0 like 0 dislike
1.9k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 1.9k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** ** * **** * * * x[] = {77,22,88,11,22};
*** **** *** * *** size = 5;
    
*** * * * * * ** ***** * print the array */
*** * ** **** * **** ** * i = 0; i < size; i++){
*** * * * ** ***** ** * * * ******** * * * * * ", x[i]); ** * * * * ** * ***** *** *
* * * ** *** * ****
**** *** *** *** *** * ** *** * * ** * * **
** * * * ** ** **
* *** * ******** * * * I need this to happen size-times */
*** ** ** *** *** ** * * j = 0; j < size; j++){
****** ** * ** *** * * * ** ** *** *** ** from left to right */
** ** * * * * * ****** ** * ** **** **** i = 0; i < size-1; i++){
* ** * * * *** * * * ** * *** * *** *** * *** * ** ** * i-th element with its neighbor to check if they are in order */
*** *** * * ******* * * * ** * * ** * * * **** *** * ** **** > x[i+1]){
****** ** * ** **** * *** * *** ** ** ** * *** * * * * * ** * ** *** * * *** exchange the values of x[i] and x[i+1] */
*** *** *** * * *** * ** ** * * *** **** * ** *** ** * * ** ***** * * * * ** ***** temporary; * * ** ************ * ** * *** **
* **** * * ** * * ** * **** *** ** ** ** * * * ** ***** ***** ******* * ** *** ** ** * = x[i];
* * ** *** **** ** * * * *** *** * ** * ** ** ******* * ** *** *** * * ** * *** *** = x[i+1];
***** **** * * * *** ** * *** **** * ******* * ** * ** * * ** ***** * * * ** = temporary;
* ** **** * ** * * **** * * *** *** * ** * ** * **** *** ***
**** ** * * * ** * ** **** * *** ** *** *** *
** * * ** ** * * *
* **** * * **
** *** * * * ** *** print the array */
* ** *** * * ** ** * ** ** * * * ** * sorting: \n");
** **** *** * ** i = 0; i < size; i++){
* * * **** ** ** * *** ** **** * * * *** ***** * * ", x[i]); * * *** * *** ** *** * ** * ** ** *** *
*** * * * * ** * * ** *
* * * * * *** * * * ** **** * *
* ***** * ****** ** *
* **** ** ** * *
* * ** ** ** ** * ** * ** * ** * *
* * *** * *** **** *** * * * ** ** * * **** *  
* * ****** * * * ***** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * ***** ** *** x[] = {77,22,88,11,22};
** * * * ****** * ** size = 5;
    
* ** * ****** *** ** **** print the array */
* * * ** ** * ** * * i = 0; i < size; i++){
***** ** * * ** * *** ** ** ** *** ** * * ** * ", x[i]); ** *** ** ** ** * * * **
******* *** * ** * * **
* * ***** * *** * * *
** * *** *** *
* *** * * *** ***** * * ** * I need this to happen size-times */
* **** *** ** * ******* ** * j = 0; j < size; j++){
* ** ** * **** * ** *** *** * ** ** ** * ** *** **** from left to right */
***** * * ***** ** ** * ****** **** ** * * ** * i = 0; i < size-1; i++){
* * * ****** * * *** ** * **** * * * ** * * * * * ******* * * * ** * **** i-th element with its neighbor to check if they are in order */
* **** ***** ** * ** * *** ** ** * * ** ** * * * *** * * * * ** ** ** > x[i+1]){
* * ***** *** ** * * *** ** **** ** ** * ** *** **** ** * **** ** * ** ***** * * **** * exchange the values of x[i] and x[i+1] */
**** * * **** ****** ** * * ***** * * * ********** * ** ******** *** * * ***** * * * ** temporary; * **** * * **** ** *** ***
*** **** *** * **** **** * *** * ** **** * **** ** *** * ** * ** * * ** *** **** ** *** ** **** * = x[i];
* * ** * * * ** * ** **** ** * * * ** ** ** * * * * * **** ** * ** * * * * * ** * ****** = x[i+1];
** ** ** ** ***** ** * * *** * * * * *** ** * * ** * * *** * ** * **** * * * * = temporary;
* ** * * *** * * *** *** ** * * * * * * ***** ***** *** * *** *
* ** ** * * * * * * * * ****
* ** ** ** * ** * **
* * * * ** ***
*** *** ******** * ** ** * print the array */
*** * * * ** * ** *** ** * * * *** ** sorting: \n");
** **** *** ** * * * *** i = 0; i < size; i++){
* *** * * * ** ** * **** * ***** * ** *** ***** ", x[i]); *** **** * **** * * * * ** **
**** ****** * *
******* * * ** ** ** * ****** **** ** * **
**** * * **** ***
*** *** * ** * ** ***
** * * * * **** *** * ** ** ** **** *
* **** ** *** * ***** ** ** * *** ** **  
* *** * *** * ** * **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** * **** ** ****** * * x[] = {77,22,88,11,22};
*** * * *** * ** size = 5;
    
