10-19 Exercise 2: Convert decimal to binary number

Question

Write a program to convert a decimal number (<256) to binary. Use +-*/% operations only. Loops are not permitted

寫一個把十進位轉換成二進位數的程式。請使用 +-*/% 運算子，不允許使用迴圈。

Example input:

50

Example output:

110010

 

Answer 1

Hidden content!
#include<stdio.h>
int main()
{
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**** * *   ** * *****   * **    * *  **   **  ** *  
    }
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
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    }
*   * * ** * *     *  **     ** *     *  ** **   *
}

Comments

prog.c: In function 'main':
prog.c:4:21: error: unused variable 'result' [-Werror=unused-variable]
     int a,b,c=1,d=0,result;
                     ^~~~~~
cc1: all warnings being treated as errors

Answer 3

Hidden content!
#include <stdio.h>
int main()
{
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    if
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        *  ****    * *  * *   * * 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
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***  ******   *** *  * *** ** * ****      ** ** *    **
*****    ** **   *  *  * * **  (a>0&&a<256)
    {   b=a%2;
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* * *   *   *** *  * *     * * *  *** * * *** * * ** ** * ****   *
***** * * * **  **  ** * *****   0;
}

Comments

prog.c: In function 'main':
prog.c:17:12: error: too many arguments for format [-Werror=format-extra-args]
     printf("%d%d%d%d%d%d",h,g,f,e,d,c,b);
            ^~~~~~~~~~~~~~
cc1: all warnings being treated as errors

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int dec_num=0;
int bin_digit[8]={0,0,0,0,0,0,0,0};
int bin_num=0;
int main()
{
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**  * *  *  *      * ******      * * = dec_num/2;

* ****** *** * * * **** * ** * *     **  = dec_num%2;
*** * ** **  *   ***  **** * *  * = dec_num/2;

***  ***  *** * *    **  *  **  *  = dec_num%2;
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*** ** *     * *    *****   = dec_num/2;

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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>
short dec_num=0;
int * *  **  *   ** **  * 
int bin_num=0;
int main()
{
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*   * *  * ** *  ***   **** ** *****  * = dec_num%2;
**  ** * *   ***** ***   * *** = dec_num/2;

 * **  *   * * ** * * ***  **** = dec_num%2;
   *   * *** *   ** *  *** ***    = dec_num/2;

       ***  *    **  ** ** * *****  = dec_num%2;
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*   *  *  **** * * *   * ****   = dec_num/2;

   * ** * * *  *    * *   *** = dec_num%2;
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****  ****   * ** ****  ** ** *****   = dec_num%2;
****   **  * *** ** * **  * = dec_num/2;

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*   ** *   ** * * * *  * * * *   * = dec_num/2;

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** *   * *   *  *** * * ***          = dec_num/2;

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**  ****  *** * *   *** **  *  0;
}

Comments

prog.c: In function 'main':
prog.c:8:13: error: format '%d' expects argument of type 'int *', but argument 2 has type 'short int *' [-Werror=format=]
     scanf("%d",&dec_num);
             ^
cc1: all warnings being treated as errors

Answer 7

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** ** *** **   ** *   **** *  a,b,c,d,e,f,g;
*      *     ****  ** * * **** * ** *  * * **    * *  * 
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**** *  **    ** *   **** ** * *  * 0;}
*   *    * * ***   **   **  ** **** * *     *** ** * *  * ***
  * ** **  ** * **** ***    **   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output

Answer 8

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* ***     *******  *   ** ***  **  * a,b,c,d,e,f,g;
* *     **** ** ****    **  **** *  **** * * *  
  *  * *   *** ** **      (a<256)
    {   b=a%2;
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*     ** * ****   *    *** * *  * *  *** ** *     *  ***** 
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   * *  * * ****   *  *    ** ***      * **   *  *** ** ********   ***
** ****   ***** *  **  *    ** *   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
 *   ** * **  * ***    * a,b,c,d,e,f,g;
 *   *  **** * ****  *    *** *** ** ** **  ***    *    **
    if (a<256)
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** * * ******    * ** * * * **  * * * ****     * *** *   **    *   *
*    *      *   ****  ** ***  **  ***   ** ** **** * **   
 *   *  ** *    ** ****  *     ** 0;
}

Comments

prog.c: In function 'main':
prog.c:8:5: error: this 'if' clause does not guard... [-Werror=misleading-indentation]
     if (a<256)
     ^~
prog.c:10:9: note: ...this statement, but the latter is misleadingly indented as if it is guarded by the 'if'
         c=(a/2)%2;
         ^
cc1: all warnings being treated as errors