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子字串

請設計一個程式,使用者會輸入兩個字串,兩個字串間用一個空格隔開,每個字串的內容只會包含大小寫的英文字母,請判斷第二個字串是否出現在第一個字串內。請將大小寫視為同一個字。

輸入範例1:

friEND end

輸出範例1:

There is "end" in "friEND"

輸入範例2:

friEND friends

輸出範例2:

There are no "friends" in "friEND"
asked in 2016-1 程式設計(一)AD by (18k points) | 2.8k views

23 Answers

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Hidden content!
#include<stdlib.h>

#include<stdio.h>

#include<string.h>

#include<ctype.h>



int main()



{
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*** *** * * * * * * a[100],c[100];
*** ** * * * * * * ** * b[100],d[100];
* ******* * * ** ** *
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*** ** * * * ** *
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**** * ******** *** ** *
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* * **** ** ** * **** *** ** * * ** * * * * are no \"%s\" in \"%s\"",d,c);
** *** ** * * * * **

    
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**** ** ** ** * * * * ** * 0;

}
answered by (122 points)
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Hidden content!
#include * *** ****

#include * *** *** *

#include * ** *

#include ** ** ***



int main(void){
*** ** **** * * *** ** * ** *
*** ** ** i = 0;

  
* ***** * * ** * * *** * ***

  
* * ** * ** ** * * != '\0';i++)
***** *** * ** *** * ** * * * * ** = tolower(c[i]);
* * ** * * * * * = '\0';
*** ** **** * ** ** ** *
** * * * *** *** != '\0';i++)
* * * * * * ** **** ** *** = tolower(cc[i]);
** * * *** ** **** = '\0';
*** *****
** * ** ** * != NULL)
* * * * *** ****** * *** * ** is ** * ** ****** in * * * * ** ***** * * * * *
* ** ****
***** ** ** ***** ** ** * ******* * * ** are no * ***** ** * in * ** * * *** * * ** * *
** ** * * * *** ***** **
* * ****
* * ** **** * * ** * **  
* * *** 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
#include * *** ****

#include ** * ** *

#include * * ** * **

#include * ** * * *** **



int main(int argc, char *argv[])

{
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* *** **
* * ** * * ** * ** ** ** ** **
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****** * * **** != '\0';i++)
* * * ** * * *** * * ** *** = tolower(c[i]);
** * * * * ** **** != '\0';i++)
************* * *** * ** ** * * = tolower(cc[i]);
*** * *
* * *** * **** ****** * != NULL)
* ***** ** * ** ** * * ** **** ** *** * *** * ** is ***** * ** *** in * * * ***** * ** *** * *
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** ***** ** * * * *** * *** ** * ** **** are no * * ** * *** *** in ** *** ** * ** *** ** *
* * * ** * ******* **

  
* * * * ** ****** ** **  
***** * * ** 0;

}
answered by (-216 points)
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