** * ** ** **** * * print the array */
* * * * * * * *** * i = 0; i < size; i++){
** * ** * * * ** ** * ** * ** * * ** * ", x[i]); * ** ** * * ******* **** * * * * *
* * *** **** * ** * *
*** **** ** ** * * ** **** *** * **
**** * * ***** ** **** **
* **** * * * * * I need this to happen size-times */
*** * **** * * ** *** *** j = 0; j < size; j++){
* **** * * * *** * **** *** ** *** * ** * * *** * from left to right */
* * *** ** ** * * ***** * ** * * ****** * i = 0; i < size-1; i++){
* *** ***** *** * * * **** **** * ***** *** ****** *** ** *** * * * i-th element with its neighbor to check if they are in order */
* ** ** **** ** * ** * * **** * * * ** **** * ******* * * * ** *** > x[i+1]){
** *** * * ** * * ** ** * * *** * * * * *** **** * ******* * ** ** ** ** * * ***** exchange the values of x[i] and x[i+1] */
*** ** * *** **** * ** * ** * * * * ** * * *********** * * * * * ****** ***** ** * temporary; * * ** * * ** ** ** * **** * *
* * * * * * * ** * ** ** * * * **** * ** * * *** **** *** * ******* *** *** *** ******* = x[i];
* * **** *** * * ** ** *** *** **** * * * *** ** ** * * ********* ** *** ** * ** * * = x[i+1];
** ****** *** * * *** ** * * * ** **** ** * ***** * ** * * * * * ***** ** * = temporary;
* * ** **** * *********** ** ** * * * * *** * ****** ** ****
** * * ** *** *** *** * **** * * * * *
** * * * * * * *
*** ** *** *** * **
* * * ** ** ** * * * print the array */
** ** * * ** * * * * * * ** ** sorting: \n");
*** * *** * **** ***** ** i = 0; i < size; i++){
** ***** * ** * * * * **** **** * **** * * * * ", x[i]); * * **** * ** ***** ***
***** * ** ** ** * * ** *
* ** * * * ** ** ** * ** * * * * * ** **** * *
* ***** * ** ** ** * *
**** * *** * * * * **
* ** * ** ** * **** * ** * ****
* * ****** **** *** ** * ** *** * ***** * **** *  
** * ** * * ** * * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * **** * * ** * **** x[] = {77,22,88,11,22};
**** * * ** * ** ** ** size = 5;
    
