0 like 0 dislike
5.2k views
請設計一程式,從使用者輸入的數中找出中位數輸出。使用者輸入的第一個數字N代表接下來會有多少個數字會被輸入,程式會從接下來的N個數中找出中位數輸出。

sample input:

4

1 2 3 4

sample output

2.5
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AD by (18k points)
ID: 15439 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

reshown by | 5.2k views

73 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* ** * **** **** n = 4, i, j, c;
** * ** * * * k = 0, f;

   int num[n];
* * ** * * * * * * * * * &n);
** * * * ** = 0;i <= n-1;i ++)
** * ** * * ***** * * **** * * *** ** ** &num[i]);
***** *** * *** * * = 0;i <= n-1;i ++)
* * * * ** * *** * ** * = i+1;j <= n-1;j ++)
* ** **** **** * * ** * * ** * * * *** * *** *** > num[j])
** ** * ** *** * * *** ** ** * *** * ** ** ** *** ** * *** **** *
* * ** * * * * ** * * * ** * * * *** * * ** *** ** * ** ** * ** ****** *** ** *** ** = num[i];
* **** ** * * ****** **** ** ** *** ** * ** * ****** * **** * ***** ** * ** * ** ** = num[j];
** *** ** * ** * * * ** *** * * *** *** * * * ** ****** * * * * *** * = c;
*** ** * *** ****** ** **** ** ** ** ****** * ** ** * **
* ** ** ** ** ** * * ** * * ** * != 0)
**** ******* ***** * * *** * * *** * * = n/2;
* ** * ** * ***** *** ** f = (n+1)/2;
* * * * ** * *** * ** = f-1;i <= f;i ++)
** ** ** **** * ** * **** * * * *
* * ** ** *** * **** * *** **** * * * *** * ****** *** ****** ** = k + num[i];
** *** * ** * * * * ** ***** * ** ** * *
** * *** * **** * * * ** = k/2;
* *** * * * * * *** *** * * * * *** k);


*** ** **** * * ** **** 0;

 }
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * ** ** * **



int main()

{
****** ** *** ** **** * ***** ** * i,j,k,l;
*** ** * * ** * * * * *
***** * *** ** *** ** ** * * * ** * * *


* * **** ** * *
* * * * ***** ** *** * ** n[i];
* ** * ** * ******* * **
* *** ** * * ** ** **** = 0;k < i;k++)
* * ** * ** ** ** ** * *** * * ** *** **** n[k]);
** ** * ** *** ** *
* *** *** ** * *** ***
* * ***** ****** = 0;
* * ***** ** *** * * ** **
**** *** * * **** ** ***** = 0;k < i;k++)
* **** *** ** *** *** = l + n[k];

   
* ******** * * ** * m;
*** * * * * * ***** = l / i;

   
* ** ** * * * ** ** ** * *** **
*** * * *** ** * * **** ****
* * *** * *** ** *
* * ** *** ******** *** * ** 0;

}
answered by (-264 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * ** ** * * **



int main()

{
* * * * * ** * **** ** * i,j,k,l;
* *** ** * *** **
* *** ** * *** ** ** *** ** ** * ** * **** **


* * * * ** * * *** * *
** * * * * * ** * ** n[i];
*** * ** * * ** * *
** * **** * *** ** * * * ***** * = 0;k < i;k++)
** ** *** ** * * ** *** ** * *** n[k]);
* *** * ** ** ****
** * * **
* ***** **** *** *** * = 0;
* * *** ******
* *** * * * * ** *** = 0;k < i;k++)
** **** * *** * ** * * = l + n[k];

   
* * ** ** * ** ** ** m;
*** ***** * * * * * * = l / i;

   
* ***** * * *** ** ** ****** * *
** * **** * * * ** * *
* * ***** * *** **** ** * ** ** * ****
** *** ***** ** * * ** *** 0;

}
answered by (-264 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.132
©2016-2025

Related questions

0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15448 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 786 views
0 like 0 dislike
33 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15445 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 3k views
0 like 0 dislike
11 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15441 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.5k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15427 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 3.7k views
0 like 0 dislike
28 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15421 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 2.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users