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AD 20161103 作業1
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請設計一程式，使用者輸入一個正整數N，程式會輸出相對應的費氏數列第N項。
sample input:
10
sample output:
55
[Exercise]
Coding (C)
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asked
Nov 3, 2016
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Shun-Po
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ID: 16957 -
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Hidden content!#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main(void) {
* ** * * ** * * * * *** * a[99],i,x;
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* * * * ** * * ** ** * * EXIT_SUCCESS;
}
answered
Dec 2, 2016
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410421238
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int Fibonacci(int n);
int main()
{
* * ** ** * ** * * ** * i,n,f;
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}
int Fibonacci(int n)
{
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* * ** *** * * ** * ** * * * f;
}
answered
Dec 1, 2016
by
610537002
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Hidden content! * * ** * * * *
long * * * n)
{
**** ** * * * a1=0, a2=1, a3=1, i;
**** * * ** * * * 1;
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}
void main()
{
* * * * * n;
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}
answered
Nov 7, 2016
by
lovekakoda
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int fibona(int number);
int main()
{ int num,fib;
* ** * * ** *
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}
int fibona(int number)
{
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}
answered
Nov 3, 2016
by
goodboy110222
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int fibric(int n)
{
int last2=1,last1=1,f=0,i;
* * * *** *
* * * * * ** * 0;
if(n==1||n==2)
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else
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int main()
{
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}
answered
Nov 3, 2016
by
410223039
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Hidden content! ** ** ** ** * *** * *** *
int fun(int num){
int n;
* * ** **** * ** || n==2)
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else{
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}
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**** * * *** ** * * ***
** * * ** * * * * * * ** ** 0;
}
answered
Nov 3, 2016
by
爾皓
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int ffff(int num)
{
** *** ** ** ** * * * *** num1=1,num2=1,b,c=0;
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{
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answered
Nov 3, 2016
by
andreas lu
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Hidden content!#include<stdio.h>
#include<stdlib.h>
#include<math.h>
int main()
{
* ** * ** ** * ** *** * * * * ** ** * * i , a ;
* * ** * * ** ** *** * * ** s[100]={0};
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** ** * * * * * * *** * * * * *** *** 0;
}
answered
Nov 3, 2016
by
410223045
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Hidden content!#include<stdio.h>
#include<stdlib.h>
void A(int j)
{
*** ** * *** *** ** * ** A[j],i;
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}
int main()
{
int i;
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* *** * * * ** * * * * ** ** 0;
}
answered
Nov 3, 2016
by
楊傑宇
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Hidden content!#include<stdio.h>
#include<stdlib.h>
#include<math.h>
int main()
{
* * * * ** * * ** * * * * * ** i , a ;
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* * * * * * ** * * * * * * ** 0;
}
answered
Nov 3, 2016
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