0 like 0 dislike
1.9k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 1.9k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * *** * ** * ** * x[] = {77,22,88,11,22};
* *** * * *** ** * ******** size = 5;
    
* * * ********** * * * ** print the array */
*** **** * ** ** ** ** * * * * i = 0; i < size; i++){
** ** * * * *** * * *** * * ** *** * * ** * ** **** * ", x[i]); ** * * * *** * ** ** * *** **
* * ** * * * * ** **
****** ** * ** ** * ***** * ** ** * ** *
* * ** * ** * *** * ****** *
** ** * ** ***** I need this to happen size-times */
** *** *** * * * ***** j = 0; j < size; j++){
** * * * *** * * * **** ** * ******* *** from left to right */
**** ** * * ** ** *** **** ** ** i = 0; i < size-1; i++){
* * * * ***** * * * * *** * * ** * * ** ** * ** ** * * *** * * i-th element with its neighbor to check if they are in order */
* **** ** * ** * ** * * ** * * ** * ** **** *** * *** *** ** * * * ** > x[i+1]){
** ** ** * ** * ****** **** ** ** ** * * * *** * *** * *** * ** ** * ** * * exchange the values of x[i] and x[i+1] */
* **** * * * ** **** *** * * * * *** *** * * ** * ** * * ** ***** * *** * ***** temporary; * * * * *** * ******* ** * ***** *
* * **** * ** *********** ***** **** * ** * * ** * * * ** ** * **** *** ***** * **** ** ** ** * = x[i];
* ** *** * ** ***** * * * * * ***** * ** ** * * * * *** * * ** * ** ** = x[i+1];
* * ** ***** **** * ** * * ** * *** ** * ** * * ** * *** * * * ** * * = temporary;
* ***** * * * ** ** ** * **** * *** **** * * ** ** * *** **
***** * ***** * ** * ** * * **** * * * *** ** *
*** ** ** ** * * *
* * *** *** * * * *
* * * ***** ** * * ** * print the array */
* * ** * ***** **** ** * * ** sorting: \n");
* * *** ** * * ** * *** * ** i = 0; i < size; i++){
* *** **** ** *** ** * ** * * ** **** * * * ", x[i]); ** * * * * * * * ** * ** **** * **
* * * * ** ***
** * *** * * ** * ** * ** *
* * ** **** ** * ***
*** * * **** * * *** *
***** ** *** *** * ** * * *** * * ** ***
* ***** ** ** * **** * ** ** ** * ** ******* ******  
* * * * * ** * * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * ** ** * *** x[] = {77,22,88,11,22};
* ********* * ** ** **** * size = 5;
    
** * ***** * *** ** ** * print the array */
********** * * **** * * i = 0; i < size; i++){
* *** ** *** * *** ** * **** *** * * * *** **** ********** ", x[i]); ** * **** * *** *** * * * **
**** *** * * * **
** *** ** ** ** ** *** * **** ** * ***
** **** * *
** * * * * * * I need this to happen size-times */
** *** * ** * * **** * * * j = 0; j < size; j++){
** *** ** * * * * ***** * ** * * * from left to right */
* *** *** ** * ** * ** ** ** * * * ** * * ** i = 0; i < size-1; i++){
* * **** * ** * * * *** **** ** * *** * *** * * ** * *** * * ** *** * *** * * i-th element with its neighbor to check if they are in order */
* ** * ** ****** ** **** * *** *** * ***** **** * * **** * > x[i+1]){
* * ** *** *** * * *** * * * * *** ***** *** * * *** *** * * * * ** * * * ** **** ***** exchange the values of x[i] and x[i+1] */
*** ** ** * * * * * * * ** *** * * ***** * * *** * **** * * ** * * ** *** * * * * * temporary; *** * * ******** **** * * ** *
* *** * ** * **** *** ** * *** * **** ** * ** ** **** ***** *** ** *** * * * * * * ***** ** = x[i];
* * ** * * ** * ** *** **** *** * * **** * *** * * *** * ** * ** * * * ** *** * ** = x[i+1];
** * * * ** * * ***** ** ** ** ** * * *** * * * * * *** *** * ** * * **** *** * * * * = temporary;
* *** * * *** * ** **** * ** *** ** **** ** * * ****** * *
********** * ** * *** * *** *** ** * * ** * *
** * *** * **** * ****
*** * *** * ***** *** ***
*** ** ** ** **** *** print the array */
*** * * ***** ** **** ** * sorting: \n");
* ** * * * ** *** * i = 0; i < size; i++){
* * ** **** * * * * * * ** ** * ** * *** ** *** *** * ", x[i]); ** ** ** * ***** **** * **** ****** *
** * ***** * * ** * ***
*** ** ** **** ** **** * * ***** * *
* ***** ** * * *
* * ** * * * ****
* * ** ** ******* * ** * ** ***** *
* *** * * *** *** *** ***** ***** ** * ***  
** * * ** *** * ** * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * * *** * * * ** ** * x[] = {77,22,88,11,22};
* * * * **** ** * * *** * size = 5;
    
