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子字串

請設計一個程式,使用者會輸入兩個字串,兩個字串間用一個空格隔開,每個字串的內容只會包含大小寫的英文字母,請判斷第二個字串是否出現在第一個字串內。請將大小寫視為同一個字。

輸入範例1:

friEND end

輸出範例1:

There is "end" in "friEND"

輸入範例2:

friEND friends

輸出範例2:

There are no "friends" in "friEND"
asked in 2016-1 程式設計(一)AD by (18k points) | 1.2k views

23 Answers

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Hidden content!
#include<stdlib.h>

#include<stdio.h>

#include<string.h>

#include<ctype.h>



int main()



{
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* * ** * * * * ** ch,xh;
*** * * * *** * * * a[100],c[100];
** * *** * * *** * ** ** b[100],d[100];
* *** ***** * * *
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* ** ***** **** * * *** * ** * * * * = ch;
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****** * ** * **** **** *
* * * * *** ** *****
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* ** *** ** ** *** * *
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** ** ** * ** * ** * *** ****** ****** * * are no \"%s\" in \"%s\"",d,c);
*** * ** * * * ** ** *

    
**** *** *** * **** * *** ** * * * ***
*** ** * * ** *** ***** * * * 0;

}
answered by (122 points)
0 like 0 dislike
Hidden content!
#include ** ** *** *

#include * ** ** * * *

#include ** * *

#include * ** * * *



int main(void){
** ****** ** * ******** * * * *** **
* * * ********** i = 0;

  
* * ***** * * ** **

  
** ** ** ** * ** ** * != '\0';i++)
* * *** * * * * * * *** * **** = tolower(c[i]);
* * * * ** ** = '\0';
** * * ** * ** *** * * * * ***
* ** * * **** ** * ** ** ** != '\0';i++)
*** * * * * * * ** **** * ** = tolower(cc[i]);
* ******** ******** * = '\0';
*** ** **
* * ** ****** * ** != NULL)
**** * * * ** ******** ** * ** *** * is * * *** * in * ****** * * * ** ***
*********** ** **
** * *** *** * * ** * * * ***** **** are no * * * * ** in ****** * * * ** * * * *
* ** * * ** ****
******** *
*** *** **** * * ******* **  
*** * **** * 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
#include * *** * **

#include * * * * **** *

#include ** * * *** *

#include * *** * **



int main(int argc, char *argv[])

{
* *** *** * * * **** * ** ***
* **** ******** *** i = 0;
** * *
* **** *** ** * ** * ******
* ** * * * *
** ******* **** ** != '\0';i++)
* **** * ** ****** *** * *** = tolower(c[i]);
* *** * *** ** **** != '\0';i++)
* ** ** *** * * ** ** **** * * * = tolower(cc[i]);
** * * **
* * * *** * * != NULL)
*** ** *** * * ** ** * * ** * ** * * is * * * **** ** in ******** * * **** ***** *
* ** * * *
* * * * * ***** *** ** * ** **** *** are no * ********** * *** in * * *** ** * * * * ***
* * ** ** *** * * * **

  
* * ** * *** * * * * *  
* ****** ***** * 0;

}
answered by (-216 points)
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