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子字串

請設計一個程式,使用者會輸入兩個字串,兩個字串間用一個空格隔開,每個字串的內容只會包含大小寫的英文字母,請判斷第二個字串是否出現在第一個字串內。請將大小寫視為同一個字。

輸入範例1:

friEND end

輸出範例1:

There is "end" in "friEND"

輸入範例2:

friEND friends

輸出範例2:

There are no "friends" in "friEND"
asked in 2016-1 程式設計(一)AD by (18k points) | 2.4k views

23 Answers

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Hidden content!
#include<stdlib.h>

#include<stdio.h>

#include<string.h>

#include<ctype.h>



int main()



{
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* * ***** ** **** * ** * ch,xh;
*** *** *** * *** * * ** a[100],c[100];
** ** ******* * * * * b[100],d[100];
* * * *** *** ** * **
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* *** ** *** *** * * ** ** *** * ** ** *** **** = ch;
* **** *** * * ** ** ** * * **** *
* * ** ** ****** ** ***
** ** ** * ** * *
* *** ** *** * ****** = getchar()) !='\n') {
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** * ** * * * *** ** ** * * * ** ***** *** * * is \"%s\" in \"%s\"",d,c);
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* * * * * * **** ****

    
* ** ** **** ** ** *** * * * **
***** ** * * * * * **** *** * 0;

}
answered by (122 points)
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Hidden content!
#include * * * *

#include ** * *

#include ** * ** ** **

#include * *** *



int main(void){
** ** * * *** ** * ****** * ********
**** ** * * i = 0;

  
* ** * * * **** * *** *

  
** * * **** ***** * ** != '\0';i++)
**** * *** **** * ** * ********* * = tolower(c[i]);
*** ** * *** = '\0';
* * **** * * **** ** * ** * * **** **
** * * ** * != '\0';i++)
** * * *** * *** ** * * ** * ** = tolower(cc[i]);
* * * ** * **** = '\0';
** *****
** *** * ** * ** != NULL)
* * ** *** * ** ** * ******* * * ********* is ***** ** * *** ** in ** * * * * **** **** ***
* *** *****
* **** *** * ** * *** * * * * are no * *** ** * in * *** * ** *** **
* * * * **** * * * * *
* *** ****
**** ** * ** * *** * * ** *****  
* * * * * 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
#include ** * *** ***

#include * ******

#include * ** * * ***

#include * *** ** *



int main(int argc, char *argv[])

{
** ** * * ** * * * **
* * **** * i = 0;
* * ** * *
* ** * *** ** * *** ****** * * ****
** * ** ** *
***** * ** * ***** * * != '\0';i++)
* * * ** * ** * ***** * ** * * * ** = tolower(c[i]);
* ** *********** ** != '\0';i++)
** * * * * * * *** * ********** * = tolower(cc[i]);
*** **
* * * * * *** ** ** != NULL)
*** ** * ** * * * * * ** **** * * * ** * is * ** * in ** **** ** * * * *** *
* *** *** *
** * * * * * ****** * * * *** * are no ** ** *** * in ** * * ** * * *
* ** * * **** *** ** ***** * *

  
** * * *** **** *** *** ***  
* ** *** * 0;

}
answered by (-216 points)
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