10-19 Exercise 2: Convert decimal to binary number

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Write a program to convert a decimal number (<256) to binary. Use +-*/% operations only. Loops are not permitted

寫一個把十進位轉換成二進位數的程式。請使用 +-*/% 運算子，不允許使用迴圈。

Example input:

50

Example output:

110010

 

[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (12.1k points)
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Hidden content!
#include<stdio.h>
int main()
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Hidden content!
#include<stdio.h>
int main()
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answered by (-214 points)
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prog.c: In function 'main':
prog.c:4:21: error: unused variable 'result' [-Werror=unused-variable]
     int a,b,c=1,d=0,result;
                     ^~~~~~
cc1: all warnings being treated as errors
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Hidden content!
#include <stdio.h>
int main()
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Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
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answered by (-498 points)
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prog.c: In function 'main':
prog.c:17:12: error: too many arguments for format [-Werror=format-extra-args]
     printf("%d%d%d%d%d%d",h,g,f,e,d,c,b);
            ^~~~~~~~~~~~~~
cc1: all warnings being treated as errors
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Hidden content!
#include <stdio.h>
#include <stdlib.h>
int dec_num=0;
int bin_digit[8]={0,0,0,0,0,0,0,0};
int bin_num=0;
int main()
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Hidden content!
#include <stdio.h>
#include <stdlib.h>
short dec_num=0;
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int bin_num=0;
int main()
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answered by (-286 points)
0 0
prog.c: In function 'main':
prog.c:8:13: error: format '%d' expects argument of type 'int *', but argument 2 has type 'short int *' [-Werror=format=]
     scanf("%d",&dec_num);
             ^
cc1: all warnings being treated as errors
commented by (4.3k points)
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Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
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}
answered by (-498 points)
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Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
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answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
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}
answered by (-498 points)
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prog.c: In function 'main':
prog.c:8:5: error: this 'if' clause does not guard... [-Werror=misleading-indentation]
     if (a<256)
     ^~
prog.c:10:9: note: ...this statement, but the latter is misleadingly indented as if it is guarded by the 'if'
         c=(a/2)%2;
         ^
cc1: all warnings being treated as errors
commented by (4.3k points)
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