* ** * * ** * **** print the array */
* * * ***** ** * * * ***** *** i = 0; i < size; i++){
** * * ** * **** *** ** * ** ** * ** * *** ", x[i]); ** *** *** ** * **** *** * * ***
* ** * ** * ** ** *
**** ** ** * * * * * ** * * * * * **
** ***** *** ** * *
** **** ****** ***** *** I need this to happen size-times */
*** * *** ** * * * * j = 0; j < size; j++){
* ** * * * * ** ** * ** * ** * ** * * * ** ** * ** from left to right */
* * **** * * ***** ***** * * * **** * * **** i = 0; i < size-1; i++){
** * ** ********* **** ** * * **** * **** * **** * * *** ** * *** i-th element with its neighbor to check if they are in order */
*** * * * ** * * ** ** * * *** * * * *** **** * * * *** ** ** * > x[i+1]){
** *** ** * *** *** *** * **** * *** * ** ** * * * * *** ***** * * ** * * ***** * exchange the values of x[i] and x[i+1] */
* *** * ** * ** *** ** * * * *** * ** * ** * ** ** * *** *** *** * * **** * * * ** * temporary; **** ** * ****** ** ** * ** *****
*** *** * * ** *** ** *** ** * *** ** ** * ** * *** * ***** ** ** *** * * * * * ** * *** = x[i];
* * ** * * ** ** * ** * ** * * ** * *** **** ** ** * * *** * *** * * * ** ** * **** * = x[i+1];
** ** ** * *** * * ***** **** * *** * *** * * *** * * ****** * * ** * ** *** *** * = temporary;
**** ** * **** * * ** * * * ******* ** * * * *** * * * * * * ***
*** *** * ** *** ****** * * **** * *** *
* * * ********* * **
***** * *** * * * * ** * * *
* ** ***** * ** * ** * print the array */
*** * * ***** ** * *** * * * * * *** sorting: \n");
* ** * ***** **** **** *** i = 0; i < size; i++){
* **** ***** * ** ** * * ***** * * * * * * * * *** * ** ", x[i]); ** * * ** **** *** * * *** * * **
** *** **** * ***** * *
* * * *** * * ** * * * * ** **** ** * * *
*** *** * ** *** *** ****
* ** ** **** ** **
* ****** ** *** * ** * ** ** ** * * ***
**** * *** *** * ** ** ** * *** * * * *** * *  
* ** * * ** * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* **** ** * * * *** x[] = {77,22,88,11,22};
**** ***** *** *** * size = 5;
    
