0 like 1 dislike

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 947 views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
* * ** ** **
int main()
{
*** ******** * **** * * * *** ***** **** ** ***
** * * * * * **** * ** **** **** %f * ******** *** **
* * * ** * ** = (b*b-4*a*c);
*** ** * * * ** * = (-b + sqrt(D))/(2*a);
** * * * * * * = (-b - sqrt(D))/(2*a);
* ** * * ** * * * * = -b/(2*a);
* *** ******* * * *** =sqrt(-D)/(2*a);
* ** **** * ** ** ******** *
** *** ** **** * ** *
* ** **** * **** ** * * * *** * * * *** ***** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and *** *** ** * **** *
*** * * ***** * * * ** ** * * * *** * *** ** ** * **** = %.2f\nx2 = %.2f",x1,x2);
* ** * * * * ***** *

****** ******** ** * **** ** * if(D==0)
** * ** *** * * * * *
* * * ****** * **** *** ** * * ** *** ** ****** ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * * **** ** ** * * * * * * ** ** * ******** * *** ** = x2 = %.2f",x1);
** ** * * * * * * **
** ********* ** *** * *
* * *** * * * *
* * **** * * ** * * * * *** * ** * * *** ** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ** * * ** **
* * * * ** * ** **** ** ** * * * * * * * * ****** ** * = * * * ** * ***** *
***** ** * * * ** * * * ** * * **** * * ** ** ** = * *** * **** * *** **** *
* ** **** * ** **
* ** ***** * * *** ** ** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** ** * * ***

int main()
{
* * *** * ** * * * n, i;

* ** * * * ** ** ** ** *** * ** * * * &n);

* ** **** *** ** ** *** = 1; i <= n; ++i)
*** * ** ** ** *** **
* * * * ** * ** * * * *** * * ** * * % i == 0)
* ** * ** * * * ** * ** *** * * * *** * * * * *** ** **** * * *** * *** ", i);
* ** **** ** * *

