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請設計一程式,從使用者輸入的數中找出中位數輸出。使用者輸入的第一個數字N代表接下來會有多少個數字會被輸入,程式會從接下來的N個數中找出中位數輸出。

sample input:

4

1 2 3 4

sample output

2.5
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AD by (18k points)
ID: 15439 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

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Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
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* * * * * ** k = 0, f;

   int num[n];
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* ******** * *** * **** = 0;i <= n-1;i ++)
* * * * * ** * ****** *** *** * * * * * ***** &num[i]);
* ** * * = 0;i <= n-1;i ++)
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** * * * * * **** * *** * * * * * **** ** * ** * > num[j])
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*** * * * * *** * * **** * * * ******* * ** ** * ***** ***** * ** ** * * **** = c;
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* * * * * ***** * * **** != 0)
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* ***** ** ** * ** ** f = (n+1)/2;
* *** * * * ** * * **** * = f-1;i <= f;i ++)
*** ** **** *** ******** * ** * ******
** ** ** ** * * * *** ** * * * * * ** * **** * * *** * * * = k + num[i];
** * * * * * ** * ** * ** ***** *
**** * * ** * * * ** = k/2;
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* **** *** * ** * ** * ***** 0;

 }
answered by (-188 points)
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Hidden content!
#include<stdio.h>
** *** *** * *** *



int main()

{
* * * * * ** * *** i,j,k,l;
** * * ** * ** ** * *** ***
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* * * * *** * ** * *** n[i];
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* * ** ** *** **** * ** * * = 0;k < i;k++)
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* ******* * *******
** ** ** * * **
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** * * * * * * * = l + n[k];

   
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*** ** ****** ** ** * * = l / i;

   
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* ***** * *** * *****
** * * * **** ****
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}
answered by (-264 points)
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Hidden content!
#include<stdio.h>
* * *** ** *



int main()

{
*** * **** * * ** ** * i,j,k,l;
* *** **** * * *** * * **
*** **** * *** ** ***** * * ** ** * ** *


* **** * ***** ** ** *** * **
* ** ** * ** * ** n[i];
* **** * ** *** ** **
* * * ** ** * * * * ** * * = 0;k < i;k++)
* *** * *** * * ** ******** **** * ***** n[k]);
* **** ** * *** *** ***
* ** ** ** *** * * *
* * * * * * *** ** = 0;
******** **** **** *
**** *** * * ** ** ** = 0;k < i;k++)
*** * ** **** *** * *** = l + n[k];

   
* *** * ***** * ** ***** * *** m;
*** * *** * * * ** * = l / i;

   
** * ** ***** * * * * * * * * *** * ***** *
* * * * * * * *** *
* * ** ** * * *** * **** ******** * ** *** **
* ** * * * ** ** 0;

}
answered by (-264 points)
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