* *** * * **** * * *** print the array */
** ***** * *** * * **** i = 0; i < size; i++){
* *** * ** ** * * * ** * * * ** *** * * ***** * ** ** ", x[i]); * * *** ******* ** * * * * * ***
* * * *** * * ** ****
*** * ** * * ** * ** ** * ** *
* * *** *** * ** *** ***
** * * * * ** * * * I need this to happen size-times */
**** ** ** * ** ** ** j = 0; j < size; j++){
*** *** *** ** * * *** * ** * * ** * * from left to right */
***** * ** ** ** * * * ** ***** ** ** * i = 0; i < size-1; i++){
***** * * * * *** * * ** ** ***** * ** * * **** * ** * * * * * *** i-th element with its neighbor to check if they are in order */
***** * ** * *** * ***** ** ***** ** * *** ** * *** ** * *** * > x[i+1]){
* ** *** * ***** ** *** ** ** * * ** * *** * * * * * ** * ** *** * * ****** * exchange the values of x[i] and x[i+1] */
* **** *** * * **** *** * ****** ** ** * * ** *** * ** * * * ***** * * *** * temporary; *** * * * ** * * ** ** * * *
* * * * **** * * * * * *** ** ** * ** *** * * * * * * *** ***** * * * * *** * * * * * ** * = x[i];
* ********* *** **** *** **** * * * * **** * ** * *** * * * **** * ** ** ****** * = x[i+1];
** * * ** *** * * ** * * * *** * *** * * * * * *** ** *** * *** **** ** *** = temporary;
* ** * ** * * * * ** * ** * ** ** ** ** ** * ** *** ** * * * ** *
* ***** * ** * * * ***** *** * * * * * *
* ** * * **** *** *
** * *** * * ** *
* ** * ** ** ** * * **** print the array */
* ** *** * * * * ** *** * ** * * sorting: \n");
** ** *** ** ***** ** i = 0; i < size; i++){
** ** * * ** **** ** ** * * ** * * * ******* * * ** *** ", x[i]); ** ** * *** ** ** * ** ** **
** *** * ** *** * **
*** **** * *** * ** * *** * * * * * ** *
** ** * ** * *** * * *
* * * ** * * * * **
* ** * * * *** * ** * * ** * * * * ** **
** *** *** * *** **** * * * ***** **** *  
*** *** * ** * * * *** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** *** ** * * * ** *** **** x[] = {77,22,88,11,22};
* * * * * ***** * * * size = 5;
    
* * *** ***** *** * * * print the array */
* * * *** * **** * ** * i = 0; i < size; i++){
*** ***** *** ** * * *** * *** *** * *** ** * * ** ", x[i]); * * ** ******* **** *** * * ** *
** *** * ** * ** * * *
* * ***** * * * ** *** *
**** * * *** * *** *****
** * * * * ** * * * I need this to happen size-times */
**** ***** ***** * * * j = 0; j < size; j++){
* *** ** * * * * ***** ***** * ** from left to right */
*** * * * * * * * * *** ** * * * i = 0; i < size-1; i++){
* * ** * ** **** ** * * * *** * * * * * * * ** ** ** **** i-th element with its neighbor to check if they are in order */
* *** * * ** * * ** **** ** ***** * *** ** *** *** ** ** * *** * > x[i+1]){
** ***** ** *** * ****** * ***** ***** * * ****** * *** * *** *** * * ***** * **** * exchange the values of x[i] and x[i+1] */
** ** *** * ** *** **** ** * ***** ** ** * * * * ** * ** **** ** * temporary; *** * * ** * ** ** * *
**** * **** ****** * *** ** * * *** * * * **** * * * * *** * ** ** * ** = x[i];
** * *** * * * * * ** * * * ** * * ** * ***** * *** ** * **** * * * * ** * = x[i+1];
** * * ******* ***** **** ***** *** * * **** *** *** * * * * * * * ** * ** **** * * * *** **** ** * = temporary;
* * ***** * ** * *** * * * * *** ** * *** * * *** * *** **
** * ** * **** *** ***** * ***** ** ** *
* ** ***** ** *
* ** * * * *
* ******** * * ** print the array */
**** * ***** * **** *** ** ** * * sorting: \n");
** ** * * * * * * ** * i = 0; i < size; i++){
*** ** *** * *** ****** *** ** * ********* * * * ", x[i]); ** * * * **** **** * * *** ****
* * * * * * ** ***
*** * * * *** * ** * * * *** ********
* ***** ** ** * ******** *
** * * ** ****
** ** *** * * **** * *** * *** * * *** *
* * ** **** *** ** * * ** * **** * *** *  
******** ** ** * ** *** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** * * * * * ** ** * ** x[] = {77,22,88,11,22};
** * ** ****** * * * * ** size = 5;
    
