0 like 0 dislike
3.9k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 3.9k views

46 Answers

0 like 0 dislike
Hidden content!
#include * *** * **** *

int main(){
** * ** number[5]; // Do not change
** * size = 5, * // Do not change

* ** * ** * * * * // Do not change
* *** * * *** ** *** * * * // Do not change
** * ** // Do not change

* ***** ** ** **** ** * * {
* ** * * * * ** ** * **
* * *** ** * ** * * ***** * {
*** ** ****** * * ** ******* * ** *
***** * * * * ** * ** * * ***** * *
**** *** ** ***** * * * **
* ** *
** ** **
* ** *
* * *** * * * ** * * {
** * *** * *** * *** * ** * * *** ** *** *
** **

* **** * 0;
}
100/100 answered by (273 points)
0 0
prog.c: In function 'main':
prog.c:11:6: error: 'i' undeclared (first use in this function)
  for(i=0;i<5;i++) {
      ^
prog.c:11:6: note: each undeclared identifier is reported only once for each function it appears in
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
** ***** * * * * ** * * number[5];
* * *** * * * ** * ** * * * size = 5, temporary;
    
* * *** * * * *** * **** i=0;i<size;i++){
** * * *** ** * * *** ** *** * ** * * * ***** ** * ** * * * *** * *
* * ** **** * * ** * * *

* ** ***** * ** ** *** * * ** * j = 0; j < size; j++){
* * *** ** *** ** **** ******* * ** ** * * * i = 0; i < size-1; i++){
**** * **** ** **** * ** * **** * * ** *** * * * * ** * ** * ** ***** > number[i+1]){
*** *** * * *** ** **** ** * * ***** * ** ** * ** * * * * *** ** * **** * * * **** * temporary; * *** ** *** ** * * * * *
* ** **** ****** * * **** * ***** **** * ** * ** ** * *** ** * ** * *** * ****** *** *** = number[i];
* * ****** * ******* **** * * * ** ** * *** *** * * ** *** *** * ** **** * * ** * ** ** = number[i+1];
** * ** * ****** *** * * ** ** * *** * *** * ** * * * * * * * * * * * *** * ** * ***** * = temporary;
* * * * * ** *** *** ** ** * * ** ** ** ******* ** ** ** *** * * *** *
* *** ** ** * *** ***** ** *** * * * * *
** *** **** * ** * * **
* ** * ** * ** ** * ** * i = 0; i < size; i++){
* ** * * * *** * ** **** * **** * * * * * *** ", number[i]); *** ** **** * * * * * * * **
** ** **** ** * *** **
    
* * *** *** **** ** * 0;
}
100/100 answered by (220 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** * *** *

int main(){
  int number[5]; // Do not change
* *   int size = 5, temporary; // Do not change
* * * *  
    for(int **** *** * // Do not change
** * * ** * * * ** ** * *** ***** *** * // Do not change
* * **** } // Do not change

* *   // Your conditions start from here
* ** * **** * ** * * ** ** j = 0; j < size; j++){
* * **** * *** *** *** * * * ** * * **** i = 0; i < size-1; i++){
**** * **** **** ** *** * ** ***** ** * ** * * * ** ** ** ** * **** > ** ***
* * * * ****** * **** **** ** * *** ****** * *** ** * * ** ** ** **** ** *** ** ** *** temporary; * ** ** * *** * * ***
* *** ** ** * * * * ** * * * ** *** * *** ** * ** * * * ** * * * * * *** * * ** *** = **
*** * ** *** * ** * * ** * *** * **** ** ** ** * * *** * * * * *** ** *** *** * ** * * = * **
**** * ** * ** ** ** * * ** ** * * * ** * **** * *** * **** ** * * * * * * * * * ** ** = temporary;
** ***** **** ** * * *** * ** **** * ** * ** ***** **** * ** * *** *
* ** * *** * * *** *** **** **** *****
* ** ** * * * *** *
** * *** ******* *** * * i = 0; i < size; i++){
** ** *** * * * * ** ******** * ** * * * * * * *** * *** * * * * *** * * **** * *** **** ***
* *** * *** * ** * *
**  
* ** ****** ** * * * 0;
}
100/100 answered by (283 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * *** * * * *

