** * * *
        }
**** **** * * ** *** * ** * * * * **** if(D==0){
** * ******** * * ** * ***** * * ** ** * *** ** * ** * * *** ****** (-b)/(2*a);
* * * ** * ** *** ** * * ** * **** * * *** * ** * ** ** **
* **** ***** ** ** * ** * * * * * *** **** * * * * * *** * *** ******* * * ** * * ** * * X=0");
******* * * ** ** ** *** * * ** * ***** * * ** * ** * ** *** **
*** *** * *** * ** *** * *** * * **** * ** *** *** * ***** **
* ** ** ** ** ** **** * ** * * *** * * * ** *** ******** * **** * * *** * ** * * ** * * * ** X=%d\n", x1);
* * * * * *** * ** * *** * * **** ** * *** * * * *** **
        }
* * * ** *** * *** ** *** ** ** * * *** *
* ** * * * *** * * ** ***** * *** ** * * ** * *** * ** ** *** * * * *** * * * *** ** ** * * *
*** ** ** * ****** ** * *** * * * *
    }
***** * ** ** ** ** * ********* * * * * *
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
* ** * * * **** * * ** a,b,c,D;
** * **** ** ** *** ** * x1,x2;
* * **** * * * **** ** * * ** * %d * * * * ** ** * * *

** * ** **** ****
* ******** ** * ** *** * * *** *****
*** *** * ** ******** * **** ** *

** * ** *** * *** * ** * * * A,B,C;
* * ** * ** * *** ****

* * * * * * ** ****
* * * ****** * *** ** * * * * * ****** *** ** **** * * * of %.2fx^2 + %.2fx + %.2f = 0  are real and * * * * *** **
***** * * * ** **** * * * * * * * * *** * * * = %.2f\n",x1);
** * * ***** *** * * * * * ** * * * ******** ** ** ** **** = %.2f",x2);}

* *** ** * * * * * *** * if(D==0)
*** * ***** * ** * * ** *** * * * * * ** ** ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
* *** ** * **** * ** * * * * *** *** * ***** ** * * = x2 = %.2f",x1);}

** * * * * *** * if(D<0)
* ** * * * * ** * * ** ** * * * * * * ** ** of %.2fx^2 + %.2fx + %.2f = 0  are complex and *** ** **
** * * * ****** ** ** *** * ** *** * * *** * ** * **** bb,d,dd;
**** ** * ** * *** * * ** * * * * * **** * ** *
*** ** ****** ** *** * * * ***** * *** * * ******* * ****
* ** * * *** * * ** *** **** *** * ** * ***** = * ** ** *** ** **
* * * *** * * * * * * ** * ** * * ** *** * * * * * * = * ***** *** * *

******* ******** * * * 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* ** ** * ** *
int main()
{
*** ** * * * * *** * * ** * ** *** **
** ** ** * * * * ** * %f * ** **** * ** ** ***
* ** **** * * ** * = (b*b-4*a*c);
** * * *** *** * ** **** ** * = (-b + sqrt(D))/(2*a);
* ** * * **** ** = (-b - sqrt(D))/(2*a);
** * ***** * * **** ** ** ** = -b/(2*a);
* ***** ** ******** * * =sqrt(-D)/(2*a);
** * * * ** * ** * * * *
** *** ****** * * *
* ** * * ** *** ***** ***** *** **** * **** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and *** ***** **
* *** * ** ** * **** *** ** * ** * * ** * = %.2f\nx2 = %.2f",x1,x2);
* * * ** ***** * **

*** ** * * *** * **** * if(D==0)
**** ** * *** ** ***
** ** ** * ** ** ** *** ** * *** **** ** ** * *** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* **** * * ***** * * **** * * * * **** * ** * * * *** = x2 = %.2f",x1);
* ** * ** ** * * *
* ** * **** ** * *** **
** *** * * **** ** ***
** ***** ** * * * *** * * * * ***** ***** ** *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * ****
* ** * * ***** **** **** * ** **** ** * ** ** * * * ** * * = ***** **** * * *** * ** * *
**** ** * * ******* ** ** **** ** ** ** * ** * * = * *** ******* * **** ** ** *
** *** * **** ***
*** * ** *** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
*** * * ** * **
int main()
{
*** * * * * * * * ***** ** * ** ** * **
* * * * * **** * * **** * %f * **** ** * * ** **
* ***** ** *** * * * = (b*b-4*a*c);
** ** *** ** *** ********** * = (-b + sqrt(D))/(2*a);
* * **** **** *** ** ***** *** = (-b - sqrt(D))/(2*a);
** * * *** * * ****** * * = -b/(2*a);
* *** *** *** *** ** * ** * * =sqrt(-D)/(2*a);
* * * **** **** * ** *** ******* ***
** ** * * * * *
* * ** ** * *** * * * * * *** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * * * ** *
** * ** * *** ***** *** ** * * *** **** * *** * = %.2f\nx2 = %.2f",x1,x2);
** *** * * ** ****

** * ******* * ***** if(D==0)
*** ******* ** * ** *
* *** * * * * * ** **** ** **** * * * * * * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** *** * * **** * ** * * * * *** *** * = x2 = %.2f",x1);
* **** ** ** *** ** ** ***
**** *** * *** **
* * ** * *** ** * ** *
* ** ** **** *** **** ** * ** * ** * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * * **** ***
**** ** * *** ** ** * * * *** *** * ** * = * * * * **** * * ** ***
** **** * * **** ** * ** *** *** *** *** ** ***** * * = * * ******** * * ***
** * * * * * *** **
** * ** * ***** ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users