0 like 0 dislike
16.3k views

Write a program that asks the user to type an integer N and find out all the factors of N and display it on screen.

寫一個程式 輸入一個整數N,找出N的所有因數

Example input 1

10

Example output 1

1 2 5 10

Example input 2

24

Example output 2

1 2 3 4 6 8 12 24

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 16.3k views

72 Answers

0 like 0 dislike
Hidden content!
#include * * ***

int main(void)
{

* * ***** * ** *** * ** * ** *

* ***** *** *** * * *** ***** *** *** * ***** * * *
******** (a=1; * * ** ++a){

** ** * * * * * *** * * *** (n%a==0){

* * *** * * * *** * * * ** * *** * ** ** * * * *
** *** *** * * ** * *
* *****







}
answered by (-107 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main(void)

{
    int n,i,count=0;

**** *** * * * *** ** * * ** *

    for(i=1; i<=n; ++i)
** ***** ** * * *** * * * * * * *
**** * ** * * * ** *** *** ** **** * * * *** * ** * ** (n%i==0)
** *** *** ** * *** * * ** ** * ** * * ** ****** * ** ** *

** * ***** ** * **** *** *** * ** *** ** * ** ** * *** * ** ** **** ** * (count==0)
* ** * * * *** ** * *** ** ** **** * *** * ** ******* ****** ** *** ** * * **
* ** * *** * * * ** * **** **** * ** ** * * **** * * * **** * *** *** * ** * ***** **** * *** * * *
* * * * ***** * * ****** * * ** * * * ** ** * * ** * *** * * * **

** * * * * * **** ** ** ** * * ** * * * ** * ** ***** * **** ** * {printf(" %d",i);}
* ** ** ** * ** * ***** ** ** * * ***** ** *** ** * ** *

** * *** * *** * *** ***** * ****** * ***** * * ** * ***

** *** * * * * * ** * * * * ** ** ***

** * * ** ** * * * *** * * ********** 0;
       }
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main ()
{
    int x,y,z,a=0;
* ****** * *** * ** ** * * ** * * * * ** ** *
    for (y=1;y<=x;y++)
    {
** ** * ** * * ** * ***** ** **** **
** **** * * *** * ** ** * * * (z==0)
* * * * * * * * ** ** ******** *** *** *
** ** ***** ** ** * * ** *** *** * (a==0)
* * * **** * * * * * *** ** **** * *
******** **** ** ***** * * * * *** * * * * * **** ** * * ***** ** * *** ***
* ** * * * *** * ** * ** ** * * **** ***** * *** ***** ** *** *** * *
** ** * * *** ** * * * * ** **** *
* * * * * * * * ** **** *** * * * **** ** * * * *****
** ** *** ** * * ** * ** * ** ** **** *** ** ** *** * * ** * ******
** ** ** * *** * **** ** *** * * * * * ** *** * *** ** * * ** *** * * * %d",y);
** * * *** **** * **** * *** * ** * * * * * * * * ******

** * ** *** *** * * ********* ** * *

** * ** * ** * *** * **** **

}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
    int i,n,c;
* * *** *** * *** * * *** * * ***
    for(i=1 ; 1<=n ; i++)
****** * * ** * * * * ** **** * ** * * **
** * ** *** * * *** * **** ** *** * * * * ** **
**** * * ** *** * **** ** ** * ***** * * *** * *
        {
* * * *** ** * *** * *** * ******* * * **** ** ** ** * * * ** * * * * ** * ** **
** ***** * * **** * * * *** * * * * * ** **** * **** * * **** * ** * ***
* ** * ** * * * * ** * ** * ***** ** *
*** **** ** * * *** * **** ** ** *****
* * *** * * ** * *** ** * * ** * ** * ** ** * ** ***
* ******* ** **** ** ***** **** * * * * * * * ** * * *** * * ** ******* * %d",i);
* * * * * *** * ***** * **** ***** *** * * **** * * **
* **** *** ** * * ** *** * ** ** * * ****
}
answered by (-323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
    int m, n;
    int a=0;
*** * * *** * * ** * * **** * ** * ** * **** ** * * * *
** *** * * *** * * * * ** n <= m; ++n)
    {
** * ** * *** ** * * ** * ******* ** *** (m%n == 0){
* ** * ** *** * * ** * *** * * **** *** ** ***** *** * ** ***** *******  (a==0) {

