0 like 0 dislike
9.6k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 9.6k views

46 Answers

0 like 0 dislike
Hidden content!
#include * * *** *** **

int main(){
* ** number[5]; // Do not change
*** * *** size = 5, * * ** // Do not change

* * *** **** * ** *** ** // Do not change
** * * * ** ****** * * **** ** * ** * // Do not change
// Do not change

* * ** ** * * ** *** {
* * **** **** ****
* * * ** * * *** * ** ** {
** * * * * * * * ****** * ** **
** * ** * **** * *** ** ** *** ***** *
* ** * ** ** ** ** **** * ****
* * * ** *
** *
* ** *
* **** ** ** *** ** ** {
* ** * *** ** **** * ** ** ** * *** * * * * **
****

* ** 0;
}
100/100 answered by (273 points)
0 0
prog.c: In function 'main':
prog.c:11:6: error: 'i' undeclared (first use in this function)
  for(i=0;i<5;i++) {
      ^
prog.c:11:6: note: each undeclared identifier is reported only once for each function it appears in
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
** * ** ** ** *** * * ** * number[5];
*** * * * ** ** * * * size = 5, temporary;
    
* **** * *** * ** *** ** ** i=0;i<size;i++){
* * * ** * *** * * * *** * ** * * * ** **** *** * * *** *** **** * ** *
** * * * * * **

* * * *** * ***** * * **** * j = 0; j < size; j++){
** * * * ** ************ * * *** * ** ** i = 0; i < size-1; i++){
* **** ** **** * ** ** ***** * * * * * ****** ** * **** * * * * > number[i+1]){
***** ** ** ** **** * * ** ** * ***** * * * *** ***** * * * ** * ** **** * ***** ** * * * temporary; *** * ** ** ** **** * ** * **
*** * ** * ** ** ** * * *** * ** * ** ** * * ** ** ** ** * * *** * * * ** **** = number[i];
*** * * * ** ** ******* ** ** ** * * * ******** ** ** * * ** * * **** * ** * *** ** ** **** = number[i+1];
* * * ** * * * ** ** * * ** ******* ** * * ** **** * ** * **** ** ** *** ** *** *** * = temporary;
* *** * * ** ****** * * **** * * ** ** * * * ******** *** *** * *
* **** ** * * **** * ** ** **** * ** **
****** * ** ** * * **
********** * ** ** * i = 0; i < size; i++){
* *** * * * * * ** * ******* ** ** ** ** * * ", number[i]); *** **** * *** * ** * *** ** ** *
* *** ** ** * * *
    
** **** * * *** * * *** ** 0;
}
100/100 answered by (220 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** * * * **

int main(){
** ***   int number[5]; // Do not change
* * *   int size = 5, temporary; // Do not change
* ** *  
    for(int * ** * * ** // Do not change
*** * * ** * ** **** * ** * ** * * ** ** * ** // Do not change
*** ** * } // Do not change

**** *   // Your conditions start from here
* * **** *** * ** ** ***** j = 0; j < size; j++){
* *** *** **** * ** * * ** *** * * * ** i = 0; i < size-1; i++){
* * * ** * * * * ***** *** ** * ** * **** * * * *** * **** * > ****
**** ** *** * * * * *** * * * ***** * * **** * * * ** * * *** ** * * ** ** * * * *** ** * * temporary; *** * * * * * ** * ** *****
* ** ** ** *** * *** * ** * * ** **** **** * * ***** * * * ** ** ** * * * * = ** *
** * * *** * **** * ** *** * * * *** ** * ***** ** *** * **** *** *** ***** * **** * *** ** = * * * *
** ** * *** * ** ** ** *** ** * * ** * ***** ******* ****** * ** ** * * * * * **** ** = temporary;
* ** ** ***** *** * *** * **** ** ** * * ** ***** * * * * *
** * *** ** * ** * **** *** *** * * *
** * * **** **** * * *****
********** * * * *** * * ** i = 0; i < size; i++){
** ** * ** * **** * ** *** *** ** *** * *** * *** **** ** * *** * * **** ** *** * ** * *** *
** ** *** * * * * *** *
**** ** *  
** * * *** * ****** *** 0;
}
100/100 answered by (283 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** **

