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子字串

請設計一個程式,使用者會輸入兩個字串,兩個字串間用一個空格隔開,每個字串的內容只會包含大小寫的英文字母,請判斷第二個字串是否出現在第一個字串內。請將大小寫視為同一個字。

輸入範例1:

friEND end

輸出範例1:

There is "end" in "friEND"

輸入範例2:

friEND friends

輸出範例2:

There are no "friends" in "friEND"
asked in 2016-1 程式設計(一)AD by (18k points) | 3.2k views

23 Answers

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Hidden content!
#include<stdlib.h>

#include<stdio.h>

#include<string.h>

#include<ctype.h>



int main()



{
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* * *** * * *** ******* **** ch,xh;
** ** * ** a[100],c[100];
* ** * ** * ** * ** ** * b[100],d[100];
** ** * * * ** * *
******** * ** ** ** * * * ((ch = getchar()) != 32) {

* ** * * **** ** ** **** ***** *** * = ch;
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** *** *** ** *** ** * *
** ** * *** * **
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* **** ** ** * ** * ** ** ** *** ***** * ** * * * are no \"%s\" in \"%s\"",d,c);
** * ** ** * **** *

    
* *** * * *** * * **** * * * * ** ** *
** *** ****** *** 0;

}
answered by (122 points)
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Hidden content!
#include ** *** ***

#include ** ******* * *

#include * ** * *

#include * **** **



int main(void){
* * ** ** * * ** * ****
* * **** ***** i = 0;

  
* ** * * * ***** * ******* ***

  
* ***** ** ** * * ** * * ** * != '\0';i++)
* * **** ** * * * ** ** * * ** = tolower(c[i]);
* * *** ***** ** = '\0';
* ** ** * ** * ** * ** ** ** ***
*** * ** * != '\0';i++)
*** * **** ** * ** *** ***** * ** ** ** = tolower(cc[i]);
* *** * ** = '\0';
** ** ** *****
*** * **** *** * *** != NULL)
** ** * * * * *** ** ** *** * *** ** is * *** ** * in ** * *** * ** *
* * *** ** * *
*** * ** **** *** *** ** * * * ** * are no ** *** * * * in * * *** ** ***** ******
* ** * * * * * ***** ***
* *** **
* * ** ***** * *******  
* ****** * ** 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
#include ** * * ** * * *

#include * ** ** ** **

#include *** ** * *

#include * ** **



int main(int argc, char *argv[])

{
* ** **** * * * * * ******
* * ** * i = 0;
*** ** *
***** ** * * ** * *
** * * * *
* ** * *** ** * * != '\0';i++)
****** * * ** * * * **** * *** * = tolower(c[i]);
* **** **** *** * * ** ** ** != '\0';i++)
* ** * ** * * * * ** ** **** * * = tolower(cc[i]);
* * * ** * ***
* * * * * *** ** != NULL)
** ******* ** ***** ** * * *** * is * * * in * * * ** ***** * ***
****** ** * **
* ** * ****** * ** * ** * are no *** ** ******* ** in * ** * *** ** * ****
* ** **** ** *** * **** *** *

  
* * *** * * * * * ****  
** * * * * ** 0;

}
answered by (-216 points)
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