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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
Available when: Unlimited - Due to: Unlimited

edited by | 332 views

22 Answers

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Hidden content!
#include<stdio.h>

int main (int argc,char *argv)
{
    char a;
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}
100/100 answered by (244 points)
0 0
Case 0: Correct output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include ** * *** **
int main(int argc, char *argv[]) {


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}
100/100 answered by (221 points)
0 0
prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c%c%c%c%c", &a, &b, &c, &d, &e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("%c%c%c%c%c", a+3,b+3,c+3,d+3,e+3);
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
int main(int argc, char *argv[]) {


* * * **   char a;
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** * ** *** char c;
* * * * * * ** d;
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}
50/100 answered by (244 points)
0 0
prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:10:25: warning: format '%c' expects a matching 'char *' argument [-Wformat=]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
                         ^
prog.c:12:6: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
      ^
prog.c:12:12: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
            ^
prog.c:12:18: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                  ^
prog.c:12:24: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                        ^
prog.c:12:30: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                              ^
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("hello");
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:18:5: warning: incompatible implicit declaration of built-in function 'printf'
     printf("errol");
     ^~~~~~
prog.c:18:5: note: include '<stdio.h>' or provide a declaration of 'printf'
0 like 0 dislike
Hidden content!
** * **** * * **

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100/100 answered by (183 points)
0 0
Case 0: Correct output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
*** ** ** *** * *

** * ** * * * {

* * **
= * * *
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e = **
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100/100 answered
0 0
Case 0: Correct output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include ****
#include ** * ***

int main(int argc, char *argv[]) {
** ** ** * **** ** *** * ** letterj;
* * * ** * * ** * * letteri;
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}


INPUT
* * ***** * *
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OUTPUT
* *** * ** * *
100/100 answered by (243 points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
0 like 0 dislike
Hidden content!
** * * ** * * *

int * argc, char * *** {


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}
50/100 answered
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include ** * *****

int main(int argc, char *argv[])
{
** *** letterj;
* * * * *** * ** ** ** letteri;
* ** ** * * **** * * ** letterm;
* * *** *** ** * * lettere;
* *** *** ** ** * lettern;
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* * ** ** ****** ** * * = letterm +3;
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** * * ** ** ** = lettern +3;
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***** * ** ** * * *** ***** * * * ** * ** lettere, lettern);
*** * * * * * *** *

** * **** ** 0;
}
100/100 answered by (220 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
* *** * * * * ***** * *

**** *** * * *** * {

**** ** **
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100/100 answered by (283 points)
edited by
0 0
prog.c:1:16: fatal error: stdio: No such file or directory
 #include<stdio>
                ^
compilation terminated.
0 0
prog.c: In function 'main':
prog.c:6:5: error: 'cin' undeclared (first use in this function)
     cin >> a;
     ^~~
prog.c:6:5: note: each undeclared identifier is reported only once for each function it appears in
prog.c:11:5: error: 'cout' undeclared (first use in this function)
     cout << a << endl << endl;
     ^~~~
prog.c:11:18: error: 'endl' undeclared (first use in this function)
     cout << a << endl << endl;
                  ^~~~
0 0
prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char *' [-Wformat=]
     printf("%c", a)
              ^
prog.c:12:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
0 0
prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char (*)[5]' [-Wformat=]
     printf("%c", &a);
              ^
0 0
Case 0: Correct output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include ** * **** **** **
#include ** ** * ** *

int main(int argc, char *argv[]) {
** *** * ****** * * * letterj;
*** ** * ** ** * *** ** letteri;
* ** *** ** * * ****** letterm;
** *** * *** ** **** * * * * lettere;
**** *** * ******* **** lettern;
****** **** * * **** ****
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* *** ** ** ** *** * *** ** ****** * * * * * **** ** ** *** *** * * * ** *** ** ** * ** *** * * *** * **
*** * * *****
*** ** letterj = letterj +3;
* ** * **** * ** ** * * * * * = letteri +3;
** * * ***** * * *** **** = letterm +3;
** * * * **** *** ** = lettere +3;
* * ******* ****** * * = lettern +3;
*** **** * * * * * * *
** * * * ****** * *** * * ** * * * ***** *** * * * * * ** ** * lettere, lettern);
* * * * *** **
** * * ** ** * *** * *** ** ** * 0;
}
100/100 answered by (220 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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