int main(){
* ** *   int number[5];
    int size = 5, temporary;
   
    for(int ** * * *
        ** * * * * ** * * **
* * *   }
* **** * * * ** * * * *** j = 0; j < size; j++){
******* * * * * * ** ** * ** ** ** ** from left to right */
** * * **** *** ** *** ** * ** * ** ** i = 0; i < size-1; i++){
*** * ** * ** * ***** ** * * ** ** * *** ** **** ** ** * ** **** i-th element with its neighbor to check if they are in order */
*** ** * * *** ** ** *** * **** ** * ** ** ** **** * * ** > * * *
* ** ****** *** * * **** ** ** ** * * * * * ** ***** * * * * * **** * **** * * * * * exchange the values of x[i] and x[i+1] */
* * **** * * * ***** ** ** ****** * *** ** *** *** ** ** * * ***** ** * * * * **** ** temporary; **** *** * ** * *** ** * *
* * *** * * * * ** ** ** ** * *** * ****** * * ** * * * * *** * * * * ** * * *** * *** = * *
*** * * * * * * ** * ** * * * **** * * * * *** * ****** * * ** * * *** ***** *** ** *** = * ** *
* * * * * ** *** ** * *** * ** * * * **** ****** *** * * ** ** * ** ** ***** * * ** ** ** * * = temporary;
*** * *** * ** * * * * ** * * * ** *** * *** ** * * ** * ** *
** ** ** * **** * **** * * * * * *** * *
** * * **** ** ***
* * ** ***** ** ** **
* * * ** ** * * print the array */
* ** * ** ** * ** ** * * * i = 0; i < size; i++){
* ** * * * * ** * ******* ** ***** * ** ***** * * * * ** ***** **** * * ** **** * * **
* ** **** *** * * **** **
* ***  
** *** *** ***** * * * ** 0;
}
100/100 answered by (153 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
prog.c: In function 'main':
prog.c:30:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("PAUSE");
     ^~~~~~
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** * ** ** *** ** x[] = {77,22,88,11,22};
** ** **** * * * * size = 5;
    
** **** * * * * * * * print the array */
* ** * * * * *********** i = 0; i < size; i++){
* *** * ** * *** ** * * ** * ** *** ** * * * ", x[i]); * *** * *** ** ** * * ***
* **** * ** * ** ** *
********** * ******** ** ****** * * * * **
** ** *** * ****
** **** ** * * I need this to happen size-times */
*** ****** * * ** * j = 0; j < size; j++){
**** *** ****** ** * * * **** * *** * ********* from left to right */
* * ** * * * ** * ****** * ** ******* ** * *** i = 0; i < size-1; i++){
*** * * ** * ** * * * ******* **** * * ** ** * ** * * *** * i-th element with its neighbor to check if they are in order */
*** * ** * * * ** ***** * * ***** * * ****** * * * * > x[i+1]){
** ** ** * * * ** * * *** * ** * * **** ******* ** ** * * * * **** exchange the values of x[i] and x[i+1] */
* ** * * ***** * * * * *** * * ** * ** *** ** * * ** *** *** **** temporary; *** * * * * ** * * * *** **
** * *** * **** * * * * ** ******* ** * * ** * **** * * * * * *** * * = x[i];
* * *** ** **** * ** ** ** ** * * * * * * * ** **** ** * * *** *** * ** ** * **** ** ** * = x[i+1];
* *** * *** * * * ***** *** ******* * ** * * ** * ******* ** * **** * * ** ********* = temporary;
** ** ** ** *** * ** *** ***** * ** ** ** *** ***** * ** * * * * * *
* * ** *** *** *** * * ** ***** * *
* ** ** * * **** * *
* ** * **** * * * * * *
** ** * * ** * ** print the array */
**** ** * * ** * *** * *** * ** sorting: \n");
*** ** **** * ** **** * i = 0; i < size; i++){
** ** **** * * ** * ** *** **** **** ****** * * ", x[i]); ** ******* * * * ***** *** * ** *
* *** ** **** ****
** ** ** ** **** * ** * ** ** * * * *
** **** * * ** **
**** ***** * * * * * **
* * **** ********** * ***** ** * * ***** *
* * * * ****** * * * * ** **** ** * * ** *****  
* * ** ****** *** ** * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * ** * * * * * ** x[] = {77,22,88,11,22};
* * ** * *** * ** ** * size = 5;
    
