0 like 0 dislike
9.3k views
請設計一程式,從使用者輸入的數中找出中位數輸出。使用者輸入的第一個數字N代表接下來會有多少個數字會被輸入,程式會從接下來的N個數中找出中位數輸出。

sample input:

4

1 2 3 4

sample output

2.5
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AD by (18k points)
ID: 15439 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

reshown by | 9.3k views

73 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
**** * *** *** * * n = 4, i, j, c;
** ** ** k = 0, f;

   int num[n];
* * ** ** *** ** ******* *** * * * &n);
* * * * * ** ** = 0;i <= n-1;i ++)
** * ****** ******* * ** * ** * ** * ***** * *** &num[i]);
** * * *** * = 0;i <= n-1;i ++)
** * * * ** *** * * ** * * * * **** = i+1;j <= n-1;j ++)
* ** * ** * * * ** ** ** * * ** ** * * ** *** ** * * > num[j])
* ** *** ** ***** * * *** * ** ** * * * * *** *** ***** **** * **
* * ** ****** * * * * **** ** * **** ** * ** *** *** ** * * **** * * * * = num[i];
* ***** * *** * ** * ** **** *** ** * *** ** * ** ** * ** ****** * *** ** **** ** * = num[j];
* *** *** *** ** **** * * * ** * ****** * * **** * *** **** * ***** * *** * = c;
* * ** *** * * * ** ******* * * * ** *** * * ** * *** * ** *
* **** **** ***** * != 0)
** ** ** ** * *** * ** *** * = n/2;
**** * ** * **** * * ** f = (n+1)/2;
* * * * **** *** * ** * = f-1;i <= f;i ++)
* * *** * * *** * **** * * * * *
** * ** **** * *** * ** *** *** * ******* * * * * ** *** ** * * *** * = k + num[i];
** ** ** ** * **** **** * *** * * ** *
* * *** * ** ** = k/2;
* * ***** *** ** * ** ** * * ** k);


* **** ***** ** * * * * 0;

 }
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* *** * * *** **



int main()

{
* * * ******** * * *** ** ** i,j,k,l;
** ** * * * * * * * *** **
* **** * ** ** ** * **** ** * * ** *** ** * **


** * *** * * **** ***
* * * * * ** ** ** n[i];
* ***** ** * ****
*** ** * **** * ** *** * * = 0;k < i;k++)
** ** * * *** *** *** * ** ** * * ** * ** *** n[k]);
* *** **** ** **
** * ** *** ****** ***
** * *** ** * * = 0;
* *** * **** ******
** * **** ****** * * * ** * = 0;k < i;k++)
** * ******* ** * *** * = l + n[k];

   
* * **** ** * **** ** m;
** * **** * ** **** = l / i;

   
* * * * **** * * * * * ** ** * * * *
** ** ** *** ** * * ***
* *** * ** ** * ** **
* * ** *** * * ** * 0;

}
answered by (-264 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
**** ** ** * ***



int main()

{
* * * * ** * * * * * * i,j,k,l;
* * ***** ** * * ***
**** *** *** *** ** ** * * ** * ** * ***


* ** * * * * ** ** * *
** * **** ** * ** ** ** ** ** n[i];
* ** ******** * * *
** ** ** * * * = 0;k < i;k++)
* ** ** * * ** * *** * * ** *** * ** ** * n[k]);
** ** ****** * * * *
* * *** * ** ** *** * *
* * * * *** ** ** * *** = 0;
* * * * ** * ** * *
* * * ** * **** * * * * * = 0;k < i;k++)
*** * **** * ** = l + n[k];

   
** * * *** ** ** *** m;
** * * ********** **** * = l / i;

   
*** * * * *********** ***** * ** * ** * *
*** ** * * **
* * ** * *** * ** ** **** *** ** ** * * *
*** * * ** *** ****** ** 0;

}
answered by (-264 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.65
©2016-2026

Related questions

0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15448 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.4k views
0 like 0 dislike
33 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15445 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 5.1k views
0 like 0 dislike
11 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15441 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 2.8k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15427 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 6.2k views
0 like 0 dislike
28 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15421 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 4.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users