Toggle navigation
Courses
Questions
Tags
Users
AC 20161013 作業 3
0
like
0
dislike
4.8k
views
請設計一個程式,利用迴圈輸出文字金字塔。
p.s. 輸入皆為奇數,且不大於20
範例輸入1:
5
範例輸出1:
*
***
*****
輸入範例2:
7
輸出範例2:
*
***
*****
*******
[Exercise]
Coding (C)
-
asked
Oct 13, 2016
in
作業
by
Shun-Po
(
18k
points)
ID: 13736 -
Available when:
Unlimited
-
Due to:
Unlimited
1
flag
|
4.8k
views
comment
0
0
Called for Help
0
0
Called for Help
0
0
Called for Help
0
0
Called for Help
0
0
Called for Help
Please
log in
or
register
to add a comment.
61
Answers
0
like
0
dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
* * * **** * * n,j,k;
** ******* ** * * *** * ******** * * *
* ** * * *** *** **** ** * *****
** * ****** * * * *
** ** * ** * * ** ** ** *** * ** * **** **** * ** * *
** * * ** ** * * * * * ** * ******** *** *** * ******* * * **** ** * ");
* ** * *** * * * ****** * *** ** * **** *** * * * * * * * * ** *
**** * * *** * * ** ** * * ** * * * * * ** ** * * ****** ** * *****
* *** * *** * * * **** ***** ** *** ***** * * ** * **** * *** *
}
* *** ** ** *** ***** **** 0;
}
answered
Oct 13, 2016
by
Jim870729
(
-102
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!
** * ********* *
*** * * * *
int main()
{
*** * *** *** * * n, j, k;
*** *** * *** **** *** * * ** * &n);
* * * * * *** *** ** *** = 1; j<= n / 2 + 1; j++)
**** *** * ** *
* * *** * * ** * ** * * * *** ** * *** = 0; k < n / 2 + 1 - j; k++)
******* *** * *** ** * **** ** * * ****** *** * ***** ***** * * ** *** ");
** * **** *** ********* * * * ** ** ******* * *** ** ** = 0; k < (j - 1) * 2 + 1; k++)
** * ** ** *** ***** ** * * * * *** *** ** * **** ***** ********** * ***
*** **** *** * ** * ** * *** * * * **** *** *** * *** * ** *** * **
** * * * ******** * *
return 0;
}
answered
Oct 13, 2016
by
410342026
(
-105
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!
**** * * * ** * **
** * * * *
* * **
{
*** * **
***** * * * ** *** * **
* ** / 2 + *
*
* * * * / 2 + 1 - * * *
* * *** ** ***
* ** - 1) * 2 + * *
** * *** * * * * * * ** ***** *** ***
*
** *
}
answered
Oct 13, 2016
by
410523022
(
-276
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!
#include * **** ****
int main()
{
* *** ***** * ********** ** ** n,j,k;
** * * ** ***** * * * * * ****
** *** * ** * * * * * = 1; j <= n / 2 + 1; j++)
* * * * ***** **
* * ** * ** ** * * * = 0;k < n / 2 +1 - j ; k++)
*** *** ** *** ** ** * * * * * * *** ** ** ** ****** * ");
** *** ** * ** * ** = 0;k < (j - 1) * 2 + 1;k++)
* ***** * * *** *** * * * ** ** ** *** * * * *** ** *
* * ***** * * * * * * * ** * **** ** ** *** * * **** ***
* * * * **** *******
*** * **** * * *** * 0;
}
answered
Oct 13, 2016
by
loyfree0706
(
-216
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main()
{
* * ** ***** ** * * num1= 0,i=1 ,j ,k,u=0;
* * **** * * * ** * *** * * * ***
if( 1== num1%2 )
{
*** ** *** ** * (i<=num1)
{
* * * * * *** *** * * ** * * * ** * ** * *** * ** ****
* * ** ** * * ** **** ** * ** * *****
* ** * ***** * ** * * * * * **** *** ** * * ** *** * * * * * **** ** ** *** ");
* * **** * *** * *** * * ***** ** * *
* * * **** * * * * ***** ** * * * ** * *** ****
** *** * * *** ** * * ******* ****
* **** * * ** ***** ** * ****** * * * **** **** ***** ** ***** ** *** *****
** * * * ** *** ** * * ** *
* * * ****** ** *** *** * * ** * ** * ** ** ***
****** ** * * * ** * * ** *** * *
**** * * *** * * * ** * * * ***** *
* ** * *** *
}
** ** * * ** ** *** * **** 0 ;
}
answered
Oct 13, 2016
by
Gulang
(
-122
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(void)
{
* * * *** * * * ** *** n,i,s;
** ** *** * ** ** *** *** ** *** **
**** ** ***** * * * ***** && n/2 != 0;
*** * ***** ******** * * *** * * ******* * * * *** * (i=1;i <= (n/2)+1;i++)
* * * ** *** * *** *
** ** ** * * ** * * * * ***** * * * * *** ** (s=0;s< n/2+1-i;s++)
*********** * * ** * * *** ** * * *** * *** ** * * * ** * * * * *** * * * * * * * ** ");
** **** ** *** * * ** *** *** ** ** *** * ****** * * * **
* ** ** * *** ** ***** *** ** * * *** *** * ** *** * ** * * * * * * * *
*** *** * *** * ***** **** ** ** * * **** * * ** * * * ** * * * * *
** ** *** * ** ** ***** ** **
return 0;
}
answered
Oct 13, 2016
by
410523007
(
-157
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!
