[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
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22 Answers

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Hidden content!
#include<stdio.h>

int main (int argc,char *argv)
{
    char a;
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}
100/100 answered by (244 points)
0 0
Case 0: Correct output
Case 1: Wrong output
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Hidden content!
#include   *   *** *  ** *
int main(int argc, char *argv[]) {


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}
100/100 answered by (221 points)
0 0
prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c%c%c%c%c", &a, &b, &c, &d, &e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("%c%c%c%c%c", a+3,b+3,c+3,d+3,e+3);
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'
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Case 0: Correct output
Case 1: Wrong output
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int main(int argc, char *argv[]) {


 **   char a;
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 * * *    ****** char c;
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}
50/100 answered by (244 points)
0 0
prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:10:25: warning: format '%c' expects a matching 'char *' argument [-Wformat=]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
                         ^
prog.c:12:6: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
      ^
prog.c:12:12: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
            ^
prog.c:12:18: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                  ^
prog.c:12:24: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                        ^
prog.c:12:30: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                              ^
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("hello");
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:18:5: warning: incompatible implicit declaration of built-in function 'printf'
     printf("errol");
     ^~~~~~
prog.c:18:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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Hidden content!
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100/100 answered by (183 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
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Hidden content!
** * * **   *  **    

* * ** * * *  ** * *****  {

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100/100 answered
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
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Hidden content!
#include   ** ** **  ** *
#include  ** *** ** *   *

int main(int argc, char *argv[]) {
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}


INPUT
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OUTPUT
        *  ** *
100/100 answered by (243 points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
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Hidden content!
    *** ** * * * *   *

int **  *  argc, char  *** * {


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}
50/100 answered
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *   **  ***   * **

int main(int argc, char *argv[])
{
** *  *  *** * **  *  letterj;
**** **  ****  **    *****    letteri;
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* ** **  *  *** ***         **  = lettere +3;
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* *   *****      * ****  **

**  *  *  ** * **  0;
}
100/100 answered by (220 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
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Hidden content!
****     * *    **

* * **   *** **   * ***  {

*  *  
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i = ** *  
** = ****  *
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** *   * 
  * *   

* * ***  * ***  *  * ** ***  *
 *
100/100 answered by (283 points)
edited by
0 0
prog.c:1:16: fatal error: stdio: No such file or directory
 #include<stdio>
                ^
compilation terminated.
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:6:5: error: 'cin' undeclared (first use in this function)
     cin >> a;
     ^~~
prog.c:6:5: note: each undeclared identifier is reported only once for each function it appears in
prog.c:11:5: error: 'cout' undeclared (first use in this function)
     cout << a << endl << endl;
     ^~~~
prog.c:11:18: error: 'endl' undeclared (first use in this function)
     cout << a << endl << endl;
                  ^~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char *' [-Wformat=]
     printf("%c", a)
              ^
prog.c:12:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char (*)[5]' [-Wformat=]
     printf("%c", &a);
              ^
commented by (4.3k points)
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Case 0: Correct output
Case 1: Wrong output
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Hidden content!
#include   *******   ** *
#include * *  ** **** 

int main(int argc, char *argv[]) {
*  ***  **    ***** *    letterj;
* *  **   ****   * *       * **** letteri;
*   ****  *        * ****** * letterm;
  **  ***   *        ** **  **   * lettere;
*  *   ** *  *  *** *     * lettern;
*** *  *   * *   **** * 
    * ** *  * * * *     **   ** * *  **  * input the letter to encode:  * * **   
 ***  *   * *  *   *** ****   *  *** * *** *   *   ***   ** ** * ****  *  ***     *  ** *   * *  *** ****  *  **  * ** *** ** *** * *** ** ** *
***  * * *   *   ****
*      **  *** letterj = letterj +3;
**  * ***  *    * ** * ********* *   * = letteri +3;
***  ** * * ** *** **  ** **  **  *  = letterm +3;
     **  **  **   *   **  * * = lettere +3;
 *  ****  *    **     ***   * = lettern +3;
*   * **  * ** **      * ***
 *   *  *** *  ***   * * **** **  ***  ****   *    ***  *  **** ******** **         * lettere, lettern);
* *  *** **** **   
***  * ***** **  *     * *** ***  0;
}
100/100 answered by (220 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
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