Final Exam 2 (20%)

1 like 0 dislike
2.6k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 2.6k views

37 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>


int isprefix(char prefix[], char txt[]){
     *   * *  ** ***  *** *  i,flag=1;
***  ***   *    *  ***   ** * * ****   ** * **  **   
*  *   **  *** *  *    * ** * ** *******          * * * **    **
   **** ** * *      **

*  *   * ***  * *   ** * flag;
}


char prefix[100],txt[100],i;

int main(){
* **  * * ** *  **      *    ***    **    * ***** 
***** ** **   **** **    ** ****   ***

** *** **   **** *   * *     *    *     ***
 * * **     **** *  * *  * *  *****       **      *    * *  * ****  *      ******  ****    
*     *  **    *    * * *** *   ***   *  *  ***   ** *    * * *** is a prefix of ",prefix, txt);
***     ****  * * * ** * * **** * * *  * * **** * ***  *      **  *  * **  ** ** * * *   ***    ** 
****   **   * ** *  *  *  
  * * * * ** *   ****    ****  {
**   * * * * * **  *  ** * *      *  * ***  **   ***   ***** *  ***  **  * *****  **** * *    * **    ******
 * ********* ***    **       *  * ***** **     * ** **  * ***    *   * is not a prefix of ",prefix, txt);
* *  * * *   *  *  * *  *  **    *   *****  *  ** *** ***   *    * *  *   ** ** ** * ** *   *****  *  **** 
 **   * * **   **  * *   *****
    * *    ** *         ****  0;
}
answered by (-286 points)
0 0
prog.c: In function 'main':
prog.c:24:16: warning: too many arguments for format [-Wformat-extra-args]
         printf(" is a prefix of ",prefix, txt);
                ^~~~~~~~~~~~~~~~~~
prog.c:29:16: warning: too many arguments for format [-Wformat-extra-args]
         printf(" is not a prefix of ",prefix, txt);
                ^~~~~~~~~~~~~~~~~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*      ****** ** *  
* * ***** *** * **   
char prefix(char string1[],char string2[] )
{
 **  * *   *        * *  * i,a;
* *       ***********  *  *****
* *  *   ** ** ** ** *** *  * * *   *   *** **
        ****** * *

  *     * **   *   ** ** ******   *** *  **
  {
 * ***  **  ***  *    **   *     *  *** ** *  *****  *  *
 ****** *  *  *** **  *******  * *** **   *         * *
* *** * * ***
***  * * ***     *     *     *   *   *
 ** ***          *** ** **   *   * is a prefix of %s", string1,string2);}
 ****** **    *   **  *****  * * *  *  * *  is not a prefix of %s", string1,string2);}
 ****       *
 *   * *  ** * **
 **** * *** *
* *** **  ***  *   * *   **    *     * ** ***** * *  ***  *** *   *   **   *
* ********* **
 **** **     *  *   * **        *      *  ***   *    **
  * *****   ******   ****  *  * *  *  *   ***   **
 ** ** * **** *** ***** * **  *** * ******   *      *   ***    * 
* *     *  **  **    ** *  * **  *   *  *
 *   *  ****  
* ***** *  ** * * * * * *      *  *** *
 *   *  *** *   *   ****   *   is a prefix of %s", string2,string1);}
**** *  *** * *  *  ** * ** ***   *  is not a prefix of %s", string2,string1);}
***** ***** ****  

}
int main(void)
{
* *  ** * *  * chaine1[1001], chaine2[1001];
   * ***** ***  * ******** * *    ***   *
    * **  ****   ******** ***   **   **
 *    **   *  * **  **  ** **
*** ** **  ** *     0;
}
answered by (-168 points)
0 0
prog.c: In function 'main':
prog.c:37:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1001]' [-Wformat=]
   scanf("%s\n",&chaine1);
           ^
prog.c:38:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1001]' [-Wformat=]
   scanf("%s",&chaine2);
           ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
***   *  * ** *  *  ** 
** ***** ***  *    
int main(void)
{
* *** * *** * * *** **  *  *** str1[100],str2[100],i;
 **     * *  * *** *   *  ** * ** **  ** ***  *  *    ***
*   **     *** ****** **          *    *    ****  
  *  **  * * * *  *   ****  *  
**  *** ***** * ****  *** * ** * * *** *   ** *  ***  *  ***
*   ******* *  **  ** * ***    ** *  * *** ** ****  ** * **  *   ** *   **   *   * * * *** * ** is not a prefix of %s",str1,str2);
*    *     ******* * ** **   * ***   *** ** ***     **     *** * * ****  * ** 0;
** *   * *** * **  * ** **  **   **   * ***  **       * **   *  **  *** **   *
 *   ***    *** *** ****  

