0 like 0 dislike
4.5k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AD by (18k points)
ID: 18072 - Available when: Unlimited - Due to: Unlimited

reshown by | 4.5k views

96 Answers

0 like 0 dislike
Hidden content!
* * ** * ****
* * * * **
* * * ** **



int main()

{
* * **** ** * c;
****** ** a=1;
** **** * *
**** * *** **
****** * ** *** *** ** ***** * ***** &c);

* * **** ****** ***
** * * *** * ** ** ** != '.')
* * * ******
* ** * * ** *** ** * * * * *******
* ** **** * **** *** * * *** * ** **** ')
** * ********** * **** * *** *** * * * * *
* * ** ** *** ** * *** * *** ** ** * **** * ')
*** **** ** ** ** * * * ** * * *
* ** ** * ** ***** * * **** if(c=='! ')
** * ** * *** ** * * *** ***** ** * * ** *
**** * *** ** * ** ** ******* *


* **** * **
* * **** *
* ** * **** * * ** * * * ** ***** &c); ******* **** *****
* ***

  
* * ********
* **** ** ** * ** **

*** * * * * *** *

  
* ****** **** **** * * * * * , a);

  

  
** ** * ****** ******* ** * * * **
* ******* ** ** *
** ** *** ** *** 0;

  
* * * *** ***
** ****** ** * * * **

}











/*According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.*/
answered by (-186 points)
0 like 0 dislike
Hidden content!
* * * ** * **
* * ** * * * * *
* *** ***



int *

{

int i=0 , j=0 , k=0;

char c;
** *** * ** * , *** *
*** != '.')

{
** ***
** ** **
* ** = i + 1;
*** ** **
* * = j + 1;
******
*** *** * * * * ** * * *
* *** = k + 1;
****
* *

***


* ** *
** ***** * **** * , * * *** * * * * * * * ** ***** * *** *

}




** ** * *** * * , ***** *




** ** ****
*** 0;

}
answered by (-194 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

int main()

{
** ******* * * ****** c;
*** ** * * **** * ** ** N=0;
* *** * *** * * * **** * ** * * * ** *
* * * * * * * *** * != '.')
* * * * ********
** ** * ** ** ** **** ** *** * * * * * **** * * ')
** ** ** ** * * * ** ** * * * ** ***** * * *** * ** **
** *** * * **** ** *** * * * ** * *
**** * * ** * * ** *** * * ** * * *** * ** * * * *
** * **** * ** * **** * ** * * ** ** ** *** **** ** * **

    }
* * * ** ** *** * * *** * *** ** * * **** **
** * * * ****** *** *** ** ** **** **** * * *
** * ** * * ** * * * * * 0;

}
answered by (156 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>



int main()

{
* * *** ***** * *** c;
* * * ***** * ** * * * i=1;
** *** * ** ****** * ** ****** ** * * * * * *
* * ***** ** *** ** ** != '.')
* * **** * ** * * * ****
* * ** * * * * * * ****** *** ** ** * * * ** *** * *
* * **** *** ***** ** * * **** * **** * ***** ***
* * **** ** * ******* * * ** * * ** * * * * * * * ** * * ** **
* ** ** ** * * ** ** ** *
* * ** * *** ***** * * * * * * * * ***
* * ** ** * * ** **** * *** * *** * ** *
*** * ** * *** ** * * * * 0;

    

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
* * * ** *****
* **** *** **
**** *** * * * *



int main()

{
***** * **** * ** * c;
* * ** * *** ** a=1;
* * * ** * *
* **********
* *** * ** *** * ** ** * * &c);

*** ** * * * ***
* * ** * *** *** * != '.')
* * * *** * *
** ** ** ** ****** ****** *** * * **
** * * *** * *** **** ** * *** * ** ** * **
** ** *** **** *** * **** ** ** * ***
* ** * * ** * ***** ** * ** * **** *
* * * * *** * * * * * ** * ** * ** if(c==',')
* * * ** * ** * * * * * * *** * ** ****
** ** ** ** ** ****** * * ** * ** * if(c=='!')
** * ** *** * ** ***** * * *** *
* ** ***** ** **** * ** *** ***


***** ** * ***
* * * ** **
* * ******* * * * ** * * * * * * * *** * &c); * * * *** **** ******* ** *

  

  

  
** ** ** ** * **

* ****** * * ***
* * * * * * ***
** * * ***** ** * * * , a);
** ** ** * * *

  
* * * * * **** ** * * * ** **
* * * ** ** **
* * *** ** 0;
* **

  
* ** * * **

}











/*According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.*/
answered by (-186 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>



int main()



