0 like 1 dislike
2.3k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 2.3k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
** * ** * * ** **
int main()
{
* *** ** * ** * ** **** ** * * * ** ** *
*** **** ** * * * ** * ** %f *** * *** ** * * * ***
* * * ** *** * *** = (b*b-4*a*c);
** * * ** *** * * * = (-b + sqrt(D))/(2*a);
* * * *** * ** ** = (-b - sqrt(D))/(2*a);
** *** * * * * * **** * = -b/(2*a);
* * * ** * * * * * * =sqrt(-D)/(2*a);
* *** ** * * **** * * * * *
***** * * * ** ** * *
* * ** * * ** ******* * ****** * *** * * * ** * ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * *******
** * ** * *** * ****** * ******* *** * *** *** ** * * ** = %.2f\nx2 = %.2f",x1,x2);
* *** ** * ** * * **

** * * * ** * * * * ** if(D==0)
* * * * * ** * *
* ******** * * * * * ****** ** ** **** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** *** **** * *** *** ** **** * *** * ** ** * ** = x2 = %.2f",x1);
*** ** * * ** *
* * * ** * ** * * * **
** * * * * ** **** *
* **** ** * * * * ** ** * * * * **** ** *** * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ******* ***
** * ** ** * *** * ** * **** * ** ******* ** *** * *** ***** = * ******* *** * ** ****
* ** ** * ** ********** * * * * ** *** ******* *** = **** ** ** * * **** **
* * * * ** * * ****
* ******* ** ** ** *** ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * * *

int main()
{
** ** **** * *** * * * * * ** n, i;

****** * * * * ** ******** ** * * * &n);

**** * * ** * ****** ** ** = 1; i <= n; ++i)
** * *** ** ********* ** * * *
*** *** * ******* * ** * ** *** * *** % i == 0)
** ***** * ******** * ** * * ** * * **** * * ** *** ** * **** *** * *** * * ** * * ", i);
* ****** * * ** ** *