* * *** *** * * ** * ** print the array */
* ** * ******* ** * * i = 0; i < size; i++){
**** * * *** * * ** * ***** * ** *** * **** ", x[i]); * ****** ** * * * ***** ** *
** ** * * * *** *
* *** **** * * ** * ** ** * * * * * * * * *
** *** * * *** *
* * * ** * * *** ** I need this to happen size-times */
*** ***** * * * * j = 0; j < size; j++){
*** * *** **** * * * ** ** *** * from left to right */
* ***** ** ** * * * * *** * * * * * *** *** * i = 0; i < size-1; i++){
** ** * * ** **** *** * * * * **** *** * * ******* * *** **** * *** i-th element with its neighbor to check if they are in order */
*** *** * ****** ** ** **** * ** ** * *** * *** * ** * * ******* * > x[i+1]){
** ** * * * * *** * * ** * *** ***** * ** ** ******* ** ** * * * *** * * *** * * *** *** exchange the values of x[i] and x[i+1] */
* ** ** ** ** *** * ***** ** * ********** * * * ** ** ** ** *** * * * ** ** * temporary; * **** **** * ** ** * *** * ** *
** * * ** ** ** ***** * ** ** * **** * * ** *** ** * **** * * * * *** ***** *** * = x[i];
** * *** ** * * * ** **** * **** ** * ****** *** * * ** ****** * ******** * *** * * ** = x[i+1];
* * **** * *** * ** * * ** * ** * ** * * * ** * * *** ** * ****** *** *** * * * = temporary;
*** * *** * * ** * * * * * *** * *** * ** ***
*** * * *** ** *** ** **** ** *** * *
* ** * *** ***
** * * ** * * * * **
*** *** * * ** ****** *** print the array */
* * * ** * ** * ** * *** ** sorting: \n");
** *** * * *** * ** ** ** i = 0; i < size; i++){
* * * * ***** * * *** ** *** * * * * ***** * *** ", x[i]); * * * ** ** * * ***
** **** * * ***** ** * * *
* ****** ** *** * * ** **** * * * ****
** * ** * *
** ** ******** ** * ** *
* ******* ** * * * * * * **** * * * *
*** * ** * ** * ***** * *** ** *** ** *** *  
*** ** * * * ** ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** ** * * ** x[] = {77,22,88,11,22};
*** ** ** ***** * * * * size = 5;
    
* * * ** ** * * ** * * print the array */
* ** * ****** * * * ** i = 0; i < size; i++){
** ******** **** * ** *** ** **** * * * **** ** ", x[i]); * ** * ******** ** ** * ** * *
** * ** *** ******
* * **** * ** ** *** * ** ** * ** * ** * **
* * **** **
*** ** ** * * **** * * I need this to happen size-times */
* *** ** ** *** ** * ** * j = 0; j < size; j++){
* *** * ** * ** ***** **** *** * * ** from left to right */
* * *** *** * * * * * * *** * * ** i = 0; i < size-1; i++){
**** ** * * * * * * * ** * * * * **** * ** * ** * * **** ** i-th element with its neighbor to check if they are in order */
*** ** * * ** **** * * ** ***** *** ***** * ** ** *** ** * * ** *** **** > x[i+1]){
** * ** * **** *** ** * **** * * **** **** * * *** *** * * * *** *** * ******** *** * *** exchange the values of x[i] and x[i+1] */
* ** ** ****** * * *** ****** ** * * * * * * **** ** ** * * * ** * ** *** temporary; **** ****** ** * * *
* ** * * ** * * * **** *** * * * ** * * *** *** * ** * ** * * * ** * * ** * *** ** ** *** *** * * *** ** * = x[i];
* * * * * ** * * ** * * *** * * *** * *** ** ** * ** * ** ** ** * * **** ** ****** * ** * = x[i+1];
** * * * ** * * * * ***** * * * *** * * * *** ** * *** * **** ** * * * **** * *** = temporary;
* ** ** * * * *** * ** ***** * * * * **** * ** * ** *******
* * ***** * ** ** *** * * * *** *** *** *
** * *** * * **
** * ** * ** *** *
* * *** ****** ** * ** * print the array */
******** ** * ** * ** ** * sorting: \n");
* ** * ** ** **** * ** i = 0; i < size; i++){
* ** ****** ** ** **** * * * ** ** * * * ", x[i]); **** ** * * *** **** * **
** ** **** ** * ** *****
* ** * * ** * * ***** * *** * ****** *
* * * ** * * **
* ** **** ** * ** ** **
*** * ** * ****** * ** ** ** * * **
** * ** ***** * * * ** ** **** ***** * * **  
** ** *** * ** ** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** * * ** ** ********* ** x[] = {77,22,88,11,22};
* *** * * * ** *** * ** size = 5;
    