{
* *** * * * ***** * k=0;

    
** * ***** * ** * ** a;

    
* ***** * * ** **** *** ****

    

    {
*** * ** * * * **** * * ** * ** * *** * * ** * ** * *** *** * ** * ** ** * ** * ** * **** * * ** ** ** *
* ******* * ** ****** ** * ** ** *** * * ** ** ** * **** *** ****** * * * * * * ** * ** * ** *
** * ****** *** * * * * *** ** * * * * * *** *** ***** *** * ** * ** * * ***** ***** * * * *
** *** ***** *** * * ** * * ******** * ** ** ** * ****** ** * ** * *** ***** * ***** ** ** * * *** *
* ** *** * * ** * * * * * * * * * * * ** **** * *** ** *** * **** * * ***** ****** *****
*** * ** * * ** ** ** * ** * * *** * ** * * * * * ** *** ** * * ** * ******** **
*** * ** ** **** *** * ** * **** *** *********** * * *** ****** ** *** ** *** ** *** * if(a==' ')
* *** * ** * ** ** * *** * ** **** ** ***** *** * ** * * * **** * * ** * ****
** ***** ** ** * * ** * ** ** ** * * * ********* * ** ** ** * ***** * * ****** * *
***** ** * * ** * * * ** * **** *** ***** * * ***** ** *** ** **** **** ** * * *


** *** *** * * * **** * ** * *** *** * ** *** ***** * ** * * *** **** ** * ** *

    }

    
* * * * ***** ****** * ** *********

    
* ** **** * ** ** * * * ** **** ***

    
** * ** * * ** 0;

    

}
answered by (122 points)
0 like 0 dislike
Hidden content!
* * * * ** ****
*** ***** ** * **
*** *** ** * * ** ***



int ** *

{

int i=0 , j=0 , k=0;

char c;
* ** ****** * , *******
*** != '.')

{
**
* *** ** ** *
* ** = i + 1;
** * ** * ** *
* **** = j + 1;
* *
** ** ** * * * * * ** ** * ****
***** ** = k + 1;
* **


** *
* * *** ** ** , * * * ** ***** ** ** *** ** * ** **

}




* *** *** * , ** **




*** ****** ***** * * **
* * 0;

}
answered by (-194 points)
0 like 0 dislike
Hidden content!
** ** *** * * **
* ***** **** ***
****** ** * *** *** * ** *


*

{
i=0 , j=0 , **
*** c;
* * ** ** * , ** * *
* * != * *

{
* *
* *** * * **
* = i + 1;
* ** * * *** **** * **
*** = j + 1;
**** *
*** * * = i + j;
*** = k - 1;
****


* *
* * ** ** * * ** , * * ** ******* ** **** ***** * ** *

}




** *** ** * , k);




* *** * * *
* * 0;

}
answered by (-194 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* ** * * ** * * ** ** c;
* * * * * * * i=1,j=0,l=0,k;
*** ** ** ** * *** * * * * * * * * * * ****
* ** * **** * * *** *

    {
** * ** * ** ** ***** * *** **** ** ****** * * ')
******* * ** ** * **** ** ** * * *** * * *** *     
** * * ** * *** ** * * **** * ** * * *******
* **** * * ** * *** ** * ** ** * * ** * * *   
** * * * *** * * *** * *** * * * ** * * ** * * ***
* * ** * ** ** ** *** **** *** ** ** * * * **** * *
* * * * *** ** * * * * * * * * * ** ** ** ** * * * * * ** * * ** * ** * * *** ** ** **

   }  
* * * * * * * * *** *

** * * *** ***** **** * ** *** **
*** ** *** ** ** *** * * * * * ** ***** *
* * * * *** **** 0;

}
answered by (-284 points)
0 like 0 dislike
Hidden content!
** * * * * **
* * * * ***
* * ** ** *



int **

{

int i=0 , j=0 , k=0;
*** c;
* * ** *** * * , * *
* != '.')

{
*****
**** ** *
***** * = i + 1;
* ** * * ***
* ** = j + 1;
* * **


* *
* ** ** ** * ** , ******* * * ** * * **** *** * ** * * ** *** **

}




** *** *** , ** *




** ** ** ***
****** 0;

}
answered by (-194 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.30
©2016-2025

Related questions

0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 18074 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 652 views
0 like 0 dislike
13 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 18069 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1k views
0 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 18068 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.4k views
0 like 0 dislike
11 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 18065 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 18084 - Available when: Unlimited - Due to: Unlimited
| 7 views
12,783 questions
183,443 answers
172,219 comments
4,824 users