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請撰寫一個程式,使用者會輸入一行字元,換行字元代表輸入結束,請計算所有的輸入當中有多少個英文字母,多少個數字,以及多少個其他的字元,並依照範例的格數輸出。

Sampile input:

1234567890ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Sample output:

digit:10
alphabet:26
other:13
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 17667 - Available when: Unlimited - Due to: Unlimited

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#include <stdio.h>

#include ** * * ** * * *

#include <ctype.h>



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{
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* * *** ** ** * * ** 0;

}
answered by (-188 points)
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Hidden content!
#include <stdio.h>

#include *** * * *

#include *** ** *



int main()

{
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*** *** **** ** ** * 0;

}
answered by (-188 points)
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Hidden content!
#include <stdio.h>

#include ** **** * *

#include <ctype.h>



int main()

{
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** * ****** * *** 0;

}
answered by (-188 points)
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Hidden content!
* * ** * **
* ** ****** * * **
** *** * ***** *****

int main()



{
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}
answered by (-110 points)
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Hidden content!
** ** * ** * * **
* ** ** * * ** ** *
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int main()



{
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}
answered by (-110 points)
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Hidden content!
* * * *** ***
* ** * * ****** *
* ** **** *** * * * **

int main ( **
* * * *
* * * * c ;
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scanf ( **** ******* * **** *
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}

else {
* ** * *
*

scanf ( * ** ** ** * *
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* **** *** ( * * * **** * ,x);

printf ( * *** *** ** ** *
***** * * ** *
** 0;

}
answered by (-304 points)
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Hidden content!
**** *** ** * *
*** ** ** *** *** * *
* **** *** *** *

int main ( **
* ** *
*** ** c ;
* * * ** * * ****

scanf ( **** **** * * ** * **
* * * (c !='\n') * * * *



if ( isalpha (c))
** *** *

x=x+1;
***** *

else if ( * (c)){
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}

else {
* * **** *
*******

scanf ( * ******** * * ** ***
*****
** ****** ( * * * * * *** ***
* ** ( *** *** **** * * ,x);

printf ( **** * ** *
* *** ** * * ** ** *
* * * * 0;

}
answered by (-304 points)
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Hidden content!
*** ** * *
** * ** *** * *
* ****** ** ** *

int main()



{
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*** ******* * * * ** a=0, b=0, d=0;
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***** *** ***
* ** * ** * * **
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}
answered by (-110 points)
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Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

int main()

{

    int a=0,b=0,i=-1;
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* ** * * ** ** ** * (c!='\n')

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}
answered by (-188 points)
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Hidden content!
* * *** * *** **
* ** * *** ** *
* * * **** ** *****

int main (  )
*** *
* ** c ;
** * ** * * * ** * * **


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}

else * * * *** *
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* * ** * * ( * * * ** * * ****** ,x);

printf ( ** * * **** **
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* * * 0;

}
answered by (-304 points)
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