** * * *** ****** ** * ** 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
*** * ** * **
* * * *** ** ****** *

int main()
{
* ** * * * ** * *** * * *
*** * * * * ** * *** *** ** * * * * ** * * ****** *** ** *
* * * * * * *** * ** = * *** *****
**** * * ******** * ** * ****
****** * * * * **** * *
* ** ** ** * **** ** * * ** ** * *
* * * * * ** * * ** * * = -b /(2*a);
* ***** ** * ** ** * * * ***** ** *
** ** * ****** * * * * * = (-b)/(2*a);
* * ***** * ** * * * * **** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = *** ********** * * **
*** * **** ** ** *** *
***** ******** ** *** ** ** * if(D==0)
* *** * **** ** *** **
* * * * * ** * * = (-b + * ** *** **
** *** * *** * ** * = (-b - ** * * **
* ** ** ** ** ** *** ** * * *** **** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ** ** ** **
**** ** * * ** ** **
*** * *** **** ******* if(D>0)
* * *** * ** * * *
* * * * * ** * * * ***** = -b/(2*a);
* *** * * *** * * ** **** = (-b + * ** * **
** * * **** ** * *** ** = (-b - * ** *
**** * ** * * ** ** ** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * ** * * ***
*** * * ** * ** * * *
* *** *** * * ** * **** ** 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include *** * * *
#include ** ** *** *
int main()
{
** ** *** ** * * * * a,b,c;
* ** * * * * * * * * ** *** * * ** ** * **
* * * ** ** ** *
**** * *** ** ** * **** * *
* * * *** * *** * *** * *
********** * ** *** * * * ** ** ** ****** **** ****** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * * ** * *** * * + ** * **** * ** - * *** ** *** *
** ****** *** * * ***
********* * * * * ***** *
**** * * * ****** *** if (b*b-4*a*c==0)
* * * * * * * ** * **
** * * **** ** ****** ** * * ****** ** **** ** *** * **** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = *** ** + * ** * * ** *
* * ** *** * ** * ****
** * ** ** ** **** * *
* ******* * * *** *
* * **** * ***** * * *
* * ** * * *** * ** * * * * *** **** ***** * * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * ** * * **** ***** * * ** ** ****** * * * ** ******
* * ** *** *** * * **
** ** * **** * * * ******** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * *******
#include * * **** ***
int main()
{
* *** ******* ****** ** a,b,c;
** * ** * * **** * *** *** ** **** *** * * *** * * * *
** * ** * * * **
* ****** ** * **** ** * * *
* ** * * ** ** * * **
*** *** ** * ** ****** ** ** *** ** *** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** * * + **** ** ****** * - * * ****
*** ***** * * *** * *
** *** **
* *** * * *** if (b*b-4*a*c==0)
** * * * * ***** ** *****
******** * ** *** ** * ** * * * * **** ** * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** * ** **** + * * ** * *
* ** ** ** ** * *** *
* * * * * * * *****
**** * *** * ******* * * *
* * * * * * * **
*** ** ** * * ****** ** ** * * ******* * **** *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= * *** ****** * ***** * * * * ** *** ***** * * * ** **
** * *** * * **** ****
***** ** ** **** * ** * * ** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
* ** *** * *** * **** * a,b,c,d,x1,x2;
* ** * ** ** ** ** ** ** * * ** * ** ***** ** * * *
* * ** ** * ** * * ** * * **
* ** *** ** * * * * * ***** ** *
** * ** * * * ** * * ** ** * *** *
* ** *** ******* * * * ** * *
**** * ** ** * * *
* **** ** * * ** * * * ** * * ** * * *** * * ** ** * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and * ** * * * **
* ** *** *** *** *** * *** ** * ***** * * ***** **** *** = %.2f\n",x1);
*** ** * ** ** * * * * ** * * * **** ** * ** * = %.2f",x2);
* * ** * * ** ** ***
* * * * * * * ***** * *** if(d==0)
* * * * * *
* * * ** * * ** * * ****** *** * *** ** * * * * * ** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** * *** * * ** ** * ** **** * * *** * * * * *** * = x2 = %.2f",x1);
***** * ** * * **** *
** * * ** ** * ** * *** *
****** * *** ** * * *** * *
* ** *** * * ** *** ** *** * *** ** * * * **** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ** ** * **
**** *** ** * * **** ** * ** * ** * ** * * ** * = * ** ****** * ** *** **
* * * * * * *** * * *** * * * * * ***** ** = * ** * * * **** ** * **
** ** ** ****** ****** * *
* ** * * * * * 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
*** * * **** * * * * * ** * * ** * *** * ************ ** aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
*** ******* ** *** ***** * * * *** ** * ** *** - (4*a*c);
** *** * *** ***** *** * **** * * * ** *** * * *
** * * * *** ** ** * * * ** * ** *** * * ** * * * * * * * * *
* * ** *** ** * ** * * ** ****** ** * ** **** (-b+spD)/(2*a);
*** ** * ****** ***** * * ** * ** *** ** * * * **** * * * **** ** * ***** (-b-spD)/(2*a);
*** ** *** * * ** ***** **** * *** * * * * * * * * * ** ** * (x1==x2){
** * * ** ** * * ** * *** * *** * *** ** * ** ***** * **** ***** ** * ** * ** ** * ** ** * *** *** * * **** * * * * * ** X=%d\n", x1);
** *** * * ** * * *** * ** * * ** ** ****** * ** *** * *
*** * * ** * *** * ** * * * * ** ** **** ****** ***** ******** {
* ** * *** ** ** ***** ****** * ** * * * *** ***** *** ** **** *** ** ******** **** * * ** ** ** *** * ** * **** ** X=%d或%d\n", x1, x2);
* * *** * *** * **** * * ** * ******** * ** * * * * *
        }
******* * * * *** ** ** * *** * * if(D==0){
* * * * ** * * ***** * ** * * ** *** ** * ****** ** * (-b)/(2*a);
*** ** * **** * * * ** **** * * ** ***** ** * * * *
** * * ******** * * * **** ** **** **** * *** ** * * * ***** ** ** * ***** * * * * X=0");
* * * ** * * * *** * * ** ** ** *** * *** * *** * ** *** *** **
* *** * ** ** * ** * **** * ** *** * * ***** **** * ** **
*** * ** * ** **** * *** **** * ** * * ** * * * * * ** ** * ** * ** ** * * * *** * * * *** X=%d\n", x1);
** * * * ****** ** ** ** * **** * * *** ** * * * ** * ***
        }
* ** * ** ** * ** ***** ** * * ****** **
* ** ****** ** ** * **** * * *** *** *** * ** * ** ** *** * ** * *** * * *** * * ** ** ** * **** *
* * * * * ** ** * * ***** ** ** * ** * * ** * * ***
    }
** * * * * ** ** ** ** ** ***** ** ** **** * * ** **
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
* * * ** ** * * a,b,c,D;
* * * * * * * * x1,x2;
* * ** *** * * ** ***** ** * ******** %d * * * ** * ** ** **** **

