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AC 20161005 作業 1
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請設計一個程式當使用者輸入一個分數(介於0-100間)，程式會輸出相對應的等第
90-100 => A
80-89 => B
70-79 => C
60-69 => D
0-59 => F
輸入範例1
100
輸出範例1
A
輸入範例2
59
輸出範例2
F
[Exercise]
Coding (C)
-
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Oct 5, 2016
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Shun-Po
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
int i;
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if(i>=90)
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else
{
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}
return 0;
}
answered
Oct 5, 2016
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410211222
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int a = 0;
printf("請輸入成績");
scanf("%d",&a);
if(a>=90)
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else
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return 0
}
answered
Oct 5, 2016
by
SRFX
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Hidden content!#include <stdio.h>
main()
{
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}
answered
Oct 5, 2016
by
Doloa
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Hidden content!#include<stdio.h>
main()
{
int score=0;
* * ** * ** * * ** * * * *** ** * * * * *** **** * **
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}
answered
Oct 5, 2016
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Jim870729
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Hidden content!#include * * *** * **
main()
{
float a;
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}
answered
Oct 5, 2016
by
410523022
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Hidden content! * * ** * * *** * ** *
main()
{
** ** ** * ** * * ** ** grade;
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}
answered
Oct 5, 2016
by
410425044
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Hidden content!#include<stdio.h>
int main()
{
* * ** * * ** * * * * * grade;
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}
answered
Oct 5, 2016
by
410425045
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Hidden content!#include<stdio.h>
#include<stdlib.h>
main()
{
int a = 0;
printf("請輸入成績");
scanf("%d",&a);
if(a>=90)
* * * * * * * * * ** * ** * * * *
else
**** * ** * ** * ** ** * * * * * * * *** **** * * * * * * *** *
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* * * ** * * **** * * ** * ** * * * * * * * * * *** ** * * ** ** ** * * * ** * *** * ** ** **
}
answered
Oct 5, 2016
by
SRFX
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Hidden content!#include <stdio.h>
main()
{
* * ** * * ** * * number=0;
* ** * * * * * * * * ** * * * * * * &number);
** *** * * * * * * ** * *
*** * * ******* * * * * (number>=90)
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* * * * ** ** * ** if (number>=80)
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* * * **** * * *** * ** ** *** **** ** * * ** *
** ** ** * *
* * ** * * ** * * * * *** * ** * * ** *** *
}
answered
Oct 5, 2016
by
Doloa
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Hidden content!#include ** ** * ** *
#include * * * * **
main()
{
*** * * * ** * ** * * score;
* ** ** * * **** * * * * ** * * * ** * ****** *
* * ** * ** * * *** * * ** ** ** *** ** &score);
* ** * * * ** (score>=90)
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* **** ** ** * if(score>=70)
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* * ** **** * * *** * ** * * * * *
* ** ** * ** ** **** * if(score<60)
* * * **** * * * * ** * ** * * * * * * **
}
answered
Oct 5, 2016
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