* ** ** **** * ***** * print the array */
** * **** ** *** * * * * ** i = 0; i < size; i++){
**** ** ******* ** ****** * * * * * ** * ** ** ** * ** * ", x[i]); ** * ** * * *** ** * **
* * * ** ******
* ** ** * ** * *** *
** * *** ** * * *** *** *
*** ** * * * * I need this to happen size-times */
* * *** ***** * * * * ** j = 0; j < size; j++){
* **** ** * * * ** * * *** *** *** * *** * from left to right */
* *** ** * *** ** * * **** * * * ** **** i = 0; i < size-1; i++){
*** * * *** * **** ** *** * ** **** * * *** * * ** * **** ** ***** ** i-th element with its neighbor to check if they are in order */
* * ** ***** * * * *** ** * *** * * * ** ** * ** **** * ** * *** * * * * * > x[i+1]){
* *** ** * ** **** * * * *** * ** ** * ** ** * ** *** ***** * *** * * ** * **** exchange the values of x[i] and x[i+1] */
* ** ** * * ** * * ** * *** * * * * * * **** *** ***** * ** * * * ** ** ***** ** * * *** temporary; * **** * ** * ** * ** *
*** * *** **** ***** ** ******* *** ** * ** * ** * * ***** * * *** *** *** ** * * * * = x[i];
*** ***** ** * ** * * * ** *** * ** * *** ** ** * * * * ***** * * ** **** **** **** ** = x[i+1];
* *** * *** * * **** * * * * *** *** ** * *** ** * * * * ***** * ** * * = temporary;
* ****** **** * * * ** ** * * ** ** **** * * * ** **
* * ** * * * * * *** *** **** * * ** * * * ***
*** * * ****** * ** ** *
** * ***** *** ******
**** * **** * ** **** print the array */
* * * ** *** * *** * **** * * *** * sorting: \n");
* *** ** ** * * **** * ** i = 0; i < size; i++){
* ***** *** * * * * ** ** * ** ** **** ** ** **** ** * *** ", x[i]); * * *** * * * * * * ** * ***
** * ** * * * * * *
** * *** * **** * ** ** ** **** * ** ** **
**** * ** *** * * ***
* * * * * ** ***
* **** * * * * * * * * **
**** ** * *** * * ****** * * * * * ** *** *  
* ** *** * * *** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** * * **** * x[] = {77,22,88,11,22};
** ** * * * * * * *** size = 5;
    
*** * * * *** ** * ***** * print the array */
*** *** * **** ** **** * * i = 0; i < size; i++){
* *** * * * ** * ** * * ** * * ** * ******** * ** ", x[i]); * ***** ** **** * ** *** **
** * * *** *** ** * *
* **** * * ** * *** ** ** ** * * **
* * **** * **** * * * *
** * * * * * * ** * I need this to happen size-times */
* * * * *** **** * ** ** j = 0; j < size; j++){
* ****** * ** *** *** * * ***** ** * * ** * from left to right */
* * * ** * *** ** **** * * ** * * * ** * i = 0; i < size-1; i++){
*** * ** * **** * ** ***** ** **** * ** ** *** ******** * * * ** * * * * *** i-th element with its neighbor to check if they are in order */
* * ** **** * ** *** * * *** ** * * * * ***** **** ** **** > x[i+1]){
** ** * * **** * ** * ** * ** ** * * ** ** ** * * *** *** ****** * * ***** ** * *** ****** ** * * exchange the values of x[i] and x[i+1] */
* ******* * * * * * * *** * ***** * ** * * * ** **** * * *** *** * **** ***** * temporary; ** * * * ** ** ** **** *** * *
** * ***** **** * ** * ****** * * ** * **** * ** ** ** * * **** ***** * * * * ****** * * * ** = x[i];
* ***** *** ** * ********* * ** ****** ** *** * **** **** ** * ****** *** * * * * = x[i+1];
** ** * * * ** * ** ** * * * * *** * *** * * ** ** * * *** *********** * = temporary;
** ***** * *** **** ** ** ** * ** * * * *** * * ** * **** * ** *
* ***** ** * * * *** ** *** * ** * * *
*** * **** ** * * * *
**** ** ** * *** ** *
** * *** ***** ** *** print the array */
* *** **** *** *** * *** * ** sorting: \n");
*** * *** * * * ** **** i = 0; i < size; i++){
* *** * ***** ** **** *** **** *** * *** *** * * * * ", x[i]); ** ** * * ****** * * * * *
** * * * ** ** ** ** * *** *
** ** *** * ** *** * * * *** * **
*** * * * ** ** ** *
** ** * ** * ******
* **** ** * * * * * * * * * ** *
* * * ** ** **** ******* * ** ** * **  
** * * * ** * ***** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ***** * ** * * ** * x[] = {77,22,88,11,22};
** ** ********* * * * * * * size = 5;
    