****** ** * * ********* * * 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
*** * ****
*** *** * *

int main()
{
* ** * ** ** ***** * * **** * ** *
** **** ** * *** *** ** ** ** *** ** * **** * * ** * * *
** * ** **** * * ** = ** *
** * * * ** ** * **** **
*** * ** * *** ** *
* * ** *** *** * * *** *** * *
* *** * * *** ** * * *** = -b /(2*a);
* ** * ** * * ** ** ** ** * *
** * ** * * * ** ** * = (-b)/(2*a);
**** * **** ** ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * * * * * **** * * *
* * ******** *** * ***
* * ** * * * * * * if(D==0)
** * * **** *** * *
* *** *** ** *** *** * = (-b + *** * *
* * **** *** * = (-b - ** ** ** *
* **** * *** * ***** * * * *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = **** * *****
* * **** * * ** ** * *
***** * ** ** * * * * ** ** if(D>0)
* * * * * *** *
** * * * * * * * ** * = -b/(2*a);
**** * * * ** ** * = (-b + *** **
* * * ** *** * * ***** * * = (-b - ***
*** * * * ** *** * ***** *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * * * * *** **
* * ** ** * ******** ** *
* ** * ** *** *** * ** * 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include *** * **
#include **** * * *
int main()
{
** ** ***** ** * * ** a,b,c;
** * * ** * *** **** ** *** ** * *** ** * ** ******
* ** ** ********
*** ** * * ******* * ** *** **** * * **
* *** * * ** * * * *
* * ** *** *** * *** * ** * *** * ** **** ** *** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * * * * + **** ** ** ** - ***** * * *
** *** ** * **** * ** * *
* * **** ** ** **
*** ** ** * *** * ** * if (b*b-4*a*c==0)
**** * ****** ** * ** **
* ** ** * * **** ** ******* ** * * ** * ** **** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ******* ** ** + * * * * ***
* **** ** ** * *** ** **
* *** * ***** *
** * ** ** ** * * **
* * *** ** * ** *
*** ** **** * ***** * ** ** * * * *** ** * * * *** * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = ** **** *** ** **** * ** ** **** * ********* * **** ** **** *
* * * ** * ** ** * *
*** * *** **** *** *** *** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ********* ****
#include ** ** ***
int main()
{
* *** * *** ** ** * *** * a,b,c;
*** ****** **** ** * ** ** * *** * ** ***** * ** *
* * ** **
* ** * ** * ** ** * *** ** * * *** *
** *** ** *** * ** **
* ** ** * ** * * * *** ******** *** *** * * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ******* ** ** ** + ** * * - * * ** *** ***
* * * * ** **** *
*** * * ** * * * ** *
** * * ** **** ***** * if (b*b-4*a*c==0)
****** ** * * * * * *
* * *** *** * **** * **** *** *** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = *** * * **** + * * * ** *****
***** **** *** *
*** * ** * *** *** ** *
* * * * * * * ** **
** ******* ** ** * * * * *
* ** ** ** * ** * * *** ** * * * * **** ** ** ** **** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= *** * * * ** * * ** * * * **** * * **** **** *
* ***** **
**** * * * ** ** * * ** ******** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
**** ** **** * * * a,b,c,d,x1,x2;
* *** *** * * * * *** ** * ** * ** * *********** ******
** ** * * ***** * ** ** * *
* * * ** * * *** * * *
* * * *** * ** *** *** ** * ** ** *** *
* ** * ** * ** *** ** * ** *
*** ** *** * ** * * *
** * ** * ** * * * * ** * * ******* ***** * ***** * of %.2fx^2 + %.2fx + %.2f = 0 are real and **** * *
* *** * * **** ******** * ***** * * ** = %.2f\n",x1);
* ** * ** * * * * ***** **** ** ***** * ** ** = %.2f",x2);
** ** *** * * * ** *
***** * * * * ** * *** if(d==0)
* * ** * **** ** * **
* **** **** ** **** * * ***** * * ** *** * **** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** ** * *** *** * *** ******* ** * * **** * ** * * = x2 = %.2f",x1);
* * *** *** ** * **
* * * * *** *** * *
* * * * ** * ******* **
* * ** * *** *** ***** *** *** * **** * * * **** * ** ***** of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** * *
*** **** *** * * ** * * * * * * = * ** ****** * * * **
* ** * * * * * * * * * ***** ** * * ***** * ** *** = *** ** * **** **** **** **
* * *** **** * * *
* ** *** * * *** * * * * 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
* ** * ** ** * ** * * *** ******** * * * ***** ** * aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
** *** * * ** ******* * * * ** * ** * - (4*a*c);
* * * * * *** ****** * * *** **** * * * **** * **
** * ** * ** * *** * ** * * **** * ** * ** * **** **** ** *** * *
* ** ** ** * * * * ** * ** * * * ** * * **** * ** * * * (-b+spD)/(2*a);
** * ** ***** * *** * ** **** ** ** * * ***** * ** * ** *** ***** (-b-spD)/(2*a);
*** * ** *** *** **** ** * * * * ***** ** ** * * * * ** (x1==x2){
* * ***** ***** * **** ** * ** *** * **** *** * *** * * * * * *** * ** * ***** * * ****** * * * * * * * * * **** * X=%d\n", x1);
** * ** *** ** *** * *** * ** ** * * * *** * ** **** *** **
** **** * ** * * * ** ** * * ** * **** ** * * * * * * * **** * {
** *** * ** ** ** ** *** * ** * * * * **** ** ** * * ** ** * ** *** ** * ** ** * ** * * ***** *** * *** * * * ** X=%d或%d\n", x1, x2);
* ** * ** ** * * * ** ** *** * ** * *** ** * **** * * * **
        }
*** *** * ** * * * * ** ** * * *** * if(D==0){
* * ** **** *** * ** * ** ******** ***** ** *** * * * *** * ** ****** (-b)/(2*a);
** ** ** *** ** * * * ** ***** * ** *** * * ** ** *** **** * **
* ***** ** * * * * * * ** ** * * * *** ***** * *** ** * * ** ** **** * ** *** * * * * * * *** **** * * X=0");
** * * * ** * * *** ** *** ****** * ** *** * ******** ** ***
* * * * * * * ***** ** * * *** *** * ** * ** ** ** *** * * ** * * ***
* ** * * * * * *** * * * * * * * **** * ** * ** ** ** * * ** * *** ** * *** ** ** *** * X=%d\n", x1);
* * ** * * **** * * * * * * * * * ** * ** **
        }
* **** *** * ** * * ***** * * *
* **** **** ** * * * ***** ** *** ** * ** ** *** ** *** ** *** ** * * * * * **** * *** *
** ** * *** *** * * * *** * * * * *** ** *
    }
* * ** * * * ** ** *** * ********* * * *
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
* ** * ** **** ** ** * * a,b,c,D;
* * ** * * * * ** ** * x1,x2;
* ** ** ** *** *** * ** ** * %d * * ** * * * *** *

