0 like 0 dislike
4k views
正三角形的面積公式是[4分之根號3乘a平方],請設計一個程式,讓使用者輸入正三角形的邊長,然後輸出正三角形的面積,輸出時請輸出並四捨五入到小數點後兩位。

範例輸入:

8

範例輸出:

21.71
[Normal] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 13422 - Available when: Unlimited - Due to: Unlimited
3 flags | 4k views
0 0
Called for Help

35 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
****** *** * * *** ****

int main()

{
**** *** *** * ** * * a;
* * * * * * * * * ** A;
* * * *** * * * * **** *** ** * &a);
* ** *** ***** ** ** * ***** *
* ** ** ** ** * ** ** **** ** **** ** * *
***** ** * *** ** ** ***
** * ** ***** ** ** * * 0;
* * * ** * ** * * *

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
*** ****
** ** ** ** *





 int main ()

{
** * ** * * ** * *** a,b;
** *** ** * * * * * ** ** ** * &a);


*************** ** * ** * = sqrtf(3)/4*(a*a);


* * * * * ** *** ** ** ** **** * **


* * * * ***** * 0;

}
answered by (-383 points)
0 like 0 dislike
Hidden content!
*** * *** ** *****
* ** * * * * * * *



 main()

{
* ***** * *** * **


* *** ** *** * * *


* * * ** * *




****** * * * * * * ***** **

}
answered by (-383 points)
0 like 0 dislike
Hidden content!
* ******* *** * * * *
* * * ** ** *
* ** ****** **

int main()

{

float ** **
* * *** * * ***** * * *****

b =
** ** * * * * * * *






* ** * ** ** system *** ** ** * ****
** * ** *** * return 0;
***
answered by (-136 points)
0 like 0 dislike
Hidden content!
****** *** **** *
* ***** * * * *
* * ** * ***





int main(){


* * * * ******** i, a, j;
** ** ** ** * ** ** * ****** * ** * * *


* * *** ******* * * * * ** = sqrt(3) / 4;


**** ** *** *** ** ** * * = i * (a * a);


** **** * ** ** ** ** * ** *** ****** j);



return 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** * * ** * * *
*** ** **** **** **





 int main ()

{
* * ** * ** *** * ** * ** ****** a,b;
* ***** * ** ** * * *** * *** ** * *** * * &a);


* * *** ** *** * *** * * = sqrtf(3)/4*(a*a);


** * ** * * * * *** ** * * ** * * * * ** ****


**** ***** **** 0;

}
answered by (-143 points)
0 like 0 dislike
Hidden content!
** * **** * * *
** * ***** *** * *





 int main ()

{
**** * * * *** *** ** ** * a,b;
*** * * ***** ** **** * * * * ***** * * * &a);


****** ** * * ** ** * ** * = sqrt(3)/4*(a*a);


**** * * * ** **** * ** *** * * ** * **


* ** * ** ***** * 0;

}
answered by (-143 points)
0 like 0 dislike
Hidden content!
#include ** **** * * *

#include * * * *** *

#include * * ***



int main()

{
*** ** ** ** ** a;
**** * * ** * * **** *** * * ** * * * ** *
* * * ** ** ** * * **** *** *** * * * * *
* ****** **** *** * ** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{
*** * ** * ** * ** a;
****** ** ** ******** * * area;
*** ** * * **** * * *
* **** * * ** ** *** * * * * *** ******
*** * * ** * ***** **** * * ** *
** ** * * * * * ** * ** *** ** * ** *** *

 }
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include * *** ** **** *

#include <math.h>

int main()

{
** *** *** * *** * * ** ** a, b;
** * *** **** * **** *** * * *** ***** *
* * ** * * * ** * * *****
* ************* ** * * * * ** * * ** ******
** * * ** ****** * * **** ** **** *
* * * ** * **** 0;
*** * *** * ** *** ** **
answered by (-122 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.15
©2016-2025

Related questions

0 like 0 dislike
43 answers
[Normal] Coding (C) - asked Oct 11, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 13025 - Available when: Unlimited - Due to: Unlimited
| 5.2k views
0 like 0 dislike
49 answers
[Normal] Coding (C) - asked Oct 11, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 13023 - Available when: Unlimited - Due to: Unlimited
| 6k views
0 like 0 dislike
39 answers
[Normal] Coding (C) - asked Oct 11, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 13020 - Available when: Unlimited - Due to: Unlimited
| 4.8k views
0 like 0 dislike
7 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15399 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users