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AD 20160929 作業 2
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請設計一程式，讓使用者輸入一個數字代表西元年，程式會判斷該年是不是閏年。
範例輸入1
2000
範例輸出1
2000 year is leap year
範例輸入2
1900
範例輸出2
1900 year is not leap year
[Exercise]
Coding (C)
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Hidden content!#include <stdio.h>
int main()
{
* ** *** * * ** ** **** year = 0;
* * *** ** *** * * *** ** ** *** * * * * &year);
* * * * ** * * ** ** *** ** ** % 4 != 0)
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** * * * * * * ** *** * * * 0;
}
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Oct 20, 2016
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Hidden content!#include <stdio.h>
int main()
{
* * * * * * * ** ** * year = 0;
** * ** ** * * * * ** ** * **** ** * * * ** * &year);
* **** * * * * * * * * * % 4 != 0)
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}
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kyle wen
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Hidden content!#include <stdio.h>
int main()
{
* * * * * * * * * * *** * year = 0;
* ** * * * * * *** *** * * * * ** * ** &year);
** * * ** * *** * * * ** * * ** * * % 4 != 0)
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* * * ** * * ** ** * * * ** * * ** * * ** * * ** ** * * ** ** * is leap year",year);
* * ** ** * ** ** ** * 0;
}
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Hidden content!#include <stdio.h>
int main()
{
* * * ** **** * * * * * * * year = 0;
*** * * * *** * * ** *** *** ** * * * ** * * &year);
* ***** * * ** * ** ** * * % 4 != 0)
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* *** ** * * * * * * ** 0;
}
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kyle wen
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Hidden content!#include <stdio.h>
int main()
{
****** * * * * **** * * year = 0;
* *** *** * * * * ** * * ** * * ** * * &year);
** * * * * * ** * *** % 4 != 0)
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* * * *** ** ** ***** * **** * ** ** * * * * * * * * *** ** * * * * ** * ** is a leap year",year);
* * ** * * * * * * * * 0;
}
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kyle wen
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int day,year;
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* * * ** * ** * * * * ** * 0;
}
answered
Oct 19, 2016
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410523005
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Hidden content!#include <stdio.h>
int main()
{
* * * * * * * *** * *** * * ** * * * ** * enter a year:");
* ** * * ** * * ** ** * ** year = 0;
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* * * * *** * * * * **** ** 0;
}
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Oct 15, 2016
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Hidden content! * * * * * * * ***
int main()
{
* * * ** *** * *** * **** t;
* * * * * * * ** ****** * * * ***** ** * ** *
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Oct 5, 2016
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Hidden content! ** * * * * *
int main()
{
** ** ** ** * *** * * ** *** * t;
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Hidden content! * * * ** * * ** **
* ** ** * * ** * **
int main()
{
int year;
*** **** ** * * * *** **** *
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** * *** ** ** ** * ** * * * ** is a leap ** * **
** * * * * ** ** * ** * * 0;
}
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