*** ***** * ***** ** * * print the array */
* ** **** ** * * *** ** i = 0; i < size; i++){
* ** ** * ** * * ** **** *** * **** *** * * ** ***** * ** ", x[i]); ***** * * * *** ** ***
* * * * * * ** *** *
** ** ** ** ** * * ** ** * * ** *
**** * * * * ** *** *****
* * * * * * * I need this to happen size-times */
* * * ** * ** * * * j = 0; j < size; j++){
* * * * ** *** * * * * * * *** ** * * * ** * from left to right */
* **** * * * ** * ***** * * ** * * ****** *** i = 0; i < size-1; i++){
* * *** * ** * *** ** *** ** ****** ** **** * * * ** ** ** ** ** i-th element with its neighbor to check if they are in order */
** ** ***** * ** * * ******* ** ** * *** ******* * * * * * * * *** * > x[i+1]){
* * * * ** * *** *** * * ** **** ***** * **** ** * ** **** ** * * * * ** * * * exchange the values of x[i] and x[i+1] */
*** * *** * ** *** *** ******** *** * * ***** ** * ** *** ***** * ** * * ** * *** *** temporary; * ** ** * **** * * * **
**** ** ** * * * * *** * ** * ** ** * * * * ** * ***** *** * * **** * * ***** *** * ** ** * = x[i];
* ** ** * ***** * ** ** **** **** * * ** * * ** **** * ** ** * * * ***** * *** * = x[i+1];
** * ** ** *** ** * * * * *** ** * ** *** *** ** * ** * ** * ** *** **** **** ** * ** ** ** = temporary;
** *** * *** *** * **** * *** * * * *** * * ** **** * * *** ** *****
*** ** * * * ** ** ** * ** * **** *
***** * * * * ** *
** ** ** ** * *
* ** * *** * * * * ** * print the array */
* *** ** * * * * *** ** ** ** sorting: \n");
**** ** *** * ** * i = 0; i < size; i++){
** *** *** ** ** ** * ** ** ****** *** * ** * * ", x[i]); ** ** * ***** *
*** *** * ** *** *
*** * * * ** ** * ** ** *** ** ** *******
***** *** * * * ***
* * *** * ***** ********
* **** ***** * *** ** * * ** **
* ** * ****** ***** ** * * **** *** *** * ** **  
** ** ** *** * * *** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * * * * **** * * x[] = {77,22,88,11,22};
* * * * * **** * * * size = 5;
    