int main(){
*** *   int number[5];
    int size = 5, temporary;
   
    for(int ** * ** **
        ****** * ** *
* **   }
* ** ** * * ** *** j = 0; j < size; j++){
* *** * * * ** **** * *** ** * * ** *** * from left to right */
*** ** ** **** * ** ** * ** ** * * * * * i = 0; i < size-1; i++){
* * ****** ** * **** * * * ** * ****** * ******** ** * ** * ** * * ** i-th element with its neighbor to check if they are in order */
*** * * * * * * * ** *** ** * * * *** * * * ** * * * * ** ** * * ** > ** *** *
** ** ** * * * ****** * * ** * * * **** ***** * * *** *** * * ** ** * ****** **** * exchange the values of x[i] and x[i+1] */
* *** * * ** **** ** * *** *** **** * **** ****** ** * * * *** * * * * *** *** * temporary; * * *** ** * *** * **** * ** *
* *** **** *** * ** * ** ** * ** ** *** * * * ** * * * ** ** **** ** ** *** **** * ** * *** * ***** ** = ** **
** ** ** * ** * * ******** * ** * * * * ** ** ** *** * **** * ** * ** ** * *** * ** * = ****
* * ***** * * ** **** **** ** * *** ****** * * ** * * * ** * * ** ** * * *** ** * *** ** = temporary;
* ** *** ** * *** * * **** *** ** * * ** * * **
* * * * ** **** * ** *** * * ** * ** ** *** **
* * * ** * ** * * *** *** **
* ** *** ** ** ** * * * **
** *** ** *** *** * ** ** print the array */
*** * * * * * * * * i = 0; i < size; i++){
** * * * *** ** *** * * * * ** *** ** * * ** ** * **** *** *** ** * * *** * ** * * * * **
* ** * ***** * ** ***
* *  
** * * *** * ** * * * * *** * 0;
}
100/100 answered by (153 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
prog.c: In function 'main':
prog.c:30:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("PAUSE");
     ^~~~~~
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** ** * * * * ***** * x[] = {77,22,88,11,22};
* ** *** * * * ** ** * size = 5;
    
*** **** **** * * ******* print the array */
*** * ** ** *** *** ** * * **** i = 0; i < size; i++){
* ** ** ** * *** * * * *********** *** ** * * * ** ** ", x[i]); ** *** ** ** *** * * ****
* **** *** * * ** * * *
** *** ** * * * * * * ** ** * *
* * * **** *
* * ** ** *** * * * * * *** I need this to happen size-times */
* ** **** * * * * **** j = 0; j < size; j++){
** * ** ** ** * * ** * * ** * * ** * from left to right */
* * ** ** ** * * ** * * * ** * ** **** ** * i = 0; i < size-1; i++){
* **** * ** ** ** ***** ******* * ** ** * * * * * * *** *** * * ** i-th element with its neighbor to check if they are in order */
* * * * * * * * * * * ** * ** ***** *** * ** * ******** **** ** * ***** > x[i+1]){
* **** * ** * ** ** * ** ** * ** ***** ** *** *** * * ***** * * ** *** *** * *** ** exchange the values of x[i] and x[i+1] */
* * **** ****** * * * *** ** *** **** ****** ** ** ** ***** * * * * **** *** **** * *** temporary; * * *** *** *** * ** ********* ** *
* ** * * * * ***** ** ** * *** ***** * * * * * *** * * ****** * *** * * *** ******* = x[i];
* *** * ******** ** * * * ***** * ** *** * ** * * ** * ** * * *** * ********** * * ***** = x[i+1];
*** ** ** ** * ** * * *** ** ****** * ***** * * ** * ** **** ** ** * * * * *** ** = temporary;
** ** ** *** ** * ***** ** **** *** * * *** *** * **** * **** **
*** * * * **** ********* * ** ** **** ****
** *** ** *
**** ** ** ** * *
* ** * *** * ** * ** * print the array */
* *** *** *** * ** * * * ** ** ** * * sorting: \n");
* * * * * * * ***** *** ** i = 0; i < size; i++){
***** *** * * * * *** **** ** * * ** *** ", x[i]); * * ** *** ** * * ** * * * **
* ***** **** ** ** * **
* ***** **** * ** ** *******
* ** *** * * ** **
* * * ** ** * ** * ** * *
* * ** * * * * ********* ** ** * * *
** *** ** * ** * ** ** *** * ** * ** **  
**** * * * * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * * * * * *** * x[] = {77,22,88,11,22};
*** *********** ** * ** * size = 5;
    