**** * *** * ** * ** *
** * * * * ****** ***** * * *
*** * **** * * * ** * * *** * **

* *** **** ***** ** ** ** * ** A,B,C;
** **** * ****** * ***** * *

* * **** ** * * * ** * *
* ****** **** * **** *** * ** ** ****** **** * ** * *** of %.2fx^2 + %.2fx + %.2f = 0  are real and ** ** * * * * *
* *** ** * *** ***** * * *** ** * * * ** * * * ** * = %.2f\n",x1);
** * * *** *** ** *** * * * * * * * ** *** * *** *** = %.2f",x2);}

** * ** * ** * * *** ******* if(D==0)
*** * ** *** * ** ** * * ** *** *** *** *** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
** * ** * * ******* ** ** * * * ** * *** * * = x2 = %.2f",x1);}

**** *** * * *** * * * if(D<0)
*** * * * * *** * * ******** * *** * * * * ** * **** * * * of %.2fx^2 + %.2fx + %.2f = 0  are complex and *** **** * *
* *** * ** **** *** * ** * * ** **** bb,d,dd;
* * ******* * * * * ** * * ****** ** *** * * **** *
* * ***** ** ** * * ** ** * ** * **** ** ** ** *
* * * *** **** * *** ** * ** ***** ** *** ** ** * ** ** * * = *** ** * * ** ***
* ** * * * *** ************ ** ** * ***** ** ** * *** * * * * * * = * * * *** ** *

*** ** *** ****** * * 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
*** * ** ** *
int main()
{
* * *** * * * * * * * **** * *** ***** * * * *
******* ** * * * ** * * * *** *** %f *** * * * * *** **
* * ***** * ** * * = (b*b-4*a*c);
* **** *** * * *** ** = (-b + sqrt(D))/(2*a);
* * ** ** ** * * *** * = (-b - sqrt(D))/(2*a);
** * ** * * * ** * *** * * = -b/(2*a);
** * ** ** * ******* ** ** * =sqrt(-D)/(2*a);
**** *** ** **** * ** ** **** * *
* * * ** *** *
***** ** * **** * * ** * * ****** * ******* *** * ***** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * ****** *
* * * ** * ** * ** ** **** *** * *** ** *** *** *** * = %.2f\nx2 = %.2f",x1,x2);
** * *** ** * ***** *

** *** ****** * ** * * *** if(D==0)
** * ****** * ** *
* ****** * *** * **** ** **** **** * * * *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
****** * * * ** *** * * ****** * * **** *** * * * = x2 = %.2f",x1);
**** * ** * *** * *** *
* **** * *** * ********
* * *** * ** * ******* ** *
** *** **** * **** * ******** *** * **** ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * * * * * *
* ** *** **** * ****** *** * ** ** ***** ** ** * ** ** * = *** *** * ** * * **** * *
* * ** * * *** * ** * * * * ****** ***** ** ****** * ** * = * ** * * * ** * ** * **
* *** * * * * **
** *** ** * ** * * *** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* **** ***
int main()
{
** ** * *** ** * * **** ** * * * ** * *
***** ** * ** ** * * ** ** ****** %f * ** **** * ***
**** * * * * **** * = (b*b-4*a*c);
* * * ***** * * ** * ** = (-b + sqrt(D))/(2*a);
* ** * *** ** *** ** * = (-b - sqrt(D))/(2*a);
** * ** ** ** * ** ** ** = -b/(2*a);
****** * * ***** * *** ** * * ** =sqrt(-D)/(2*a);
** * * * * **** ** * ******
* ** * * ** * ** *** *
* ** * * * * * * **** * * * ** * **** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** ** ** * *
** *** * * *** **** * * * * * * * *** * * * * * ** = %.2f\nx2 = %.2f",x1,x2);
* * * * * * * * * * * *

**** * ***** *** * * * if(D==0)
* * ** * ** **
* * ***** * * *** ** * ** * * ** * * ** * * * *** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ******* **** *** ** * *** **** **** * **** * * * * ** * = x2 = %.2f",x1);
* * * ** * * **** * *
* * * * *** *** *
*** ** * * ** *
** * ** ** ** ** **** *** *** *** * * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * **** ***
*** *** * * * * *** ** *** * * *** ** * *** ** *** * ****** ****** = ** ** **** * *** * ** *
* ** * *** * * *** * *** ** * *** ** ** *** ** ** = *** * * *** ** **
* * * * * ** **
**** * * ** * ** * * * * * *** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.151
©2016-2024

No related questions found

12,783 questions
183,443 answers
172,219 comments
4,824 users