0 like 1 dislike
2.3k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 2.3k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
**** ** * * * * * *
int main()
{
**** **** ** * ** ****** ** *****
*** * ******* ** ** * ** **** %f *** ** ** * * *** * **
**** * ** * ** * * * = (b*b-4*a*c);
*** * ** ** ** * = (-b + sqrt(D))/(2*a);
* * * *** *** * **** = (-b - sqrt(D))/(2*a);
* **** * ****** ** * = -b/(2*a);
** * * *** ***** ***** ** * ** =sqrt(-D)/(2*a);
* * * * * * * **** ****
*** ** * *** * *
*** * * ** * * ** *** * * * * ** *** * * ** *** *** **** * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * ***
** * * * ******* * * *** * ** ** * *** * * ** * *** ** = %.2f\nx2 = %.2f",x1,x2);
** * ** * * * * ** *

***** *** ** ** ** ** * if(D==0)
*** ** ** ** * ****** *
** * *** *** * * ** * *** ** ********* of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* *** * **** ***** * ***** * * *** * ** ** * ** * = x2 = %.2f",x1);
*** * * **** * *
* * **** *** ** * **
*** * *** * *
* ***** * ** ** * **** * ** * * ** ** * * ** **** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ** * * ***
* * * *** *** * *** ***** * * *** * * ** * = * ** * ** * *** *
* * * *** * ** * *** * * ** * **** ** * * * * = ** ** * ** * ** ** ** ** * **
** * * ** * ** ** *
** * * ** *** * ** ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include *** * * ***

int main()
{
* ** * * ** * *** * n, i;

***** * ** * ** *** *** ** * ** * &n);

**** **** * ** * * * * = 1; i <= n; ++i)
* **** * ***** ** *
** * ** * * * **** ** ** * * ** * * * * * * % i == 0)
* * ***** * **** * *** *** *** * ***** * ** **** * *** * ** * ** ** *** * * * ", i);
* * * **** ** *** ****

* * * * * * * * 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
*** *** * * *
*** * * * ***

