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AC 20161005 作業 1
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請設計一個程式當使用者輸入一個分數(介於0-100間)，程式會輸出相對應的等第
90-100 => A
80-89 => B
70-79 => C
60-69 => D
0-59 => F
輸入範例1
100
輸出範例1
A
輸入範例2
59
輸出範例2
F
[Exercise]
Coding (C)
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Oct 5, 2016
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Shun-Po
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ID: 12291 -
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Oct 5, 2016
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Hidden content! **** * * * ** * * * * * *
int main()
{
** * * * * * * ** *** num;
* * * *** ** * * * * &num);
* ** ** ** * ** * * * * * * * ** * * ** * ** * ** (num>=90)
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}
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}
* ** **** ** * 0;
}
answered
Oct 5, 2016
by
楊介振
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Hidden content!* * * * * ** *
main( )
{
** ** * * ** ** num;
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}
answered
Oct 5, 2016
by
松山金城武
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Hidden content!#include<stdio.h>
int main()
{
int num=0;
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}
answered
Oct 5, 2016
by
林宗鴻
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Hidden content!#include<stdio.h>
** * * * ** * **
int main()
{
* * * * * *** * * * z=0;
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*** *** * * * * * * 0;
}
answered
Oct 5, 2016
by
威
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Hidden content! * * ** * * *
int main( )
{
* * *** ** * grade;
* * * * * * * * * * * * * * ** * ** * * * * *
* * * * *** * ** ( grade * * 90)
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else if(60 > grade )
** * ** * * ** *** * *** * ** * * * ****
* * * ** * * * * * * * * ** ** * ** 0 ;
}
answered
Oct 5, 2016
by
Noah1011
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Hidden content!#include <stdio.h>
int main()
{
int score;
scanf("%d", &score);
if (score >= 90 )
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else
{
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***** ** ** **** ** * * * ** * * ** ** * * * * * * *
}
return 0;
}
answered
Oct 5, 2016
by
m8f2617
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Hidden content! * * * *
** * * * * *
int *
{
int ** * **
* **** ** * * *** * * * * *
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else ** * * ** **
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*** * * * *
**** * * * ** ** *
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* *** **
* *
* ** ** ** ** * *
* * 0;
}
answered
Oct 5, 2016
by
羅祖嘉
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Hidden content!*** *** **** * *
main( )
{
*** **** ***** num;
* *** * * * * * * * * * *
* ** * * ** * * * * * * *
** * * * ** * * >= 90)
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* * ** * ** *
* * * ** * ** ** 0;
}
answered
Oct 5, 2016
by
松山金城武
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
int num;
** ** * * ** * ** *** * * * * * ** *
if (num>=90)
*** * * * * * ** * * * * ** ** ** *****
else
{
* ** * * *** ** * * * ** * (num>=80)
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* * * ** * *** * * *** ***** * * *
}
return 0;
}
answered
Oct 5, 2016
by
林恆毅
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Hidden content!#include<stdio.h>
int main()
{
int num=0;
* * ** * ***** *** * ** ** * ** ***** ** * * ** * score:");
* * * * * * ** * * ** * ** * * * * * * * *
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* * * ** * * * * ** * ** * ********** * ****
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* *** * * * * * * * * ** ** * * ** ** 0;
}
answered
Oct 5, 2016
by
林宗鴻
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