[Exercise 02] Simple Discriminant Calculation

Question

Please write a simple program that performs calculation and, shows its result equals to '10'

** There is no restriction as long as the result indicates 10 from its calculation **

** However, your codes should NOT be the same as the given example **

 

Example

#include <stdio.h>
int main(){

int a, b, c, d;

scanf ("%d %d %d", &a, &b, &c);

d = a + b * c;

printf ("%d", d);

return 0;
}

Input

2 2 4

Output

2 2 4
10

Suggestion

• Try to apply Addition, Subtraction, Multiplication, Division in your codes
• Be advised that 'Order of Operation' is crucial. The relative precedence levels of operators found in many C-style languages are as follows

Comments

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}
input 2 1 5 output 2 1 5 10

Answer 1

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Answer 2

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Answer 3

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Answer 4

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= a + b - c * d;


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Answer 5

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}

Answer 6

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Answer 7

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int *


a, b, c;


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** ** * *** * *** is = **** **


* * 0;

}

Answer 8

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* * *** ** * **** ** the ** *
** *** ** * * ** * * + %d * %d = * ** a, b, c, d);
* * **** * * * 0;
* ** 4 4 2 10

Comments

Good job

Answer 9

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d = a - b / c;
* * *** the *
* * ***** ** ** * * * *
** * ** * 0;

}


*


* 8 2


*


8 2



10

Comments

Nicely done, keep up.

Answer 10

Hidden content!
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* a, b, c;
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c = a + b;
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**** ** *** + %d = * * * **
* * *

* *
7
*** *
* ****
* 7
10

Comments

Nicely done