* *** * * * **** * * print the array */
* ** * ** * ***** i = 0; i < size; i++){
***** * * ** ** *** *** **** * **** *** ** * ** ** * ** * * ", x[i]); ** ******* ***** **** * *** ** *
****** ** *** **** * ** * ****
*** * * * * ** * *** ** * ** ** ** ***
* *** * * * *** *
** * * * *** ******* *** I need this to happen size-times */
** * * * ***** * ** * j = 0; j < size; j++){
* ** ** * * * * * * * * * **** * * * * ***** * from left to right */
* * ** ** ** ** * *** ******** * * * ** * ********* i = 0; i < size-1; i++){
** * *** * ** **** * * **** *** * ** * ** ** ***** ** * * * * * *** i-th element with its neighbor to check if they are in order */
** * * * ** ** *** * ** * * * * **** * * *** ** * * * > x[i+1]){
* * * * * ** * ****** ** * ** * * ** *** ** ** * * **** * ** * *** ***** *** exchange the values of x[i] and x[i+1] */
* ** **** * * * ** * *** ** * * ***** ** * * * ** * ** *** * * * temporary; * * * ** * * *** * ** ** *** ***
** *** * * ** * * ** * *** ********* ** * ** *** * * * **** * ** ** ***** ****** * * * = x[i];
** * ** * * ** * * * ******** * *** ** ** **** ** *** * **** * * * * ** **** ** ** ** = x[i+1];
** **** * * *** * * * * ** ****** * **** ****** * ** * ** * * **** * ********* *** * * = temporary;
**** * * * * *** * * ** * ** * * ** * * ** ******* * * ** ** **
** * ** * ** * ** * ** *** * *
***** * ** * * *
** *** ***** *
** * * ** * ** * print the array */
** * ** * *** ** ***** * ** * * * sorting: \n");
* * ** * * * * * i = 0; i < size; i++){
*** ***** * * * **** * * ** * *** * ** * * ** ** *** * ** ", x[i]); * * **** * * ** * ** ** * ** ** *
*** * * * ** **
** * * ** ** * * ** ** *** ** * *
* ** * * * **
** *** * *** * * ***
* * * **** **** *** * ** * * ****
*** * * **** ** *** ** * * **** ** *** * ** **  
*** * * *** ** ** ****** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** * * *** ** *** x[] = {77,22,88,11,22};
* * *** * *** * * * * * ** * size = 5;
    
** * * **** * print the array */
* * * **** *** ** * ****** * i = 0; i < size; i++){
** * * *** ** * ** *** ** ** **** * * * **** ", x[i]); **** ****** ** * * * *** *
** * ** **** * * *** * *
** * **** ** * * * * ****** * * *** * *
* * *** * ** *** ** *
* * *** * ****** * * * ** * I need this to happen size-times */
* * *** ** ****** *** j = 0; j < size; j++){
*** * * *** * * ** * * * * **** ***** * ** from left to right */
***** * *** * * ****** * * * *** * * i = 0; i < size-1; i++){
** ** *** * ***** * *** ** * ***** * * * *** * * * * **** *** * ** ** i-th element with its neighbor to check if they are in order */
* *** * *** *** *** **** * * ** **** * * * **** * * ** * * > x[i+1]){
** * ****** * * *** * *** *** * * * ** ** * ***** ** * * * * * * * *** ***** ** exchange the values of x[i] and x[i+1] */
* ** **** **** ** *** * *** * * *** *** * * **** * **** * * ****** * * * ** temporary; ** * * * * * **** * ********* * ***
* ** * ** * **** * *** * ****** *** * * * *** *** * * * * ** ****** * **** * * *** * * = x[i];
* * * * **** * ** * * * ** * * * * ** * * * ** * *** * *** * *** * ** * *** * ** * * = x[i+1];
*** ** * * ** *** *** * ** *** ** ** ** * *** ** * * * ** * * **** ** ** * = temporary;
* *** * * * * *** * * *** ** * *** * * *** * * * * *** *** * *
** * *** *** ** * **** * *** * ** * *** **
* ***** ** * ** ***
* **** * ** *** **** ***
* *** ***** * * *** * print the array */
* ** * * ** ****** * ** ** ** * ***** sorting: \n");
* * * * *** ** * * * i = 0; i < size; i++){
* ** ** * * ** ** ** ** ** ** ***** ** ", x[i]); * ** * * ** **** *** **
**** ** ** * **
* * * ** **** * ***** ** *** * * * * *
**** * ** * * *** *
* ** * * * *** * * *
**** *** * * * **** ** * * * * ** * * **
* * ****** ** * ** *** * **** * * * *** *  
* ** ******* ** ** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * ** ** * **** * x[] = {77,22,88,11,22};
* ** * ***** ** ** size = 5;
    
