3 like 0 dislike
18.1k views

Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%
[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 25730 - Available when: Unlimited - Due to: Unlimited

edited by | 18.1k views

86 Answers

0 like 0 dislike
Hidden content!
* ** **** ***
int main()
{
* * **** * ** ** ** * ** a,b,c,d;
* ********* * **** ** ** * *** **** ** *** **** * ******* *
* *** * *** * ** **** ** * * *** Ratio: * * ** ** * ** *
** * *** * ** * * ** * * Ratio: %g%%",100*(b/(a+b)));
** ** * * * * * 0;
}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
             ^
prog.c:5:15: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
               ^
0 like 0 dislike
Hidden content!
#include *** *** * *
int main()
{
***** * * * **** * * * * ** a, b, ans, sr, fr;

** * *** * * ** ******* * * ** ** * * &a, &b);

* * **** *** ** * * **
* * ** *** *** ** * *** *
** * * * * ***** ** * * * * ***

* ** *** * **** * * ** * **** * * Ratio: ** * ** sr);
* * **** ** * * ** * ** ** * * * ** ** Ratio: * * *** * fr);
*** ** ****** * * * 0;
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include **** ** ***
int main()
{
* * ** *** ** * ** **** ** a, b, ans, sr, fr;

** * * ** ***** ** * ** ** * ** * &a, &b);

* ** * *** * * * * ** *** *
* * ******* * * ** ** *
* ** *** ** * * *** * * *** * *** * *

******* * ** *** *** *** *** Ratio: ***** * sr);
***** ****** * * * ** **** ** ** *** *** Ratio: ** fr);
* **** * ** * * ** * **** 0;
}
answered by (-168 points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d %d", &a, &b);
             ^
prog.c:6:16: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d %d", &a, &b);
                ^
0 like 0 dislike
Hidden content!
* **** * * * *
int *

{

int a,b;
* c;
* * *

** * *
** *** ***

*** * * * * * ** * ** ** * *
**
** ** * 100;
* ** - good;

* * ** ******* ** * **** c)
* * * * ** *** d)*/

** **** * * * ** * * ** **
* * * ** * * *** * ** **


}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include ** **** ** **
int main ()
{

***** * * *** * ** * pass, fail;
* ** * * * * * * * ** ** ** *** * ***
* * * ** * ** *** ** * ***** ****** &pass, **** *

* * * ** * * * * *** * * = *** * **** *** ;
** * * ***** * * ** * * ** = * ** * * **
* * * * ** *** **** * * ** *** Ratio: *** **** * * passratio);

*** * ***** ** *** ** * * * * * Ratio: * * * **** *** ** failratio);

**** * *** *** 0;




}
answered by (-167 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include **** * * * *
int main ()
{

* * * **** * ** pass, fail;
** ** * **** **** ** *** * *
* ** ** *** ** * ** ** * *** * *** * **** &pass, * *** ** *

*** ** *** ** ** * ** * * ** *** = * *** ** ** * ;
* * *** * **** ** *** * * = * * * ** *
* * ** * ** ***** * * * ***** * Ratio: *** * * ** * passratio);

* ** *** ** * * ** * *** * * ** ** * Ratio: * *** * failratio);

**** ** ** ** ** 0;




}
answered by (-167 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include * ** * * *

int main() {
* ** *** * * * * ****
* * * * ** * n1,n2;
* ********* * *** * * **** * tot=0;
*** ******* * ** * * * pass,fail;
* * * * ** * * ** ** * *
** * * ** ** ** * * * ***** ****** &n1, &n2);
** **** ** ** ** * * **
* * * ** * ** *** * = n1+n2;
* * * ****** * * = ((n1*100)/tot);
* * ** ** ** *
*** ***** ** * ** ** = ((n2*100)/tot);
**** *** * ** ** * *
** ** ****** * ** *** * * * *** * * Ratio: ** ** * pass);
* ** **** * * ** * ** *** * Ratio: %d%%", fail);
* ** ** ** ** * * ** *
***** ** ****** ***** *
** *** * ** * * *** 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include * ** ***

int main() {
** * * * * * **
* * ** * ** * ** *** * * n1,n2;
* **** * * *** ** *** ***** tot=0;
** ** * * ** * * * ** pass,fail;
* *** * * * * ** * *
** ******* * *** ***** ** * * * * ** * ** * &n1, &n2);
* *** * * * * ** *****
* * * ** ** ** ** * * = n1+n2;
* ** ** * **** **** * = ((n1*100)/tot);
* * ** ** * * ***
* *** * * *** * ** ****** = ((n2*100)/tot);
** * * *** ** ****** *
** *** * ** ** * * * ** * * Ratio: * * * pass);
* * * * * * ** * ** **** * ** * Ratio: %d%%", fail);
****** * **** * ****
* ** * ** * ** *
** * ** * * * ** ***** **** 0;
}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
* * ** ** *** * * * ** pass;
* * * ** **** fail;
*** * * * *** * * ** * sum;
* * *** * * ** * avg1;
*** **** * * *** ** avg2;
***** * ** **
** * * * *** *** *** *
* * *** *** *** *
** ****** ** ** * * ** *** ** %d",&pass, &fail);
******** * * * ***** ****
***** *** * * * * * * *** * * *
* ** * ** * ** *** * * *****
* *** * *** ** * * ** * **
**** * **** ***
* ** *** ** *** * ********** * Ratio: %d%%\n",avg1);
** ** * ** *** ** **** *** Ratio: %d%%",avg2);
**** ** * ****** * **
* ***** ** **** ** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
**** ** ** * * ***

* **

{

int a,b;

*** * * * ** ***** * ** * * **
** *** * ** **** %d %% ** *** **** * *
* * * ** *** %d %% * * * * ** *
** 0;

}
answered by (-66 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.95
©2016-2026

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users