** **** * * ** * * print the array */
*** *** * * * * ** * **** * i = 0; i < size; i++){
* * ******* * * **** * * *** * ** * * * * *** ** ***** * ", x[i]); *** ** ** * * * * ***** * *** *
** ** *** * * * **
* * ** **** * * * *** * *
**** * * * * * * **
****** ** *** * ** *** I need this to happen size-times */
* * **** * * * *** ** *** * j = 0; j < size; j++){
***** ** ** * **** * *** ** ** * * * from left to right */
* * ***** * * * * * ***** ** *** ** * * *** i = 0; i < size-1; i++){
***** ****** * *** ** * * **** * ** ** * ** * ** * ** ** i-th element with its neighbor to check if they are in order */
*** *** ** ** * * ** **** *** * * * *** ** * ** * ** **** * * * *** > x[i+1]){
* * * ** *** * ***** * ****** * *** * ** ** ** * ******** * * ** ** * ** * *** exchange the values of x[i] and x[i+1] */
***** * ******** **** * **** *** * *** * * ***** ** ** ** ** ** ** ***** * temporary; * * ** * *** * * **** * ***
** * * ***** * * * * * *** * ** ****** *** * * ** * * * *** * * *** * * *** ***** * * = x[i];
* * *** **** * * * * ** * ** * ** * * * ** * ** * *** * * **** ** = x[i+1];
** ** * * ***** ** * * ** * ** ** ** *** ** ** ** *** *** * ** * * ** ** ****** *** = temporary;
***** ** ** * * ** * *** ** * ****** * *** ** * *** ** ** ***** *** *** **
* *** * ***** * ** ** ** **** * *** *
*** * ***** * ** *
** ** *** *** **
* * ** ** ******** print the array */
** * * ***** * *** * * ** sorting: \n");
* * ***** * * * **** i = 0; i < size; i++){
** ******* ** * **** ** * * * ** ** ** * ** * **** ** * ", x[i]); * * ** * ** ** * * *** * *
* *** * ***** * **
* * ** *** ** ** * * ** * **** * *****
** * ** * * * *******
* *** * ** * * ***
* ***** ** * ** * * ********* *
* * ***** * **** * ** ** * * ***** * *  
** ******** ** *** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
******* ** **** * * *** x[] = {77,22,88,11,22};
** ** ***** * * * *** * size = 5;
    
****** ****** ** ** print the array */
**** * * ** ** *** * *** ** i = 0; i < size; i++){
* *** *** * *** * * * * *** ** * ** *** **** *** ", x[i]); * * * *** * * * * ** * * * ***
*** * ** * * ** ** **
** * *** * ** **** * * **** * * * * *
*** * *** ** ***
* * ** *** * * I need this to happen size-times */
* * *** **** * * * *** j = 0; j < size; j++){
* ** ****** ** ** ** ** * * * * *** * * ** from left to right */
*** * ** * *** ** ** * **** * * ** * * *** i = 0; i < size-1; i++){
* * ** *** * **** * ** * * ** * *** ** * ** ** ** ** * * ** * i-th element with its neighbor to check if they are in order */
* *** ** **** * * **** * * * *** *** * * * * * *** * * ** ** ** > x[i+1]){
* *** ** ******* ** * * * * ***** ** * ***** * *** * * * ****** ** *** ****** ** * * * * exchange the values of x[i] and x[i+1] */
* ** *** * ** *** * ** **** * * ** * * ** * * ** * * ** ** * * ** ** temporary; ** * * ** * ** * ** ** * **** **
** ** * ********* ** ** ***** * * * *** ** * *** * ** * * * *** * ** = x[i];
** * * ** * *** ***** ** ** * ****** ** *** * * * ** * **** * * * ** ** = x[i+1];
* * ** * ** * * * *** * ** * ** * *** *** ** ** * ** * ******* * **** ** ** * * * = temporary;
* * ******** * * *** *** * * * * * * * ** * * * ** ** * *
* ** * * **** * ** **** ** ******
*** * ** *** * * *
** * * * * * * *
** *** **** * * print the array */
*** **** * *** ******** * * ** sorting: \n");
* ** * * * **** * ** * ** i = 0; i < size; i++){
* * ** **** * ***** ** * * * *** ** * * **** * * ", x[i]); *** *** * ** *** * * * *
* * ** * *** **
***** ** * **** * ** * * * *** *** * *
* ** ************
* *** *** ** *** * *
* * * * * ** * ** *** * * ** *
** * * * *** ** *** **** ** * ** *** * **  
*** * * ** ** * **** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * **** *** ***** * * x[] = {77,22,88,11,22};
* **** ** ** * ********* ** size = 5;
    