 printf("%s is a prefix of %s",str1,str2);
  * *** * * **** **** ** * 0;
}
answered by (-304 points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
     scanf("%s%s",str1,str2);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'int *' [-Wformat=]
     scanf("%s%s",str1,str2);
               ^
prog.c:7:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(str1);i++)
               ^~~~~~
prog.c:7:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:7:22: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=0;i<strlen(str1);i++)
                      ^~~~
prog.c:7:22: note: expected 'const char *' but argument is of type 'int *'
prog.c:10:23: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
             {printf("%s is not a prefix of %s",str1,str2);
                       ^
prog.c:10:45: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'int *' [-Wformat=]
             {printf("%s is not a prefix of %s",str1,str2);
                                             ^
prog.c:15:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  printf("%s is a prefix of %s",str1,str2);
           ^
prog.c:15:29: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'int *' [-Wformat=]
  printf("%s is a prefix of %s",str1,str2);
                             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(str1);i++)
               ^~~~~~
prog.c:8:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:8:15: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
** **   **** ***  *  ***   str1[100],str2[100];
    *    **  *  * * *** ** i,c=0;
***   *** *******    **   *  * ** *  * *** *****
 *** **** ***  *    *   *      * *  ** *  *   ** ***
 * * ** *   *  *     ****** **** *** *  *  ***
  * **   * *** ** ** ** **  
** * * *     * ******  * **  *       **  *  *  * * **** * ***** *     * *  
  ** ** **      *  * ** **  ** *  ***  *   ** * * **
********    ***** **** **    **   *  ** **  ** ************ **  **** *** * **    * 
 ** *     *  * *  * *****   *   *     *  *** *****     *   ** * *
    }
 *******   *** **** * *     **   * 
* * **  *  **** **  *  ****
* ** *** *****  * *  **** ***        **** * *  *** * ** **** * ** * is a prefix of %s",str1,str2);
*****  ** *   *** * * 
 * ** * ** * *  **  *   *   *  
**  *    ***  ******    ***** *
   **** ** *   * **    *   * *   *  * *    ****   *  ***   **    *   *   is not a prefix of %s",str1,str2);
 * **   * *  ** **  * *  *
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
# include <stdio.h>
# include <string.h>
 int main(void)
 {
*  * * ***  *  ** ** ********* ***   * pre[100],str[100];
    *   ** ** *   *  *** *** *** ** *    i;
**   *** *** ****** **  *   ****      * *  *    *   ****
* ***   ** ****      **  *  ***  *  ** ** * *    * ** * * ** ** *
*  * *  **  * ** * *   ** *  * * ** *    *  **  *  * * ** 
    {
*    **      *** *   *   ** ***  *   * **  ** * ** ***** ** *  ****     * 
  ******  *****        ***    *  * *** **  *   ** *   ** ** *   **   * *  **  ***
**  **** *  **  **  * * ** ** * * *  *** * **  *  ***   *   ** *   **  *    * *  * *  * *** * **********  **   *** * is a prefix of %s",pre,str);
 **  * ** ***     *  **      *  * *  **   **    *****   **    ** **  *    ******* **   ** *** *   * *  ***** *
  **  * ***         **  *  *   ** *    *  **  **** *  * ** *  *** ******* *    *  **
** **    ** ** ***  *    ***   *  ** *     ** ***** * 

*** * * *** * * *         *       *** *   **   * *   *  **   ******* *     **
 *** *  * ** *** ** *   *  * *  *  *   *     **  ***   * * * **   ******  *   * *  *****    *** ** *  **    *  **   is not a prefix of %s",pre,str);
 **  * * * ** **   *   **  *  ** **   *      ***   *****    **  * *  ** * **  *    ** ** ***** ***   *** **** ** *    *  * *
  **   *** * ** *       * *   **    ** **  ***   *******    *  *     **
    }
    return 0;
 }
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    *   *     *** * ***   * **  *  str1[100],str2[100];
      * ** * ***  **   ***   i,c=0;
*** * *  ** **     *  ** *  **  **  **     * * * * 
 * * * *    *  ** * *** *   * * ** * *  ******
*  *    **** *  ** ** **  ***   * *   *
* * ***     ** 
*   ******* ****** *  * **  **** ***  *  **     **** *   **  ***    *  
** ** * *      *****  *     *******  ***** ** *    * **
** *  *******   * *       * ***** * * ** ***  *    ***  * *     **  * * ***    
 ** ****   * ****  * ******* **    *   ** ** ****** **    **
    }
   *** *    *  * *  *   ***** * 
* * * ** *  * *    **  *
*     * * *   *    ** * **  ***** *     *  ****   **  **  * * **  **      is a prefix of %s",str1,str2);
 *   ** *** * **   *  *
* *  *    ***   * ***  * 
**   *    ** **** **    ***  ****
* *             *  **   ***  **  **   ****** * * ** *  ***  *    ** * *** is not a prefix of %s",str1,str2);
** * ** ***    *** **  *** 
}
answered by (-323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *   * *** ** * 
#include ***  **  * 
#include  ** **    ***  *