** * * * * *** *** print the array */
* *** **** * * i = 0; i < size; i++){
* * ** * *** * * ** * *** ** * * * * ** *** *** ", x[i]); ****** **** * ** **
** * * * *** * ** * ** * **
** ****** ** *** * * *** * * * * *** * **
* * ** * * * *** *****
** * * ** * I need this to happen size-times */
** * * * * ** *** **** j = 0; j < size; j++){
* *** *** * *** ** * ** * ** ** *** * * * from left to right */
* *** * * * * * * **** * * * * * * * ** ** * * i = 0; i < size-1; i++){
* * *** ** * * * * * *** ** * ** ** *** * ***** ** ** ** * * * * i-th element with its neighbor to check if they are in order */
* ** * ***** ***** **** * ** * *** *** ** **** * ** ** ****** * ** ***** ** *** > x[i+1]){
***** * *** * *** ***** ** *** ***** * ***** * ***** *** **** ** * ** *** * ** ** ** exchange the values of x[i] and x[i+1] */
* **** ******** * ** *** ****** ** * *** * ** * * ** * *** ** ****** ** * * * * ** temporary; * ****** * * *** * * ** *
* ** * *** ** *** * * * * * ** ** * * * ** * ***** * *** *** *** ** *** ***** ****** = x[i];
** * *** *** ** * ** * ** * *** ** ** ** ** * **** ****** * * ** * * * * *** *** ** = x[i+1];
* **** * ** * ******** ** * ** *** ***** * * * * * * **** ** * * * * *** *** ********* *** = temporary;
*** * ** * * * * ***** ** * * ** * * * ** *** *
****** ** * ** ** *** *** ** * * * ** * * **
** ** ** *** ** **** **
* ***** * *** * * ** **
*** ** * ***** ** * print the array */
* ** * *** ** ****** **** ** sorting: \n");
** ** * *** ****** ** * i = 0; i < size; i++){
***** *** * * ***** * **** * ** ** ** * * * ***** * ** ", x[i]); * * * * * ***** ** * ** * *
* * * * * ****
* **** * ** ************ * * ** *** ***** *
** * ** ** * * * ** **
* * *** * * **** * *
** * * ***** *** *** * * * * * * * ** *
* * * * ** ** **** ******* ** * * **** *  
** **** * *** *** ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ****** * **** * x[] = {77,22,88,11,22};
* ** ** * ** **** size = 5;
    