* * **** * ** * ** print the array */
** ** * * *** ** ***** * * * i = 0; i < size; i++){
*** ** ** *** * **** ***** ** * ** *** *** * * * ** * ", x[i]); ***** * **** ** * *** * * *
* **** * * ** ** **
* * ** ****** * * * ** *** ** * ** * * *
** **** ** * ** ** *
* ** *** * ** *** ** I need this to happen size-times */
**** *** * * ** ***** ** j = 0; j < size; j++){
* ** *** * * * * * * ** ** * *** ***** ** * from left to right */
**** ******* * * * ****** ****** **** **** ** * * * *** i = 0; i < size-1; i++){
*** *** *** ** * * **** * * *** ** ** *** ** * * *** * * i-th element with its neighbor to check if they are in order */
* ** * *** ***** ** ** * * ** *** *** ** **** ***** * ** ** * * * ** * > x[i+1]){
* * * *** ******** *** * *** *** * * ** * *** *** ********* * ** ** *** * ** ** ** * ****** exchange the values of x[i] and x[i+1] */
** ** ***** **** *** * * * * * * ** ******** * ** ** * ** ** *** ****** *** * * ***** * * * * ** temporary; * *** ** * **** ** * *** **** * *
* ****** *** ** * * ** * * ** * * ** *** * * ****** *** * **** *** * ***** * *** = x[i];
** ***** ** *** *** ** **** ** ** ** *** * * * ** * *** * * * *** ** *** * **** * ** ** = x[i+1];
** * ** * ** ** * ** * *** * ** * * ** * ** ** * * * ** ** *** ** ***** * ** **** ** ** * = temporary;
* ** *** ** ** * * *** * * * ** * * * * * * ** ** * **
* * **** ** * ** * **** *** *** * ** *** *
* ** ** *** **** * **
****** ** ** *** *
****** * * ** ***** * * print the array */
** ** *** * * * *** * * * ** ** sorting: \n");
*** * * * *** * **** * i = 0; i < size; i++){
* * ** * * * * ** * * ** * *** ***** **** ** * ", x[i]); * * * ** ******* * ** * * ** * **
* ** * * ***** **** * *
** *** ** * * ***** *** *** *** *
* ** **** * * ** *
** *** *** ** * *** *
* * ** ** * * *** ** * *** * * ***
** ** ** ** **** ** ** * ******* *** * **  
** * **** * * * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* *** *** ** * *** **** x[] = {77,22,88,11,22};
* ** * ** ** * ** * size = 5;
    