int main()
{
* * ** ** ** ** * * * * * **
** * ** * * * * **** *** * * ***** * ******* * ** *** **** * *
* ** ** ** * ** ***** = * * * * *
* ** *** *** ** ** **** *
* * ***** **** * **
** * * ***** * *** * ** * ** *
* ** ** ***** ** * *** = -b /(2*a);
* *** * **** * * ** ** ** * * * *
*** *** ****** * *** = (-b)/(2*a);
* ** ** * ** * * * ** * ** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = *** * * *** *** ****
* * * * * *
* *** * *** * ** *** if(D==0)
******* * ** * ** *
** *** * * *** ** * = (-b + * * *******
***** * * ** ** **** *** = (-b - ** * * * *
*** ** * *** * ** *** *** **** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** * * **
* * * * * * ** **** ***** ** *
* * ** * ***** * * * * if(D>0)
* * ** ******* **
***** *** ** * * * **** = -b/(2*a);
*** * *** *** ** * = (-b + * *
* * ** * ** * * = (-b - * *
* ** * * ******* ***** * ** *** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * * * *
* * ***** ** * * *** * **
* ** *** * **** 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include *** * * * * **
#include * *
int main()
{
*** * * ****** * * *** * * * * a,b,c;
*** **** * * * * * ****** * * * *** * * **** *** ** *** ** ** *
** *** ***** ******
** ** ** ** * * * ** *
* * ** *** * ** *
* * * * * * * * * * * * * * ***** ** ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * ** ** **** + * **** **** - ** * *** *
* **** ** * *
* *** ** **** * **
** ** * *** *** * * * ** if (b*b-4*a*c==0)
* * ******* ** *
** * ** * * * *** * * * ***** * * ***** * ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * *** * * + ** * *** *
* ** * * ** * *
** ** **** * ** ** ** **
* **** * * * *** * *
**** ** * * * *
** *** ** * **** *** * * * * ** ****** * *** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * * ** * * *** * * * ** * * * * *** ** ****** *** **
** ** ** * ** * * ** * **
** * * **** ** ** * * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include *** ** ** ***
#include * * ***** **
int main()
{
** * ****** ** * * * a,b,c;
* * ** ** ******** *** ** ** *** * ** ******** *** *** * *** **
* * * * **** * * *
* *** * *** ******* *** * *
* * ** ** * ** * * * *
* *** ** * * *** ***** * ****** * * * * ** * ** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** * **** * + * * ** * * * - * ** ** **
***** ** * * * * * **
***** *** ***** *
*** ** * * ** * if (b*b-4*a*c==0)
* * * * ** *** * **
** * ** *** ** * * * * * * ** ***** * * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * * ** * * + ** ****** *** *
*** * ** * ** * * *
*** * ********* * ** ******
* * * ** ** * * ** ** *
**** *** * *** *** ** *
* * * ** * * ********* * ** ** * ** ** ****** * * *** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= ** * ** ***** ** *** * * * ** *** * ** * *
* ** * ** * * ** *
* * * *** ** ** * * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
* *** * ** * ** * a,b,c,d,x1,x2;
**** ***** **** * * ** * * * * *** ** ** ****** *
** *** * *** *** ** *** *** *
* **** * * * * ***** * * * * ***
** ** **** ** * * ** * ** ***** * **
** * **** ** ** *** ** * * ***
*** * * ****** * **
** * * ** ** ** ******** * * * * * **** * * ** *** ***** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and * ******* **** *
* *** ** * ******* * *** *** * * ** *** *** **** * ** = %.2f\n",x1);
** * * * **** * * ** ** ** *** ** ** * ** * = %.2f",x2);
*** * * *** * * * **
*** ** ** ** **** ** ** if(d==0)
**** ** ** * * ** ** *
* ** ***** ** ** * ******* * * *** ** ** ** * * *** *** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * **** ******* * * * * ** * ** *** * * * * = x2 = %.2f",x1);
** * * * ** * ** *
**** * * * *** *** ** * **
* * * ** * ***** ** * *
** * ** * * * *** ** *** * * **** * ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** * *** * * *
* ** *** * ** * * * * * * ** **** ** ** * ** * *** ** = **** ** * ** ** ** ** * * *
*** ** * * * * ***** * * ***** * *** * ** * ** * * *** * = ** * **** * ** * * ** *
* * * ** * * * ***
* * ** * * **** ** 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
** ** * *** *** ****** **** * *** * * * *** * ** aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
* * * * * *** * * **** * * ** * * * ** *** * *** - (4*a*c);
** * **** * ** * ** ** * * ** ** *****
* * ** **** * ** * ***** *** ****** ** ** ** ** ** * * * * * *****
* ** * ** * * * ** * ** * * *** ** ** ** * * * ** ** ** (-b+spD)/(2*a);
** * * ** * ** * * * * ** **** * * *** * * ** *** ** (-b-spD)/(2*a);
* ** ** * *** ** * * *** *** ** * * * * **** ***** ** * * ** (x1==x2){
* * * *** * *** ** * ***** * * * ****** ** * * ** ** * * ** *** ** *** * ***** ** * ** * * * * ***** * * ** ** X=%d\n", x1);
* * **** * **** * *** *** * ** * * *** *** * ** * *** * ****
* ******** ** * * *** * **** * * * * **** **** ** * * ** * * {
* * * * *** ** ** ****** * * * * * * *** * ** ***** **** ** ** ** * * * * * *** * * ** *** * * ******* * ** * * X=%d或%d\n", x1, x2);
* * ** ***** * * * *** * * * * ** ***** * * * **** ** * * * * *
        }
** ** ** * ** * * ** * ****** if(D==0){
** * *** * ** *** *** **** * * * ** * ** **** * ********** ** *** * * (-b)/(2*a);
**** * * * *** * ******* * * *** * * * **** * ** * * * *** ** * * **
***** *** ***** * ** ***** * * * **** ** * *** ** ** **** ****** ** ** * * **** *** * ** * ***** * * ** X=0");
* *** ** * * * *** ** *** ******* ** ** ** * * * *** * *
* **** ** ** ** *** * ** * * **** * *** ** *** **** * ** *
** ***** ** ** ** * * ***** ***** ** * ** * **** * * ** ** * ** * * ** *** ****** ** * ** X=%d\n", x1);
*** * ** **** * ** ** ** * **** ** * ****** **** *** *** *** ****
        }
**** *** * ** ** *** ** * * * * *
** * *** * *** ** * * * * ******* * * * * * ***** * ** *** *** * * * **** ** *** * * *** **** ** * ***
*** * * * * *** * * ** * * ** * *** *
    }
** ** * * **** **** * * * * *** ** ** * ** ***
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
*** ** * * * * ** a,b,c,D;
* ** * * * ** * x1,x2;
* * ** *** *** *** * *** * * ** *** %d ** * *** * ** * *****

* ***** ** * **** **** ***
** * ** * ** * ***** *
* * *** * * ** * * * **** ** ** ** **