* ** * * ** * * * * print the array */
** * * * * * *** * i = 0; i < size; i++){
*** * * ** * ** *** ***** ** ** *** *** * *** ** ", x[i]); * **** **** **** **** **** ********
* *** ** * * * * **** **
****** * ** * ** * ***
* * * ** * *** **** * **
*** ** * ** ** ** * ** ** I need this to happen size-times */
** * * *** * * * j = 0; j < size; j++){
*** * * * **** * *** ***** * * *** ******* * * from left to right */
* * * ** *** **** ** ** * * ***** ***** ** *** * i = 0; i < size-1; i++){
** ***** *** * * **** ******* * * * * * * * **** **** * ** ***** **** i-th element with its neighbor to check if they are in order */
* * * ** * ** * * * ** ** * **** * * * ** * * *** * **** * * * > x[i+1]){
* * * ** * * * * *** * ** ** * * * * ** ** * **** * * ** * * * ** exchange the values of x[i] and x[i+1] */
*** * **** * * * * ** *** * * * * * * ** ** ** ** ** * ****** ** * * ** *** * * * *** temporary; ** ** ** *** ** * * ***** *
****** * ** * * * * * *** ****** ** * * * *** * ***** ** * ** *** ** * * *** *** ******** * = x[i];
* * * ** * * * * *** *** *** * *** ***** *** ***** ** ****** * * * ** * * ** * * * * * * * = x[i+1];
*** ** ** * ***** * * * * *** * *** *** * ** ** * * * *** * **** ** ** * * * = temporary;
** * ** ** * ** * *** ** ** ** * * * * *** **** * *** ** * * ** * ** **
* * ******* * *** ** * * **** ***
**** * ** * ** ***
** * * * * *** * **
* * * ***** *** **** ** * print the array */
* ** ** * ** * * ***** * sorting: \n");
* * * ** * * * * * * * * i = 0; i < size; i++){
**** *** * * * * *** * ** *** * ****** * * ", x[i]); * * * **** * * ** ***
****** ********* * ** ***
** * * * *** * * * ***** * ******* *
* * * **** ** * **
*** **** * ** * *
* * * *** ******* **** * ** *******
** ****** * * ***** * **** * ** **** * * *** * ******  
* * **** * ** ***** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** ** *** ** * ** *** * * x[] = {77,22,88,11,22};
* * * *** * **** *** size = 5;
    
** ** * * * ** print the array */
* ** ** * ** * * *** i = 0; i < size; i++){
*** * * **** * **** ** ** * *** * * *** ** * * * ", x[i]); * * ** * * *** * * * * * * ***** *** **
** **** * * * * * *
* ** * * ** **** * * * * ** ***
* * * * *** * *******
** ** * ***** * ** * **** I need this to happen size-times */
* * * * * *** * ** j = 0; j < size; j++){
* *** * ** *** * * * ****** * * * ** *** from left to right */
** * * *** ** * * * ** * * *** * ** i = 0; i < size-1; i++){
*** ***** *** * * * *** * ** **** * *** * * ** ****** * * ** **** ** * * i-th element with its neighbor to check if they are in order */
* ****** *** * ** * ** *** * * **** * * *** ** * * * * ***** ** * *** > x[i+1]){
* * * * ***** ****** ** ** * * ******** * * ** ******** * * ** ** *** ** * ** **** * * exchange the values of x[i] and x[i+1] */
** * * *** ** * *** * * * ** **** ****** * ** ** * * * ** * * * ** * * * * temporary; *** ** **** *** ** * * * *** ***
* * **** * * *** *** * ***** *** ** * ***** * ** * ** * ** *** * *** * * * * ** **** = x[i];
* * * ***** ****** * ** * * ***** * ** ******* ** **** ** ** *** * *** * * * * * * * = x[i+1];
** ** * ** * * *** ** **** ** * * ** * * ** *** *** ** * * * * *** * * *** * * = temporary;
** * ** ** * * * * * * * *** ***** *** **** ***** ** *** * ******** ***
** ** *** * ** * * * * *
** **** ** ** ** ** * * *
* * * ** * ** ** * * *
*** ** *** * ** * print the array */
*** ** * ** * * *** ** ** * sorting: \n");
** * ***** ** * *** ** * * * i = 0; i < size; i++){
** * ** * ** * * * * **** * ***** * ", x[i]); * * * *** * * **** * **
* * * ***** *** * *
** **** * * *** ***** ** ** *** ** ***
* ** ** * *** *
** * ** * ** * * ***
** * *** ** * ** ** ** *
***** * * * * * *** ** * * * * *  
** ***** * * * * * ** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.126
©2016-2024

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 1.3k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 663 views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 934 views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 578 views
12,783 questions
183,443 answers
172,219 comments
4,824 users