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請設計一程式,從使用者輸入的正整數中找出中位數輸出。使用者輸入的第一個數字N代表接下來會有多少個數字會被輸入,程式會從接下來的N個數中找出中位數輸出。輸出時請注意小數點尾巴的零不要輸出。

sample input:

4

1 2 3 4

sample output

2.5
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15440 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

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18 Answers

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Hidden content!
* * * * ***** *



int main()

{
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* ** ** ** * *** sum, ava;


* ***** ** * ** ** * **** *** ** ** * ** &a);
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* ** * * * ** ********** ** * ** &math[i]);


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*** ** * ** * ** * * * ** * **** ** ** * * * ** * += math[i];
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*** * * **** ** ***** * *** * ** ** * **** * ** *** *** *


** *** * ** * *** *** ** ** ** **** **** * * 0;

}
answered by (-114 points)
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Hidden content!
#include <stdio.h>

int main()

{
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*** ** ** **** *** if(a%2!=0)
* ***** * * * * * * ** * * * * *** *** * * ****

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{
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    {    m=math[a/2];
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}

}
answered by (-124 points)
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Hidden content!
#include <stdio.h>

int main()

{
** *** * **** ** * a,i;
* ** *** * * ** * * * ** * ** *** *** ** ****
* * *** * * ** **** * ** * * m,j,k;


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}
answered by (-124 points)
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Hidden content!
#include * * * ** *

#include ** * * ** *

#include * * *

int main()

{
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* * *** * ** * * * * a;
** * ** * *** ** * *** ** * ** ** * ** **
* * * * * ** * b[a],i,j;




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* * * *** *** ** ** ** = c/a;


* ** ** * * * *** * * * * ** *
** ** * * * * **** * *** 0;

}
answered by (-136 points)
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Hidden content!
#include <stdio.h>



int main()

{
* *** *** * *** ** ****** N;
* * ** * ** ** *** * * * * *** * * ** * *
* * ** ** *** ** ** num[N],i;
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**** * ** *** * * ** * *
**** **** *** ** * * * ** *** * ** ** * * * ** * * ******* ** * ***
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* *** ***** * * * **
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* **** ****** *** * ** *
** *** * * **** * ** = sum / N;
* * ** * * ********* *** ** * *** * ** *



}
answered by (-162 points)
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Hidden content!
#include <stdio.h>



int main()

{
*** ********** *** ** * * N;
* ** ** ** ** * * * *** *** ***** * ** *
** * * ** ** * * * * *** num[N],i;
***** *** *** * ** ave,sum=0;
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** *** * * * **** ** ***
**** ** ** * * *** * * = sum / N;
* * ** *** * * * ** * ** * **



}
answered by (-162 points)
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Hidden content!
#include <stdio.h>

#include ** * * * * *

int main()

{
** *** * ** ** **** ** n,anynum,p,sum,ans;
**** ** *** * * * * ** * * ** * ** * ***


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** **** * *** * *
** * * * * **** * * ***** ** * ** * ** * **** * ** * * ***** * ** * ** *****
*** ** * ** **** * ******** * ** * += anynum;


****** **** * * * * *
* * ****** ** * ** ** * * = sum / n;
** * * **** * * ***** * *** ** * * * **


*** ** ** * ** ** ** 0;

}
answered by (-320 points)
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