** * ** * ****** ** * ***** ** print the array */
*** *** ** ** **** **** * * * * i = 0; i < size; i++){
** * * ** * ** * *** ** * *** ** * *** ** * ** *** ", x[i]); * * *** ****** *** ** ***** ** ***
*** ** * * * * ***
* * * * ******* * **** * **** * ** * *
*** * ** ** ** ** *** ***
* ** * * * ** * **** *** I need this to happen size-times */
* **** ** ** *** * ** *** ** j = 0; j < size; j++){
* **** *** * *** * * ** * ** *** * ** * from left to right */
* * * ** * * ** *** * *** * ***** * ** ** ** i = 0; i < size-1; i++){
* ** * * * * ** * *** * * * ** * * **** ** ********** * i-th element with its neighbor to check if they are in order */
******** *** ** ** * **** * * ** * ** * ** * ** * * **** > x[i+1]){
* * * ** *** *** ***** * * * * * ** ***** **** ** * * **** ** ** ** * ** * ** * * exchange the values of x[i] and x[i+1] */
** *** ** * **** * **** ** * *** * *** * *** *** * **** *** ** **** * * * * ** *** temporary; * *** ** *** * *** *** ** *** *
** * ***** * * *** *** * ** *** *** ** **** ** *** * *** * * * ** ******** ** * * * = x[i];
* * *** ** ** ** * * * * ** * *** *** * **** ** * ** *** * * * * * * * ** * ** * ** * = x[i+1];
**** ********* * ** * *** *** * *** * ** * ** * * * *** **** * * * * ** *** *** ** * *** = temporary;
* * * ** * * ***** ** * * * *** ** * * * * * **
* * ***** *** *** * ** * *** ** *
* * **** ** * ****** * *
** ******** ******** **** **
* ***** * * * ** print the array */
** ** ** ** **** * ** ** **** * sorting: \n");
* **** ** * ** * * ***** i = 0; i < size; i++){
** ** **** * * ** * * ** ** **** * ** **** * * * ******* ", x[i]); ** ** *** * ** *** * **** ** * * *** *
*** * *** * **** *
* * * * ** * * * **** * *** *
*** * ** **** **** **
** *** * **** * ***
** **** ** * * ** * * * * ** * **
*** * **** * ********* ** ** * *** ** **** ****  
** ** * * * * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** ***** * * **** * ** * ** x[] = {77,22,88,11,22};
***** * * ** **** * * * size = 5;
    
** *** * ***** ** * *** * * print the array */
* * ** **** * * *** ******** i = 0; i < size; i++){
* * * * * * * ******* ** **** **** * * ", x[i]); ** ** *** * *** **** **** * *
* * * *** *** * ******
***** * * ** * * * ** * *** * *
* * ***** ** * *****
** *** ** **** ** ** I need this to happen size-times */
* ** ** **** * * * * *** j = 0; j < size; j++){
* ** ***** *** * * ** * *** * ****** * * * ** from left to right */
*** * ****** **** * ** ** * **** * * **** i = 0; i < size-1; i++){
* *** * ** * ** *** *** ** * ***** * ** * * **** * * * * ** * ** i-th element with its neighbor to check if they are in order */
** * * * * * * ** * * ** * * *** * ** * * *** ** * > x[i+1]){
* * * * * *** *** * * * ** ***** ** * ** * **** ***** * * * ** * ** ** ** * exchange the values of x[i] and x[i+1] */
******** * **** *** * *** * **** ** *** ** * *** ** * * * ** ** *** * * temporary; * * ** * * * * *** * ** * * ****
* * ** *** * * *** *** * * * * * * * * *** *** ** * **** * **** ** * * * ** *** *** * = x[i];
* * * * * **** ** * ** *** ** * ** ** ** * ** ***** * * ** * * * *** ** *** ** = x[i+1];
*** ** ** * ** ***** ** * *** * **** ** * * *** ** * * ** * ** ** * ** * * = temporary;
* *** * *** * * ** * *** ** ** * ** * * * **** * * *
* **** *** * ** **** * *** **** * * ***
* *** * * * ** **
** *** **** * ** * * *
****** * * * * ** ** print the array */
* ****** ** **** * * * * **** * sorting: \n");
*** * * **** * *** * * * *** i = 0; i < size; i++){
* * *** * **** * ** ** * * ** * * * ****** **** * ", x[i]); ** * * ** * * ** * * *** ***** * *
* * * *** *
* ** * * *** * * * **** **** * * *** ** *
* *** *** * * ** *
** ** * * ** **** ** *
* **** * * ** * * * ** ** * ** *** ***
* * ** * * ******** * * *** * *  
* * * * * * ** * *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ***** * * **** * * ** x[] = {77,22,88,11,22};
* ** ** * * * * * * * size = 5;
    