** * * * * ** * * * * ****
** * * ***** **** * * * * *
* * * **** ** * * * * ** * * *

* *** ** * **** **** *** ** A,B,C;
** * *** ** * * ** **

*** ** ******* ** * *** *
* * * ** * ** * ***** * ** ** ** * * * **** ******* of %.2fx^2 + %.2fx + %.2f = 0  are real and * * *** * *** *
** * * * * * ** *** ***** ***** **** **** * * ** * ** * ** ** = %.2f\n",x1);
***** * * * *** *** *** * * ** *** *** * ** ** ** * ** * ** = %.2f",x2);}

** **** ** * * * ** if(D==0)
******* **** **** **** ** * * ** * * ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
* * ** *** * **** * * **** * ** *** * ** *** **** * * * *** * = x2 = %.2f",x1);}

* ** * * * ** * if(D<0)
** *** ** *** * ** **** ** *** **** ** *** ** * * * ** * ** *** of %.2fx^2 + %.2fx + %.2f = 0  are complex and *** * * ** *
* * * ** ** ***** ** *** * * * ** **** *** bb,d,dd;
** * * * ** *** * * * ** **** ** **** * * * ** * *
*** ** * *** * **** * ** ** * **** * * * **** ** ***
*** * ** * * * * * ** * ****** ** * * ** = ** * ** ** * ****
** ** * * * * * * * ** ** ** * ** **** ** * ** = ** * * * ****

* * **** ** **** * 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* * * ** *
int main()
{
* *** * * ** *** * * *** *** *** * *** * *
* ** * * * ** ***** ** * %f * *** * *** * * *** *** ** * *
** ****** * **** * *** = (b*b-4*a*c);
** ** * ** * ** ** = (-b + sqrt(D))/(2*a);
*** ********** ** ** * = (-b - sqrt(D))/(2*a);
** * ** * *** ** * ** ** = -b/(2*a);
**** * * ** **** * ** ** * * * =sqrt(-D)/(2*a);
* *** *** * * *** ****** ***** **
* ** *** * **** *** *
** ***** **** ** *** * *** ** * ** * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * ** *
**** * * ** *** ** * * * * * *** ** * * * *** * * * * * * * = %.2f\nx2 = %.2f",x1,x2);
** * * * * * **** * ** *

*** *** * * **** if(D==0)
** ****** * * ** ****
***** * * ** ** ** * ** * **** * * * * *** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** ** ** * ** * * ** * ** * * * ** * ***** *** * ** = x2 = %.2f",x1);
*** ** * * *** * *
** ** * ** * ** ** ** **
* ** * ** * ** ** * *
* ** * * ** * * ** *** ** *** * ** * * *** *** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * * ****
** * * ** * * * * * ***** * * * * * ** * **** ** ****** * = * * * ** *** * *** ******
** * ** *** ** * *** * * * * *** ** * ** ** * ** ** = * ** * ** * * ** *
* * * * ** * * *
** **** **** * *** * * ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
********* *** * ** *
int main()
{
* *** ** ***** ****** ** * *** * * ***** *** * * *
*** * * ** *** * ** ** * ** * %f ** ** ** **** ** ** *** *
* * * * **** * *** * * * = (b*b-4*a*c);
* ** * * * ** ** * = (-b + sqrt(D))/(2*a);
* *** *** * * ** * = (-b - sqrt(D))/(2*a);
** * ***** * * * * **** **** = -b/(2*a);
** ****** * * ** ** =sqrt(-D)/(2*a);
*** *** * * * *** * *** ** *****
* ** ** * * * ** * ******
* ** * * *** ** * ***** * * * ** ** * **** ***** **** *** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * * * * ****
*** *** * * ** *** ** ** *** **** * * * * **** = %.2f\nx2 = %.2f",x1,x2);
** ** * * * ** *

* * * ******** **** * if(D==0)
*** * * * ** ** * **
*** * * * ** **** *** ****** * ** * * ****** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * * * ** ** **** * *** *** * * *** * *** * *** = x2 = %.2f",x1);
** ** *** ***** *** *
* * ** * * * ** * ***
** * * ** * * * ***
** * ** * ** * * * * *** ***** ** * * *** *** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ** * ****
** ** * * ** *** * * **************** ** * * * * ** = ***** * * ***** * * **
* ** ** * ** ** * * *** ** **** *** * * * **** *** * = ** * ** ** ****** ****
** ******** ** * * ****
* * * * ****** * *** ** *** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Get it on Google Play Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.158.63.81
©2016-2021

No related questions found

11,539 questions
144,434 answers
149,285 comments
4,159 users