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子字串

請設計一個程式,使用者會輸入兩個字串,兩個字串間用一個空格隔開,每個字串的內容只會包含大小寫的英文字母,請判斷第二個字串是否出現在第一個字串內。請將大小寫視為同一個字。

輸入範例1:

friEND end

輸出範例1:

There is "end" in "friEND"

輸入範例2:

friEND friends

輸出範例2:

There are no "friends" in "friEND"
asked in 2016-1 程式設計(一)AD by (18k points) | 3.3k views

23 Answers

0 like 0 dislike
Hidden content!
#include<stdlib.h>

#include<stdio.h>

#include<string.h>

#include<ctype.h>



int main()



{
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* * * ** ** * **** ** **** *** ch,xh;
** * * ** ** ***** * a[100],c[100];
* * ** * *** * ** * ** b[100],d[100];
**** ** **** *
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* * ** *** * ** *
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* *** ** * * * * * ** ** ****** * * ** * * ** * ** * ** ** is \"%s\" in \"%s\"",d,c);
* *** ** * * ** * *
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*** * ** ** * * * **** * ** ** ** * * ****** ** * are no \"%s\" in \"%s\"",d,c);
**** ** **** * * * * *

    
* * ***** * ** * *** * *** ** ** **
* ** ** * * **** **** 0;

}
answered by (122 points)
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Hidden content!
#include *** * ** **

#include ** * **

#include * * ** ****

#include *** *** **** *



int main(void){
** *** * * ** * * *** *
* ** *** i = 0;

  
** ** * ** ** * ** * * *

  
** * ** * * *** ** *** != '\0';i++)
* ** * * *** *** ** * *** * * ** * = tolower(c[i]);
** * * * *** *** = '\0';
** ** **** *** **** * *** **** * * *
** ** * *** * *** * *** * **** * != '\0';i++)
* * *** * ** * * *** **** ** * = tolower(cc[i]);
** **** ** * = '\0';
** * * * **
*** * * * * ** ** != NULL)
* *** ** * **** * * * ** * * **** *** * is * * ** * * in * ** * ** **** ** * * *
* *** **
** ** * * *** * ** * ****** * * ** ***** * * are no ** **** * * in * ** ** * ** * * ** *
**** * *** * * *** *** * *
** * ** * *
** * *** * * * * * * ** *  
* * * ** 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
#include ****** * **** *

#include *** * * ***

#include * * * **

#include * * * * *



int main(int argc, char *argv[])

{
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* ** * *
* * ** *** *** * * *** **
*** * * * *
* **** * * ***** * * ** * != '\0';i++)
** * * ****** ** * *** * ****** = tolower(c[i]);
*** *** * * *** ** ** ** ** != '\0';i++)
* * * *** *** * * * **** *** * = tolower(cc[i]);
** ** *
* ** ** ******* ** ** != NULL)
* ** ** * * * * * ** * * *** * ***** is ***** * **** in * * *** * *** *
** * *
* * * *** * * * * * * ****** are no **** * * * in * * ** *** * * ***** * * *
** ****** * * *** *** * *** *

  
****** * * * * * * * ******  
***** * ***** *** ** 0;

}
answered by (-216 points)
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