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AC 20161005 作業 1
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請設計一個程式當使用者輸入一個分數(介於0-100間)，程式會輸出相對應的等第
90-100 => A
80-89 => B
70-79 => C
60-69 => D
0-59 => F
輸入範例1
100
輸出範例1
A
輸入範例2
59
輸出範例2
F
[Exercise]
Coding (C)
-
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Oct 5, 2016
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Shun-Po
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
int i;
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* *** * * * * * * * ** * * ** ** ** ** * * *
if(i>=90)
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else
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}
return 0;
}
answered
Oct 5, 2016
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410211222
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int a = 0;
printf("請輸入成績");
scanf("%d",&a);
if(a>=90)
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else
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return 0
}
answered
Oct 5, 2016
by
SRFX
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Hidden content!#include <stdio.h>
main()
{
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}
answered
Oct 5, 2016
by
Doloa
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Hidden content!#include<stdio.h>
main()
{
int score=0;
** * * * * ** * * * * ** * * * * * * * *
* * *** ** * * * * * * * * * * * **** *****
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}
answered
Oct 5, 2016
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Jim870729
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Hidden content!#include * * * **** **
main()
{
float a;
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else * * * * ** * * * **
}
answered
Oct 5, 2016
by
410523022
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Hidden content! * *** *** * *
main()
{
* ** ** * * * * grade;
* * * ** ** * * ** * * * * * * * * * * * * * * * ***
* * * ** *** *** * * * * *** &grade);
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}
answered
Oct 5, 2016
by
410425044
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Hidden content!#include<stdio.h>
int main()
{
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}
answered
Oct 5, 2016
by
410425045
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Hidden content!#include<stdio.h>
#include<stdlib.h>
main()
{
int a = 0;
printf("請輸入成績");
scanf("%d",&a);
if(a>=90)
* * * ** *** * * ** * ********* ** * * * * **
else
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}
answered
Oct 5, 2016
by
SRFX
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Hidden content!#include <stdio.h>
main()
{
* * * ** * * * ** * number=0;
***** **** *** * * * * ** * * ** ** *** * * &number);
* * * * **** ** * * ** ** *
* ** * * * * * **** (number>=90)
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* * * * * * ** * * ** ** ** ** * * ******
}
answered
Oct 5, 2016
by
Doloa
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Hidden content!#include * * ** * ** *
#include ** * * ** *
main()
{
* ** * *** * * * * score;
** * ** * * * * ** * * ** * * * **
* * * * ** ** ** * * * ** ** &score);
* * * ** ** * (score>=90)
* ** ** * * * ** * ** * **** * * * *
* * * ** ** * * * * * * * ** *
* * * * * * * * * ** ** * * * * *
** * ** *** * * if(score>=70)
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** * * * * * * * **** * * ** * * * * *
* ** * * * if(score<60)
* * ** * * * * * * * * ** * *
}
answered
Oct 5, 2016
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wilson0121
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