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請設計一程式,從使用者輸入的數中找出中位數輸出。使用者輸入的第一個數字N代表接下來會有多少個數字會被輸入,程式會從接下來的N個數中找出中位數輸出。

sample input:

4

1 2 3 4

sample output

2.5
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AD by (18k points)
ID: 15439 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

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Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
*** * *** ** *** * * n = 4, i, j, c;
** * * * ** * k = 0, f;

   int num[n];
** ** ** * ** ** ** ** * * &n);
* ***** * * ** = 0;i <= n-1;i ++)
** * * *** ***** * * *** * ** ** ** * ** *** * *** &num[i]);
*** * * *** ***** *** = 0;i <= n-1;i ++)
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****** * ** ** ** ** ** * *** ** ** ** ****** > num[j])
***** **** * * ** ** * * ***** * ** ** ** *** * * ** * * *
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*** ** **** ** ** * ** *** ** ** ** * ** * * **** ** ** ** * ** * * * * = c;
* ** * * * * ** **** * *** * ****** * * * **** *** ** *** **
* * ** * ** * * ** * != 0)
** ** * * * ****** * ** ** * *** * * ** = n/2;
* ***** *** * * **** *** f = (n+1)/2;
* ** *** * * ** ** * = f-1;i <= f;i ++)
** * ****** **** * * *** ** * ** * ***
* *** **** *** ******* ** * * * * **** **** * * ** ** * * * **** ** * * = k + num[i];
*** ** ** * *** ****** ** ** ** **** ***
***** **** * **** * ** ****** = k/2;
* * ** ***** * * * * *** *** * ** *** k);


** ** ** * *** *** * ** 0;

 }
answered by (-188 points)
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Hidden content!
#include<stdio.h>
* * *** * * *** **



int main()

{
* * ** ****** ** * * ** i,j,k,l;
* *** * * * **
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** ** * * ** * *
** *** ***** * *** * ** *** n[i];
* *** * ** * * * *
**** **** *** ** * ** * = 0;k < i;k++)
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* * ** ** * *** *** **
* * * ** *** ** * * ** **** *
* ** * * * * * * *** * = 0;
***** * *** * **
** **** * * ** *** = 0;k < i;k++)
* * * ** ** *** * * * * ** = l + n[k];

   
** * ** * * * ** * * m;
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** * * * ** *** *** ***** * * * ****
* *** *** * ****** ***
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** * ** **** * ***** * 0;

}
answered by (-264 points)
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Hidden content!
#include<stdio.h>
* *** * ******** **



int main()

{
** ** * *** ****** **** i,j,k,l;
** * ** *** * *
* **** ** *** * ***** * * ** ** * ***


* * *** * ** *
** * ** ******* *** * n[i];
* *** *** * ** **** * *
* * ** * ** ** * * * * = 0;k < i;k++)
** * *** ** *** ** ** * * ** *** * * n[k]);
*** ** ** ** * ** * **
* * * * ** ****
* ** * ** *** = 0;
* ****** * *** * ***
*** ***** *** **** * ** = 0;k < i;k++)
* * * *** **** * ** = l + n[k];

   
* * * * *** ** * m;
** * * * * ** = l / i;

   
*** *** ** * * * **** * ** * * * ***** * **
* **** * * ** *** ***** *
*** ** * * ******** * * ** * * * **** ***** * *
* ** * ***** * **** ** * 0;

}
answered by (-264 points)
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