0 like 0 dislike
4.1k views
正三角形的面積公式是[4分之根號3乘a平方],請設計一個程式,讓使用者輸入正三角形的邊長,然後輸出正三角形的面積,輸出時請輸出並四捨五入到小數點後兩位。

範例輸入:

8

範例輸出:

21.71
[Normal] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 13422 - Available when: Unlimited - Due to: Unlimited
3 flags | 4.1k views
0 0
Called for Help

35 Answers

0 like 0 dislike
Hidden content!
** * ** **

#include * *** **

int main()

{


** * * *** * * *** ** A ,B;
** * * * ** * * * **** *
* ***** * ** = sqrt(3)/4*A*A;
* ** * * * * * **** * * * * ***



}
answered by (-82 points)
0 like 0 dislike
Hidden content!
* * * ***** * *
* ** *** * *** ***





int main (void)



{
***** * * **** int a,i;
** * * *** *

* * * * double *
* * *

** ** * ** scanf ** *** * ** * *
** ** * ***

* * ** b = *** *
* ** ** *****

* ** ** * * c = **
* * ** * * *

* * * * * ******* ***** **** ** *
* * *** * * * *

*** **** * * 0;
* ** * * *

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
#include * * * **** *

#include * ***

#include ****** *** *

int main()

{
*************** ** * ** * a;
*** ***** * * * * ** b;
* * * * * * * ** **** ** * * * * * &a);
** **** * * * * * *
*** **** * ** ***** **** ** * * ***** ** ** b);
** * ** **** * *** * 0;

}
answered by (-158 points)
0 like 0 dislike
Hidden content!
#include * * *
* * ** ******* *
* * ** **





int ** ** **
* * * ** * ** a,ans;
* *** *** * * *** ** * **** **
***** * *** * * * = sqrt(3) * 0.25 * a * a;
** * * * * *** ** * *** ans);


*** * ** *** * * **** * *** *** *

return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include *** ** *

#include **** ***

#include <math.h>





int main()
** *** **** * ***** ** *
* * * **** ** ** ****** ** ** ***** * * a=0,c=0;
** * **** * * * * **** * ** *** * * * * * * * ** ***** * * *
** ** * * * * *** * * *** * ** ** = ** * * *****
* **** * * ** ** * **** *** * * * ** ****** ** * *
* ** * * ** * *** **** * ** * * * * *** **** * 0;
** **** * *** * * * *
answered by (-216 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>





int main()
* * * * * * ** ** ** * *
* * * * * * * ** *** * *** * **** a=0,c=0;
**** ** ** ** * **** * * * ** ** ** **** * **
* * * * * *** ** * * ** * * * *** = ((sqrt(3.0)/4.0)*(a*a));
***** * ** ** * * *** *** * *** *** * *** * * * ** *** *** *
* * *** * ******* ***** * ****** ** * ** ** 0;
** * * * *** ** **** ** *
answered by (-216 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include * ** * ** **

#include <ctype.h>





int main()
* * * * * *** * * *
*** ** * **** ***** * ******* *** ** * * a,b,c;
*** **** * ** ** *** * ** ** * ** ***** * * ** **** * * *
* ** ** ** ** * * * * ** *** ** = sqrt(3.0);
* * ** ** ** ** * *** * * * ** ** * = ((b / 4.0) * (a * a));
* ** * *** * * **** ** ** * ** * **** * ***
* * * * ************ * * ** * * * * ** * *** 0;
** * *** ** * * *** *
answered by (-216 points)
0 like 0 dislike
Hidden content!
#include *** * ***** *

#include **** * * ** ** *

#include * * *****

int main()

{
**** *** * * * * ** * a,area;
* ** * *** * * * ** * **** *******
**** * * **** * * ** = sqrt(3) / 4 * a * a;
* ** ***** * * **** ** * ** *** **


******* * ** **** * 0;



}
answered by (-320 points)
0 like 0 dislike
Hidden content!
**** ** ** * * * *
* * * ******* **** **

int main()

{

int a = 0;
* * ** * ** ** ***
**** * * ****** * * *


*** 0;



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
* * * *******



int **

{
** ** * * ***** n, A;


* ** * * ** ** ** * ** * ** * **** , ** * * *
* ** ** * ***** *** = (1.732 * n * n) / 4;
** ** **** ******* * ** * **** * , A);



}
answered by (-90 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.80
©2016-2025

Related questions

0 like 0 dislike
43 answers
[Normal] Coding (C) - asked Oct 11, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 13025 - Available when: Unlimited - Due to: Unlimited
| 5.2k views
0 like 0 dislike
49 answers
[Normal] Coding (C) - asked Oct 11, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 13023 - Available when: Unlimited - Due to: Unlimited
| 6k views
0 like 0 dislike
39 answers
[Normal] Coding (C) - asked Oct 11, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 13020 - Available when: Unlimited - Due to: Unlimited
| 4.9k views
0 like 0 dislike
7 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15399 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users