** * * * ** ** * print the array */
*** ** **** * * **** ** * **** * i = 0; i < size; i++){
* *** ** ***** * * ** *** *** * ** ** * * ** ** ", x[i]); ** * * ** * * * * *** * * *
* * * ***** ** * *** ***
* * * **** * ** ** * * * ** * ** *
*** ** **** * *
*** * * ** * * * * I need this to happen size-times */
* * **** * *** * ** ** ******* j = 0; j < size; j++){
* * * * * * ** *** ** * ** * ** * from left to right */
***** * ***** ** *** * ** * * ** *** * i = 0; i < size-1; i++){
** * **** *** * ** * ** * ****** ** * * * *** *** ** * ** * ** * i-th element with its neighbor to check if they are in order */
* * * * * ** * *** * * ** * ** ** ***** ** ** ****** ** * * *** > x[i+1]){
** * * * *** ** * ** **** ** **** *** ** *** * ****** **** **** * * *** * * * * **** * exchange the values of x[i] and x[i+1] */
***** *** *** * * * * *** ** * ** ** ** * * *** ****** **** * * ** ** ** * **** * * * * temporary; * ** * * *** * ** ** * * * * **
***** * *** * **** ** * * * * ********* * *** ** * ****** * * *** ** **** * * *** = x[i];
* * * *** ** * * **** * * * ** ** ** *** * ** * **** **** * * ** * ** ** * *** ** ** = x[i+1];
*** * * ** ** * * * ** ***** *** *** ** * * ** * *** *** ** * * *** ** * * ** ** * * * = temporary;
* ** * ** ***** **** * * ** ** ***** * *** ***** * ** * ** *
*** * ** ** * * * * ** * * *** * * **** *** ***
** **** * * **
**** * ***** ****** *
* * *** ** * ***** print the array */
* * ** * * **** *** * * ** ** * * sorting: \n");
*** ** ** * *** *** *** i = 0; i < size; i++){
** * * ** ** **** * *** ** * ** * * * * *** * ** * ** ", x[i]); * * * **** * ** * * ** * *
*** ** * * **
* **** * **** ** * * ** * ** * * * ***
* *** *** *** **** ** *
* * * ** ** * * * **** **
** **** * * * * ***** * * * ****** *
**** * ****** * * ** ** *** *** *** **  
* * ** * ** **** ** ***** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** ** * * **** x[] = {77,22,88,11,22};
* ** ** ** * * * * * size = 5;
    
* *** * * * * * * * print the array */
* **** * ** * * ** ** * i = 0; i < size; i++){
***** ** * * ** * ***** * ** **** * * ** * * * ", x[i]); * ** *** * * * * ** * ** *
**** * ** * ** * ****
* *** ****** * ** ** * * *** ** ****
*** * ** ** *
** **** * ******* * * * * * ** I need this to happen size-times */
* * *** ** * *** * j = 0; j < size; j++){
***** ** **** * *** ** * * * * *** ****** ***** from left to right */
**** **** *** * * **** * ** * ** * **** i = 0; i < size-1; i++){
** *** ** **** ** *** * ***** *** ** * ** ** * * ** ** * * * * i-th element with its neighbor to check if they are in order */
**** ** ** ** * * * ** ** * * * * * *** * **** *** * > x[i+1]){
* *** ** * * **** * ** * *** * * * ** ** * *** * *** * * ***** * * * * * * * * * * *** exchange the values of x[i] and x[i+1] */
* ** * * * * *** * ** * ** **** * * *** *** **** *** ** ** * * * * * * ******* **** * * * temporary; ** * * ** ** ** * * *
* ** * **** * * * ** * * ** ** ** * ** * * ** ** * * * ** * * * ** *** ******** * *** = x[i];
** **** * * * *** **** * *** ** *** * *** * * * ****** ** * ** *** *** ** * ** * **** = x[i+1];
* * * * * * ** *** * * ** ** * * *** * *** * ******* ** * *** *** *** ** *** * = temporary;
* ** *** **** * ***** *** *** * * * ***** ** ** *
******** *** *** *** * ** *** * ** * **
** * * * ***** * **
* * *** * ** * ***
**** *** *** ********** print the array */
* * *** * **** * * * * *** * sorting: \n");
* * *** ***** **** *** i = 0; i < size; i++){
*** ** * ** *** **** ** * * ***** * **** ***** * ", x[i]); ****** * * ***** ** * **** * *
* ** * * ** * * ** *
* * * * * * * *** * ***** ** * * *
* * ** * * ** *** ** * *
**** **** **** ****** *
* * * ** * *** * * ** * **** *
* * **** ** **** ** ** ** **** *** * ** * **  
* ** ** * **** ** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.52
©2016-2024

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 1.3k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 663 views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 934 views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 578 views
12,783 questions
183,443 answers
172,219 comments
4,824 users