** * *** *** ** ** * * * * A,B,C;
** *** *** * * ** ** *** ***

* ***** * ** **** * **
*** *** * **** *** * *** ** * *** * * * ** *** of %.2fx^2 + %.2fx + %.2f = 0  are real and *** *** * ** *
** ** * ** * * * * *** ** * * ** * ** ** **** * ** = %.2f\n",x1);
*** * * **** **** * * * * ** ** * * ** * = %.2f",x2);}

** *** ***** * * * * * * if(D==0)
** * * ******* ***** ** ** ********** *** * * ** ** * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
* * ** ********* ** * ** * * **** * * * ** ** * *** * * = x2 = %.2f",x1);}

* ** * **** * ****** ***** if(D<0)
* *** * * * *** ****** * ** * ** * * ** * * * * * ** of %.2fx^2 + %.2fx + %.2f = 0  are complex and * * * *** *** * ** **
*** *** **** * * * *** * * * * * *** * * ***** ** bb,d,dd;
** ** * * * **** * ** * ** ** ** * * ** *** ** *** *
* * * ** ***** ** ** *** ** * ** * * * *** ** **** ** ** *
* * **** * * *** ********* ** * * *** * ** * = ** * * ***** **
* ** ** *** * ** * ** * * ** * * ** *** **** ** *** * * ** = * * * * * *** * *

* * *** * * * 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
** * **** ** *** ****
int main()
{
* **** *** ** * * * ** ** * * * * * ** *** *
** * ** * * * * * **** * ** * %f * * * ** ** * * *
* ***** **** * ** * ** *** = (b*b-4*a*c);
* **** * * ** ** * ***** = (-b + sqrt(D))/(2*a);
** ** * * ** * * * * * = (-b - sqrt(D))/(2*a);
* * * **** * * *** **** = -b/(2*a);
* **** ** *** ** **** * * * *** * =sqrt(-D)/(2*a);
* * * ** *** ** * ***** *
* **** * ** * * * ***
** *** ** ****** * * ** * * * ** * * * * ** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * ** * * * *
* ** ** ***** * *** ** ** * * **** * ** ** ** ** * = %.2f\nx2 = %.2f",x1,x2);
** *** * * * ** * ***

* ** ** ** *** **** * * if(D==0)
*** ** * ** * *
* *** * * ** * ** ** **** ** ** ** * *** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * *** *** * * ****** * *** * * ** * * * ** * * * ***** = x2 = %.2f",x1);
***** * ** **** * **** * * *
* * ** ** ****** * ***
** * *** ** * * ***
** * * ** ****** ** * * * * * * **** * ******* of %.2fx^2 + %.2fx + %.2f = 0 are complex and **** * ** * *** **
*** * ** ** *** ** * * * ** **** *** * * * * ** ** * * = * ** *** * ** * **** ** **
** ***** * ** * * **** ** * ** * * * *** ** ** * = **** ** * * *
**** * * **** * *
* * * * ****** * ** ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* * ** ** * ***
int main()
{
** * *** * * ** ***** * * ** ** **** *
*** *** ** ******** * ** * * * %f * ******* **** *** * * *
* * * ** * *** * = (b*b-4*a*c);
** * *** * * ** * **** = (-b + sqrt(D))/(2*a);
* * *** * *** * ** * = (-b - sqrt(D))/(2*a);
* ** * *** ** * * ** * * = -b/(2*a);
* * * ** * ** * ** * =sqrt(-D)/(2*a);
* *** **** ** **** * ***
* ***** ** **** * *
* * ** **** **** * ** * ** * ** * * * * ****** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * *** **** *
* **** ** ***** ** * * ** * *** **** * *** ** * ** * * = %.2f\nx2 = %.2f",x1,x2);
* * * * *** * *** * ***

** * ** * *** * * * if(D==0)
* * **** * * * **** * *
****** * * * ** ** * * ** * **** * * * ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ****** * * *** * **** * * *** * * * ****** *** * = x2 = %.2f",x1);
* ** * * * ****
*** ** ** ** **** *
*** ** * ********** **
* ** * * *** * ** * **** * * ** * * ** **** * * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ** * *** * **
* * ** *** * * * *** ** ** *** * ** * = ***** ** ** ** * **** *
* *** * ****** ***** *** ** ** * **** * * * * * ** **** = * * * ** *** ******* *
* * * ** * ** * *
*** *** * **** *** *** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.155
©2016-2024

No related questions found

12,783 questions
183,443 answers
172,219 comments
4,824 users