*** * * *** ** * * * **** * **** *** *** ** ** ** * *** ** * ** *** * * * * **
*** * * ** * * ** *** * * *** * ** *** ** * ** ** * * ***** ** * ** * * * {
***** *** ** * * * ** * * ***** ** ** * * * *** * * *** ** * * ** **** * *** *** * **** *** ** * ** * * ** *** ");
********* * * * * ** * * * ***** * ** ****** * **** ** *** *** * * **** ***** *** *

* *** ** ** * * **** * *** ** * ****** ** * ** ** * * **** ***** *** ** * * * *** *
* * **** ** * **** * * * * ** ** *** * ** * ******* * ** * ** * * ** ** ** * * * * * ** * * * * * **
* *** *** ****** * * * **** * ** * * **** * **** ** * *** **
    }



    return 0;
}
answered by (-254 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
    int N,a=1;
* ** ** ** * **** ** ** * * *** * ** ****** *
**** ********** * ** **** **** *
    {
*** * * ** * ** * * *** *** * ** * *** ** ** *
** * *** * **** ** ** ** **** ******* * * * * ***
* **** ***** * * **** ****** * ** * ** * *** ******
* ** ** ** * ******* * ****** *** * * * ** * * **** * *** * ** *
* ***** ** * ***** ** ** **** *** * * * ** ** * *** *** **** * **** ** * * *** ");
** * ** * *** * * **** **** *** ** *** ** *** * *

** * *** ** *** *** * * * ** *** ** * * * *


    }

* * * * ** * * **** * ** 0;

}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
*** *** * *** * *** N,a=1;
*** *** * * *** ** ** * **** * * * ***
* * * ** ** ** ** * * * ** *
    {
* ** ** * * * **** ** * * ***** *** *
* ** *** **** ** * ******* *** ** ** ** *
** ** * ** * ** ** * ** * *** * *** *** ** * ****** ** *
* * ** *** * * * **** * ***** ** * **** ******** * * * ");
** * * ** * * * * ** *** ** ** * * * **

* * ** ** *** * ** * ** * ** * * * *


    }

* ** *** **** **** * * ** ***** 0;

}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
int a,b,c=0;
int space=0;
scanf("%d",&a);
  for(b=1;b<=a;b++)
  {

**** ** * *** * * *** **** ** **** *** *** * ** * ** **
* * ** *** * ***** * * * ****** * ** * *** * * ** **** ** *
** ** ** ** * * ** * **** ** * * * * ** * ** * * * * ** * * **** ** ** * * *** * **** ** * * * *
** * *** **** * *** * * ** * **** * ** **** ** ** *** *** * ****** * ** ** * *
*** * ******* * * *** * * * ** *** * ** ***** * ***** ***** ** * * **** *
* *** * **** ** * * *** * *** *** * * ** * ** * ** * *** ** *
******* ** ******** *** *** * **** *** *** ** **** * ** * ** ****** * * ***** * **** * * * * *** * *** %d",b);
** ** ** * ** ****** ** * * ** *** * * * * * **** ** * * ** *** ** ***** * ** **** ** *** **** ** *
*** * * * * **** * * *** ** * * * * * * ** ** * * ** * * * *
        }

  }
}
answered by (-329 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main ()
{
* ** * * * ** ***** n,i;
**** * * * ** * ** *** * *** ** ** ** * ***

* ****** *** *** ** ** ; i<n ; i++)

* ** *** * * ** * * ******** * ** * * * (n%i==0)
* * **** * **** * * ** * * * * * * * * ****** * * ***** ** * ",i);
*** * ** * ** * * * ** * ***** *
* * *** * * ****** * 0;
}
answered by (-196 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* * * * * * * * ** **** *** N,a=1;
* * * *** * ** * * *** * *** * *
**** ** * **** * * **
    {
* * *** ** *** ** * * ** *** ** *** ***
** *** *** ** * * * * ** *** ** **** ** *
** * * *** * ** * * ** * *** ***** ** ** ** * * * *** ",a);

* ** * **** * * *** ** *** ** * ** ***** * ** *
** *** *** * * * ** * *** ** *** * ***** ** * * * ** ** *


    }
** * ** *** ** * * 0;

}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.95
©2016-2026

Related questions

0 like 0 dislike
99 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 24k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 21.4k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 16.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users