* * ** ** * ** * *** * print the array */
* ** * * ** * ******* ** * i = 0; i < size; i++){
* * *** *** * ** ** * * * ** *** * * *** *** ** ** ", x[i]); * * *** * ** ** ** ** * ****
**** *** **** * *** *** ** *
*** * * ** * ** ** * * *** ** *
*** ** ** ** * * *
* ***** ** ** *** * * I need this to happen size-times */
** *** * * *** ** * ** j = 0; j < size; j++){
* ** ** * * * * * * ** * ***** * *** * ** from left to right */
** * ** ** * * ** ** * * ** * ** * * *** * *** i = 0; i < size-1; i++){
* * *** ** *** * * **** *** ** ****** ** ***** * * ***** * i-th element with its neighbor to check if they are in order */
** * ***** *** ** * *** * * ** * * * ** ************* * **** ** * * > x[i+1]){
* ****** ** * * * ** *** * * * ** ***** *** ** * *** * * * * * * * ******* exchange the values of x[i] and x[i+1] */
* * * * ** * ** ***** *** * * * *** ** *** * * * ** ** * *** * * ***** * * ** * temporary; **** **** * *** * * * * **
* ***** ** *** *** * * * * ** ** ** ** * * **** * * * * ***** ** * * ** ******** ** * ** * * = x[i];
*** **** ** * *** * * *** * * ** ***** *** **** ***** ** ** ** ** ** *** * ** ******* ** * = x[i+1];
** ** * ***** * ** *** *** * ** *** * * ** * * * * **** ** ** * * * * **** * = temporary;
* * ** *** ****** ** * * *** ** **** ** ** * * * ** * * *** ** * * ***
* ** ***** * * * * *** * *** * *** * * * *
* *** * **** * * ***** *
**** * * * ** *
*** ***** * * * * * print the array */
** ** * * * * ******* ** ** * sorting: \n");
*** *** * * ** **** i = 0; i < size; i++){
** * * ** * ** * ** * * ** * ** * ******* ", x[i]); ** ** ** * * * * * *
*** *** * ** *** * *
* *** * ***** ** * * * * ** * * *** *** **
* * * * *** * ** ***
** * * *** * ** ** ***
* *** * ***** * ** ******** * ** *** *
** * * * * * * *** * *** * * * ** * * * * ** *  
** * **** ** * * ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
****** * * * * ***** * x[] = {77,22,88,11,22};
*** * ****** *** ** ** size = 5;
    
