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請撰寫一個程式,使用者會輸入一行字元,換行字元代表輸入結束,請計算所有的輸入當中有多少個英文字母,多少個數字,以及多少個其他的字元,並依照範例的格數輸出。

Sampile input:

1234567890ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Sample output:

digit:10
alphabet:26
other:13
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 17667 - Available when: Unlimited - Due to: Unlimited

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Hidden content!
#include <stdio.h>

#include ** * * * ** *

#include <ctype.h>



int main()

{
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* ** ** ** *** * * 0;

}
answered by (-188 points)
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Hidden content!
#include <stdio.h>

#include * * * **

#include ***** * * **



int main()

{
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**** * ***** * * 0;

}
answered by (-188 points)
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Hidden content!
#include <stdio.h>

#include * * * ** **

#include <ctype.h>



int main()

{
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* * * ** *
**** ** * ** ** ** ** *** ** x, y, z);


**** * * *** ****** 0;

}
answered by (-188 points)
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Hidden content!
** ** ** * ** **
** * * * *** **
** ** * **** * ****

int main()



{
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}
answered by (-110 points)
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Hidden content!
*** ** **** *** * **
* **** ****** ***
* *********** * * *

int main()



{
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}
answered by (-110 points)
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Hidden content!
** * * * *** ***
** ** * * * * **
**** * *** ** * *

int main ( ** **
* ***
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**** * * * * * *

scanf ( * ** * * * *
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else {
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scanf ( ***** **** ** **** *
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* * * * ** ( *** *** * ** ***** * ,x);

printf ( * ** ** **** * * **
* * *** ** **** * ** *** **
**** * 0;

}
answered by (-304 points)
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Hidden content!
* *** * * * ***
** ******* *** * ***
* * **** ***

int main ( ******* *
* * *
** ** c ;
** * * ** * * ****

scanf ( *** * * ** * * * *
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x=x+1;
* * *

else if ( ** (c)){
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}

else {
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scanf ( *** ** ** * *** *
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**** ** ( * ** * ** * ** *
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printf ( * ** **** **** **
** * ***** ** * *
* * * * * 0;

}
answered by (-304 points)
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Hidden content!
* *** * * * * *
* *** * * ****
* *** * * *****

int main()



{
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** ** ** * **** ** * * a=0, b=0, d=0;
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* ** ** ** * **** ("pause");
*** ** * ** *** 0;

}
answered by (-110 points)
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Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

int main()

{

    int a=0,b=0,i=-1;
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* * * ***** * * ** * (c!='\n')

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}
answered by (-188 points)
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Hidden content!
** ** * * ***
** * * * * *** *
** * *** ** * *

int main (  )
** * *
** * c ;
** ** ** * ** ****


* * * (c !='\n')  {
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}

else ******* *
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printf ( ** * ** *** *****
**** * ** * ** * * ***
**** * * 0;

}
answered by (-304 points)
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