** ** ******** ***
int main()
{
int *
* ** * * ** **
** = *** * * * *
{
**** * * * /2 +1 -j ;k++)
*** * * * ** *
* * **** * ** - * * *
** * ** ** * * ****
* ** ******* * *
}
** ** 0;
}
answered
Oct 13, 2016
by
rickyliu
(
-50
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!
* **** * * * *
int main()
{
** * ** * ** * * ** n, j, k;
** * * * ** * , &n);
* ** * **** * = 1; j <= n / 2 + 1;j ++)
* ** * * **
** *** ** * ** * * * *** *** *** ** * * = 0;k < n / 2 + 1 - j;k ++)
* ******** * ** ** ** * ***** ****** * ** ** *** * ** * ");
* ** * * *** * *** *** * * ** * * < (j-1) * 2 + 1;k ++)
**** * * *** **** * * * * ** *** * * * * ** ** * **
* **** ** * ** ** ******** * * ** ** * ** ** * ** * ******
**** ** * * ****
** * ** **** * * * *** * * 0;
}
answered
Oct 13, 2016
by
410425045
(
-90
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main()
{
***** * * * * ***** * ** num1= 0,i=1 ,j ,k,u=0;
* *** * ** * * ** ****** * **
*** * ** ** * ** 1== num1%2 && num1<=20)
{
* **** * * ** ** ** (i<=num1)
{
* ** * * * ** *** ****** * * *** *** * **** **** ** * ** **
* ** ** * * * ** ****** *** ** *
*** * * * * *** ** *** * *** ** * * *** * ** * * * * * *** ** ");
* ***** ***** ** ** * * *** * *****
* **** * ** * * * ** * ** ** * * * *** * *** * ****
**** * ** ** ** ** * ***
* ** *** ** ** * *** * ****** ** * * * * ******* ** ** ** * *** * ** ** *
* * * * * * **** * * *** * *
* * *** ********** * * ****** ** * * * ***** ** *
* * * *** * ** *** *** * ** *** * * *
* * ** * * ** ** * *** * * *** **
*** * *** * ** * * * **
}
* ****** ** ** 0 ;
}
answered
Oct 13, 2016
by
Gulang
(
-122
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!
#include<stdio.h>
int main(void)
{
**** * ** ** ** * n,j,k;
** * * **** ** * *** ******* *
* ** * ***** * = 1;j <= n / 2+1;j ++)
** * *** *** *
** ** ******* ** ****** * * ** * = 0;k < n / 2 + 1 -j;k ++)
* * ** ** * ** * ***** ** * * *** * * * * ** * ");
* * ** * * * ** ** * *** ** * * * * ** * * = 0;k < (j - 1) * 2 + 1;k ++)
* * ** * ** * ******** * * **** * * *** * * *** * * ** * ** * * ** * * * ****
* *** * * ** ** ** **** * ***** ** ** * * ****** ** *** * ** * * *** * * * * *
*** * ** * * *
* **** ** *** ** * ** 0;
}
answered
Oct 13, 2016
by
蘇瑋朝
(
-8
points)
ask related question
comment
Please
log in
or
register
to add a comment.
Page:
« prev
1
2
3
4
5
6
7
next »
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English
中文
Tiếng Việt
IP:172.71.254.222
©2016-2025
Related questions
0
like
0
dislike
64
answers
AC 20161013 作業 4
[Exercise]
Coding (C)
-
asked
Oct 13, 2016
in
作業
by
Shun-Po
(
18k
points)
ID: 13763 -
Available when:
Unlimited
-
Due to:
Unlimited
|
4.5k
views
0
like
0
dislike
91
answers
AC 20161013 作業 2
[Exercise]
Coding (C)
-
asked
Oct 13, 2016
in
作業
by
Shun-Po
(
18k
points)
ID: 13617 -
Available when:
Unlimited
-
Due to:
Unlimited
|
6.5k
views
0
like
0
dislike
117
answers
AC 20161013 作業 1
[Exercise]
Coding (C)
-
asked
Oct 13, 2016
in
作業
by
Shun-Po
(
18k
points)
ID: 13581 -
Available when:
Unlimited
-
Due to:
Unlimited
|
7.3k
views
0
like
0
dislike
152
answers
AC 20161005 作業 3
[Exercise]
Coding (C)
-
asked
Oct 5, 2016
in
作業
by
Shun-Po
(
18k
points)
ID: 12295 -
Available when:
Unlimited
-
Due to:
Unlimited
|
9.6k
views
1
like
0
dislike
48
answers
AC 20161102 作業2
[Exercise]
Essay (Open question)
-
asked
Nov 2, 2016
in
作業
by
Shun-Po
(
18k
points)
ID: 16865 -
Available when:
Unlimited
-
Due to:
Unlimited
|
4.3k
views
12,783
questions
183,442
answers
172,219
comments
4,824
users