*** ** ******** * ** * ** ** print the array */
** * * ** *** * * * ** *** i = 0; i < size; i++){
*** * * * ** *** * * * ** ** * * **** ** * * * ", x[i]); ** * * ** * * *** ** ** *** * * ** *
****** ** **** * * * ****
** ** **** ** ** * * * * ** ** **
* * * ****** * * ****
* * * * ** * * ***** ** * I need this to happen size-times */
* *** *** ** * * * ** ** * j = 0; j < size; j++){
*** **** * * * *** ** * * * * ** * from left to right */
* * * *** ** ** **** ****** **** * ** *** ** * i = 0; i < size-1; i++){
****** * ** * **** ** *** *** * * ** * **** * * ** * * * * * * * i-th element with its neighbor to check if they are in order */
** * * *** *** *** * * **** *** * ** ** * * * ** * ****** > x[i+1]){
* * ** * * * * * *** * * * ** ** * * *** * * ** ** * * ** * *** * ** ***** exchange the values of x[i] and x[i+1] */
* * * *** * * ** * * * * ** ** * * ** * * * * * * * * ** * *** ****** * ** temporary; *** **** *** * * ** *** ****
* ** * ** * *** * * * * ** * *** ** * * ***** *** * *** * * ** * * ** **** * *** **** = x[i];
** *** *** * *** *** ** * ** ** * * ** * * ** * ***** ** * * * * ** * * = x[i+1];
* ** *** ** * ** ** ** * * **** ** ** *** ** *** * * * * * * * *** ** ** * *** = temporary;
* * * *** * * * * * ** * ** **** ** **** ***** ** ** *
**** * * *** * ** * ** * ***** * * ** *
** * * * ******** ****** * *
** * ** ** * ** *
*** * * * **** *** ** print the array */
** ** ** * ****** ** **** * * ** sorting: \n");
* * ** * ** i = 0; i < size; i++){
* **** **** * * * ** * * * * * ** ** * * *** * * ", x[i]); *** ** * *** *** * * * * * **
***** * *** * * **** * * **
* * * * ** **** * ** ** * * **** *
** ** ****** * **** * *
*** ** ******
*** *** * *** ** ** * * ** * ** * **
**** * * ***** **** * * *** *** * ** ** **  
** *** * ** * * * ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** **** ** ** ** * x[] = {77,22,88,11,22};
* ** ***** * * ******* ** size = 5;
    
**** ** *** ** ** * print the array */
**** * ** * * * ** i = 0; i < size; i++){
** * * ***** ** **** *** ** * * * * * *** ** * ", x[i]); *** ** * ** * ** ** ** ** * * **
*** ** * * ** * *** **
* * *** ********* * * * * * * *** * ** *
* * * **** ** *****
* ***** * * * ***** I need this to happen size-times */
*** ** *** ** ** * j = 0; j < size; j++){
*** * ** * * ** * * ** * * * ** ** * ** ** from left to right */
* * ****** * * * * * * **** * * * * * *** i = 0; i < size-1; i++){
* ***** *** * * * * *** ** ****** * ** *** *** * * * **** * ** ** ** * * i-th element with its neighbor to check if they are in order */
** *** * ******* *** ***** ** *** *** ** *** ** * ****** > x[i+1]){
* ** * ** * * * ** * *** * * * ***** *** * * *** ****** **** * ***** * * **** * ** ** ** ** * * ** exchange the values of x[i] and x[i+1] */
* * ** ** * * * ** * **** ***** * **** * * ** ** * * * ** *** * ** * ** * * * * temporary; ** ** ** *** **** * * * *****
* * * ** ** * *** * * ** ** * ** * ** ******* ******** ** ** ** * *** * * * ** ** * ** = x[i];
* * ****** * * * * *** * * ** * * ** * ** * ** * ***** * *** ** **** ** ** *** ****** = x[i+1];
* * * ******* * **** ** ** * * * * ** * ** **** * * * * * * * ****** ******* ******** = temporary;
* ** ***** * * ***** ** ** **** * ** * ** ********** * ***
* * *** * ** *** * *** *** * * **
* * * * * * * * **
** ** * * * *****
** ** **** **** * * print the array */
*** * ** ** * ***** * ** * *** * sorting: \n");
* * * * * *** * * i = 0; i < size; i++){
* ** ** * * ** * ** * * ***** * * * * * ", x[i]); ** * * ** * * * ** ** * *
* ** ** ** ** **** **
** ** *** ** * * *** * * * *
* * * ** **** *
** * * *** ** * * *
* *** ** ***** *** ** ******* * *
* * *** * **** * * *** * * *** * **  
* * ***** * ** *** ** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.21
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 6.1k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.9k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 5.3k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 2.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users