2 like 0 dislike
1.9k views

若一個正整數的奇數位數字和與偶數位數字和兩者差的絕對值是11的倍數,則這個正整數就是11的倍數,否則就不是11的倍數。

請寫一個程式來判斷輸入的數是不是十一的倍數。

 

輸入說明:

會輸入一個正整數N,N不會超過1000位。

 

輸出說明:

如果輸入的數字是11的倍數就在螢幕上輸出YES,否則就輸出NO。

 

輸入範例:
 

11111111111111111111111111111111111111111111111111



 

輸出範例:

 

YES

 

[Normal] Coding (C) - asked in 2017-1 程式設計(一)AD by (30k points)
ID: 38154 - Available when: Unlimited - Due to: Unlimited
| 1.9k views

6 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
** * *** * *** * arr[1000];
   int even=0,odd=0,i,n,sum;
* ** ** ** ** * ** * * * ***
* * * * ***** ** ** * * *
* * ** * * *** *** ** * * * *
** * ** * ***** * * **
   {
* * ** ** *** ** * * * * ** * * * * ** ******
* * ** * ** * * * * ** * * * * ** * ** *****
* *** * * *** **** *** *** * *
*** *** ** * ** * ** * **** ******** *** ** * **** ** *
   }
** * **** * * * * **** * * *
**** * * ** ****
* * * * * ** **** * * * * ****
*** * **** * ***** ****
*** * ** ****** ** ** **** * ** * ** **

* * ** *** * * * **** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
** * *** * ** ** *** arr[1000];
   int even=0,odd=0,i,n,sum;
* * * **** ******* * ***
* ****** * * * * **** ** **** **
*** ** *** *** * ******* ** * ** * *
* * * * * *** ** *** * *
   {
* ** * * * * * * ** * ***** * **** ****
* * ** * * * ** * * ** * * * * ** **** ** ** * * *
* *** ** ** * ****** * ** * **
* ** * ** ** ** ** * *** ** *** * ***** ** * * * ** ** ** ** * *
   }
** * **** ** **** **** *
** * ** **** ** **** *
* * * * * * ** * ** *** ** **** **
**** ** ****** * * ** * *
* * *** * ** * * * *****

* **** * ****** * 0;
}
answered by (190 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
* * **** * arr[1000];
   int even=0,odd=0,i,n,sum;
* ***** * * **** ** ** **
** **** ** ** *** *** *
* * * ** ** * * *** ** * *** * * *
* ** * ** ******* * * * *** * *
   {
* *** ** ** * * *** *** ** *** * *** * * **
* * * * * ** * * ** * ** ***** * **** * ** *** * * ** ** ***********
* * * * **** * * * * * ** ***
* ** * * * ** ****** ** * * * ** * * **** ** *
   }
** *** ** * **
**** ****** *** * *** ***
* * * * * * ** * * * **
* * * * *** *** * *
**** * ** ** ** ** ** *** * **** *

** ** ** * * *** ** 0;




}
answered by (174 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 0
prog.c: In function 'main':
prog.c:8:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(j=0;j<strlen(num);j++)
               ^~~~~~
prog.c:8:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:8:15: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
** ** * * * *
int main()
{
** ** ** * char num[1000] = {0};
** * ** int k,a=0,b=0;
** * * * ** *
** * * *** ** * ** *
** * * * {
* * ** * ** ** * * ****
** **** * **** *** * * * * * *
*** * *** ** *** * * *
    * ** ** * * else
* ** ***** * ** *** * *** * *
** ** * ** }
* *** * * ***
** * ** * **
*** * ** * * **
** ** ** * ***** * ** ** * **
* * * ** else
**** * **** ***** ** * ***** * **** * * *
** * * ** **
******** ** ** return * ** *** *
}
answered by (160 points)
0 0
prog.c: In function 'main':
prog.c:6:2: warning: 'gets' is deprecated [-Wdeprecated-declarations]
  gets(num);
  ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccdBSinu.o: In function `main':
prog.c:(.text+0x50): warning: the `gets' function is dangerous and should not be used.
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
    char str[1000];

* *** * ** *** ** ******* **** ** *** *** * * * ****
    {
* ** * * * * ** **** * * ** * ** * * *** len,i,j,odd=0,even=0,sum=0;
* * * *** * *** ** * * * *** * * ** *** ** * * **
        {
*** **** ** * ** ** ** *** * * * ***** *** * * ** **** ** ** ** * * *
*** ** * ** ** *** ** ****** * * *** ** ***** ** * **** ** ** * * * ****
* *** * * ***** * * * *** * **** ** * * ** * * * ** * **** * * * * *
** ****** ** * *** * * * * * * * * * * * **** ***** ** * *** * *** *** * * *** * * ***
* * * *** * **** * ** * ** *** * *** * * ** * ** * * ********** **
*** * * ** ** * * * ** * * ** * ** *** *** **** * * * * * * * **** * ** *
* ** *** * * *** * ** * * ** * * ** ********** * * * **** * *
* ** ***** * ** * * * * ****** * ** * ** * ** ** ** * * **** * **** * * * *** **** ** **
* * ** *** * *** * * *** ****** ** * ** ** * *** * * *** * *
* * * * * * ** *** * * * * ** * ******* * * * *** * * * ** ** ** * *** * ***
* ** * * * * * * **** ** ** * ** ** ** *** ** **** **** ** * * ** ** * * * ** * * * * * * ** ** ** *
** * * *** * *** * *** * ** **** * * ******* * ** **
    }

    return 0;
}
answered
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main(){
*** *** * ** *** * ** ch[1000];
    int one=0,two=0,i,n,ans;
*** * * * **** ****** * *** *** **
    
* * ** * ** ** ** * * * *** * * * * *
    {}
    
* * ** * *** ***** * ** ** ** *
    {
* * ** ** * * * *** ** *** * * *
* * ****** ** * * * ** * * * * *****
* * ** * ** *** ** * * * *** * ** * *** ** ***** * ** * ** ** * *
****** * ******* ** ** * * ***** * ** ** ** ** * *
* ** ******** ** * * * ** * * * * ** *
* * * *** * *** *** **** * * **
* ** * * * ****** * * * ** ** ** *** * * * ** * * * *
* *** *** ** * ***** * ** * *** * * * **** * ** * * **
*** * * * * * * ** * * * ******* * ** * ****
    }
** ** ****** * ***** * ** *
* *** **** ** * **** *** * ** * ** *
* * * ******* *** * * ** * ** * **
* *** * * ** * * ** ** ***** *
** *** ***** **** * * * * * * * * * ***
** **** **** ** * **
** * ** * ** * * *** ** * *
    
** * * *** ** ** *** * ** ** ** * * * * *
}
answered by (192 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.98
©2016-2025

Related questions

2 like 0 dislike
8 answers
[Normal] Coding (C) - asked Dec 20, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38155 - Available when: Unlimited - Due to: Unlimited
| 3k views
2 like 0 dislike
5 answers
[Normal] Essay (Open question) - asked Dec 20, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38147 - Available when: Unlimited - Due to: Unlimited
| 1.1k views
8 like 0 dislike
19 answers
[Exam] asked Dec 8, 2017 in 2017-1 程式設計(一)AD by Shun-Po (18k points)
ID: 36178 - Available when: 2017-12-08 18:30 - Due to: Unlimited
| 8.2k views
2 like 0 dislike
7 answers
[Normal] Coding (C) - asked Dec 20, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38159 - Available when: Unlimited - Due to: Unlimited
| 2.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users