1 like 0 dislike
2.2k views
請設計一個程式,由使用者輸入一個數,程式會找出其所有因數後由小到大輸出。

sample input:

12

sample output

1 2 3 4 6 12
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15446 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

reshown by | 2.2k views

37 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include * * * * *** *



int main()

{
** * *** * **** *** ** * * j,n,k,g=0;


* **** * * ** *** * * **** * ** ** ** *** ** **
*** * ** * ** * ** ****** num[j-1];
** * ** ** ** ** *** *** * * * *
* ******** ** *** * ** * **** **** * * **** ** * (0==j%n)
** ** * * * ** * * **** * ****
*** **** * * * * ***
* *** ** * ** * ** **** ** * * *
* * *** *** * ***


****** ** ** * ** **


** * ** *** * * *





 return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include ** * * **



int main()

{
**** ** ** * * * * * * j,n,k,g=0;


** ** * * * ** ** **** * ** * ********* * * * * ***
** ** * *** *** num[j-1];
* * * *** * ** * * * * * * *
* * **** * * * ** ** ** * * * * ** * ****** * (0==j%n)
* *** * ** * *** ****
* ** * ****** *** * **
******* *** * ** ** * *** * *
* ***** *** *** * * **
*** * * * *** ** ** *** * * * *** ** * * *

printf(" ");
* ** ***** * ** * * ** *


** * *** *** ***





 return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include *** * * * *

using *** * * std;






* * * * main()
*** *


* * * ** *** *** *** * n;
* *** ** * * * ** * * ** ** * **** * ***** n;
* * *** **** * * ** ******* * (int i = 1;i * ** n; i++)
** *** * * * *** * int j = i;j * *** i;j++
* *** **** * *** ** ** ** ** ** '*';
** *** * ** * * * * ** * ***** ** * ** * '\n';


* ** ******* *** ***












* ** *** *** * * **** *** * * *** **** ** ** **** * 0;

}
answered by (-98 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include ** * * * **



int main()

{
* * ****** * ** ** * * j,n,k,g=0;


** * * * *** ** *** * *** ******* ***** *
**** ** * * ** *** ** * **** * num[j-1];
** * * * * **** * * * * *** * ** ******
** ** * ** * ** * ***** * *** * *** * **** * * (0==j%n)
* * * ** * * * * ** * *
*** ****** ** * *** * ***
* * * * * * * * * * * * ** *
* * ** ******* **
* ** ********** **** * **** * **** * * * * *** * **

printf(" ");
* ***** ** *** * * ***


** * **** **** *





 return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include ** * * *

#include * ** * *** **



int main()

{
*** * * * * ****** j,n,k,g=0;


** * ** ** * ** ***** * * *** ****
****** **** ** * * * * * ** num[j-1];
* ** * * * ****** * * *
* * * * ** * ****** * * ** **** * (0==j%n)
** ** ** * ** * * *** **
** * ********* * * * * * ** ***
** * * *** ** * * ** *
** ** ** * ***



printf(" %d",num[k]);


** ** ** * ** ****** **





 return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * ** *** ** *

#include **** ** * *



int main()

{
***** * *** ** ** * *** j,n,k,g=0;


** ** *** ** * * ** *** **** * * *
** ** * * ** ** * *** ** num[j-1];
** * * ** ***** * ** ** *** ** **
** * ** * * *** * * * ***** * *** * * * (0==j%n)
* * * * * * *** * * * * *
* * *** **** **** * ** *
** * ****** *** * * * **** * **
* *** *** *** *** * ***


* ** * *** ** **


* * * * ***** **** *
** **** ****

printf(" ");

 return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include * * * * **



int main()

{
** ** *** * ** *** ***** * j,n,k,g=0;


* ** * ** ** * * *** * ** ** * * **
* ** * * ** *** ***** num[j-1];
**** * * * * * * **** ** ** ** * *
* * * * * * * ** ** ** * * * * ****** *** ** * (0==j%n)
** * **** ** * * * * ** ***
* * **** * * ** ** ** * *** *
** *** *** * ** ********** ** **
* * ** * * ***** *


**** ** * * *


**** * ** ***** * * **** * *



 return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include * ** *** ** **



int main()

{
* * * **** ** ** j,n,k,g=0;


** ** ** * * ****** * ** *** *****
** * * *** * * *** * num[j-1];
* * * * * ** * * * * * ** *
* * * * * * ** *** * * *** * * ***** * *** (0==j%n)
**** ******* ** * * ** **** * **
* ** * **** * * * * *
*** * * * * ******** *** *
** * * ** ** ** ** * **


* ** * **** ****** ***

if(k < g-1)
* **** * * *** * **** *** ");
* * * ***** ** ** * ** *



 return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include * * * ** **



int main()

{
*** * * ******* ** * *** j,n,k,g=0;


**** * ** * ** * ******* * * **** * ** * * * *
* ***** * * ** ** num[j-1];
** ** * * * ** * * *** * *** ***
* *** * * ** * * ***** * * * * * ** * *** * (0==j%n)
* * * ********* *** *****
** ** ** * ******
* * * *** ** *** * ** ** **
** * ** * *** ** * **


**** * **** ******** ** *

if(k!=g-1)
* * * * *** * * * * * *** ** * ");
** * ** * *** ** ***



 return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include * ***** ***



int main()

{
**** * ** * *** * ** *** * j,n,k,g=0;


* ** * * * ** * * * ** ********* * ** *** * ** **
** ***** * * * num[j-1];
*** ***** ** * * * ** * * * * *** *
** ** * * ** * * * * ** * * *** ***** * *** * ** (0==j%n)
** ** * * * * **** *
* **** * * * * ** ** *
**** * * *** *** ****** *** ***
* ***** * *** *** ** * *


* ** *** * * * *
* * * ** ****** **



 return 0;

}
answered by (-122 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.35.160
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15475 - Available when: Unlimited - Due to: Unlimited
| 13 views
0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15447 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 681 views
1 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15442 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.2k views
1 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15440 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.2k views
0 like 0 dislike
112 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15426 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 5.6k views
12,783 questions
183,443 answers
172,219 comments
4,824 users