*** * * *** print the array */
* *** ***** * * ** * ** * i = 0; i < size; i++){
* ** * ** ** ** * ******** * ** * *** * * *** * ", x[i]); *** *** * ***** * **
* * * **** ** ** **
** ** ** * ** * **** ** ** * * * * * **
** ** **** * **** *
** *** * ** * * *** * ***** I need this to happen size-times */
* ** ** *** **** *** ** *** j = 0; j < size; j++){
** ** * * **** **** ** ******* * *** ** **** ** ** from left to right */
*** * **** ** ** ** * * * * ****** **** *** i = 0; i < size-1; i++){
* *** * * ** * * **** ** * ** * * * * ** * * ** ** * i-th element with its neighbor to check if they are in order */
* * * *** ****** * * * * ******* **** **** **** * * ** * ******* > x[i+1]){
* * * ** * ** ** ** ** *** * ** * ** * **** *** * * * *** *** *** ****** * * *** * *** * *** * * exchange the values of x[i] and x[i+1] */
* **** *** *** * *** * * * ****** * *** ** * ** ** * **** **** * ** * ** ** ** ** temporary; ** ***** ** ** * * * *** * * *
* ************ ****** * ** ****** * * ***** * ** * ** *** *** ** * * ** * ** ******* ** = x[i];
*** * ** **** * ** ** ** ** * *** ***** * * * * * * **** * * *** * * * *** * * * * ** * = x[i+1];
* * ** * * * ***** * *** ** * ** * * ** ** * * * ** * ** ** * ** ** * ** ** * * **** = temporary;
* **** * * *** * ****** * *** ****** ***** * * ******** *
***** * ***** **** ******* * * ** * * *
* * * * *** * * **** **
*** * * * * * *** * * *
***** * ** * **** * ** ** print the array */
* ** * ** * ** * * *** * ** sorting: \n");
** ****** * * * *** * i = 0; i < size; i++){
** * *** * ** * ** * * * * * * * * * * * ", x[i]); * * * ****** * ***** ****** * *
* **** *** * * **
* *** * * * * * * ** ** * * ** * * ** *
* * ** ** ***** * ** ****
* ** *** * * * * *** ***
* * * ** ** * ** *** * **** ** * * *
** ** ***** * *** ** ** * * **** ** *** ** * ** *  
*** * ** ** ** *** ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* *** *** * * ** * x[] = {77,22,88,11,22};
** ** * ** * * * * ** size = 5;
    
** *** ****** * * * print the array */
****** ** *** ** * ** i = 0; i < size; i++){
*** * ** * *** * * *** ** ** **** * * **** * * ** * * *** * ", x[i]); *** ** *** * ** * * ** ** * **
* * ** * *
* ** ***** * * * * ** **
*** * * *** * * ** *
** ** * **** ** ** * ** *** I need this to happen size-times */
**** ******* * *** * *** * *** j = 0; j < size; j++){
** ** *** ** * ** *** ** * * * *** ** * ** * ** *** from left to right */
***** * * *** *** * ** * ***** ** * ** ** ** i = 0; i < size-1; i++){
** * ** ** ** * ** * ** * ** * ** *** ** * *** * * ** ** * *** i-th element with its neighbor to check if they are in order */
* ** * * * **** * *** * * **** ** * ** * ** * *** * * *** **** * * *** > x[i+1]){
* * * * *** * *** * * *************** * * **** * * * *** ** * ** **** ** * *** exchange the values of x[i] and x[i+1] */
** ** *** * * * *** * * *** *** **** * ** * ** * ** * ** ** * * *** * * ** **** *** temporary; * * ** * *** **** * * ** * ***** ****
* ** * ** * * * ******* * ** * ************* * ** * * * * *** ** ** ** **** * * * = x[i];
* * * * * **** ** ** ** ***** ** **** ** * **** ** * *** ** ** * *** ** * * * *** *** = x[i+1];
* **** * *** * ** *** ** * * * ** * * * * * * * * ***** ** * *** * * ** * * * = temporary;
* *** ** *** * * ** * ** ******* ** * * * ** * *** * * * * **
* *** ******** ** *** ** ** *** * * ** ** ** ***
* ** ***
** * * * * * ***** *** *
** * **** * * **** *** print the array */
* ***** ****** ** ** *** * * ** ** sorting: \n");
* ** * **** ***** * * * ** i = 0; i < size; i++){
***** **** * ** ** * * * * ** ** ** * * * ** * ** * ** ** ", x[i]); * *** * ** ** ** * ** ** * ***
* * **** ** * * *** ** **
* * ** * ** * ** **** ***** *** * * *
* ** ** **** ** * * ***
* ***** ** *** **** ***
** * *** * ** *** * * *** ** * ** ***
* * * **** * ** ** ** * ** **** * * **** * **  
** * * ****** **** *** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.94
©2016-2024

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 2.4k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 1.3k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 1.8k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 1.1k views
12,783 questions
183,443 answers
172,219 comments
4,824 users