int main()
{
 *** **  *** * * ****  ***   *   prefix[100];
 *****   *   **  * ***** * ** ** * word[100];
*   * **  *****  ** * *  ****   ** * * *** * %s", prefix, word);
* ***   ***** ** ****     * ******* i;
   * **  *    *** *** ******     = 0; i< strlen(prefix); ++i)
 **        * ** ***  ***   
*  ***** ** **     * * *  ** *  *** *  *    *   *   * *   *  * *
 ** * ***     ***  ****  **  * **    ***  **    *
*   ***** ***   **  **** *****  *  **  *  *  *  ***** * * * * * * * *  * *   **  ****  * *  **  is not a prefix of %s", prefix, word);
**** * **  *  * **  *  *  **  *  **  * *  *   *        ****  *   * ***** **  * *     0;
* * *   *** ** * ***  ** *****  *** **   * *** * 
   *    *  *** *** ** *       *  *
*** *** ****** * * *****  ** **** ******* * is a prefix of %s", prefix, word);
  * *  * * ***  *   * * *    0;
}
answered by (-254 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* *** ** ***  **  * *  * * * n,count;
* *  * * **** *  *   * * ****  *   a[100],b[100]={0},c[100]={0};
  *   ****** **    *  *  ******   ** ** %s",a,b);
   * **  *******  * * ***  ** * **
* ***  ***  * *  * *    * *    **   * ***** * *****  *  * ** 
**     **  ** * *      * *    **  *     ** *  * **
*** *** *    * * ***     
 * ***  *         *  **  *  *   *     ** *** ****** *** * * *** * **
** *  ***  * ***  ***** 
** ******* * *   * ** *      * ****  * **   ***   ** *    
 ***  **  ******* **  *    (strcmp(a,c)==0)
* *****   *** *  **   ****    *  
 *** **** * **    **** *  ** ***   **   ** *     *  * ** * ** is a prefix of %s",a,b);
** ****   *****  *  *  ****
 * ** **   * * *****  *   *** *  
       *** ** *  * ***  **
    * ***      ****     ***       **  *  **** *  ****** *** *  * * is not a prefix of %s",a,b);
 **  **** * **  *  *****
* *      *  *** ****  *  *  * * 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    ** *  ***     * * *  *** *   String[50],string[50];
 **    *  ** *    *** ***     a,b=0;
 * **  ***  *********** *** *    **  *   *   *   *
** *  *  *     ***   * *  *  ****   * * *  *** * *

*  ** *  *  ** ** * ** **  * ***  *** *  *  
  **           **  *   *  *
  ****    **  *** *     *** **  ** **  * ***  * **    * **  ****  **  * *
 *  * * * * **    **  **  **   ** **** * *** ***** *** *
  **   **** * **    * * ******* *    **** * **    **   * *** *  ** * * *  * * *** * 
 * ** **  *   *      * *   **  ***  ***  * * ***    **
    }
*    * * * * * *** *   **   * *    
* *  * ** **** *  ** * *    *
 ****  **  *******    * *****     **  ***     ** *     ** ***** is a prefix of %s",String,string);
 *  *  * **    *******     *
 ** ** * * **** **  ****** 
 **   *     ********  **
*****  *** ****** **     ****     *** *   *    ** **  *** *  *  *  is not a prefix of %s",String,string);
 ** *** *  * *****   ***  
  return 0;
}
answered by (-107 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *  ***   **  ***  
#include *  *   ** *     *   

int main()
{
 * *** * ** *     *   ** *  ** a[100],b[100];
*   **** * ***     **** **   **   %s",a,b);
** *** *  *  * *  * *  ** * i,j,prefix = 1,len = strlen(a);
 *****    **     ****  ** **  = 0 ; i < len ; i++)
*     **    *   * ** * * **  
 ***** **  * **  ****   *  * * *  * ***** *  ***** != b[i])
** ******** *   *** ***    ** ** * *  ******  *  *   *   *    *   
  *******   *   * * *  ******  *****       * * **  ** ****** * ** ** *    *** *  **  *** = 0;
 *    * * * *****   **  **  *   ** *   ** * * **  *** *****     *  *  *  **   ***    * * * is not a prefix of %s",a,b);
* ***** ** * * *  ** *  *  *   *  * *   *         **      ****  ** *  **        * *   *   * *
     * ***    *** **  *  *     *** *   ** *****    

     ****      ** ***    ** **    *
* **   ***        *****  * == 1)
 **   **** ***  **  ** *  *     *    *  *****     **  ******  ** * ** is a prefix of %s",a,b);


 *  *   *** * **  * ******    * ** **  0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.92
©2016-2024

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 2.2k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 2.2k views
1 like 0 dislike
32 answers
Final Exam 3 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 2.6k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 1.8k views
0 like 0 dislike
4 answers
[Makeup] Final Exam 2 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 478 views
12,783 questions
183,443 answers
172,219 comments
4,824 users