11-01 Exercise 1: Find out all prime numbers between n and m

0 like 0 dislike
3.4k views

Write a program that get the input of two integers n and m(n < m). Find out all prime numbers between n and m (not include n and m), then display them on the screen.

寫一個程式 輸入兩個整數n和m (n < m)，找出所有n到m之間的質數(不包含n和m)。

Example input 1

1 10

Example output 1

2 3 5 7

 

Example input 2

10 20

Example output 2

11 13 17 19

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 3.4k views

99 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
** ** * **    * **   ** **** *  * ** **  %d",&a ,&b );

    * *   * **  ** ******  * i=a;i<b;i++){
  *     ***** * *    * ******  *  ****** **** ******* *  j=2;j<=b;j++){
*   *** *    ******* * *  **  *  *     *  * ** ** **           ** *        **  * **** ** * && i%j==0) break;
*   * * ** ****  ***  * *****  ** *  ** *  * * **  ***    * ***   *     ****  * ***  ***  if(i==j){
**** **  *  * **  **** **   ***  ** * **    *   ******      * *** * ***** * *   *  *  *  *** ***  ***  ** *   * **
  * *   **  ****  * ****   ** **** ******  **   * **  * * ***** * *      * * *  *******  *  **  *  ** ** * *   *  *   *     ** * ** * ***  ****  * *     ** * *** 
 *  * ** *  ****  * **** **  ***  * * *   *  * *   *  *   * ** * * ******* *      **       *** *  ** * ***  *** ** **  * ******   * * * * ** * *  ** ** 
***  ***** * * ***   *  * ***** ** * * *      ** ** * ****  * **   * * *  *** * ** **  ** *  **  *  ***
*  * ** *      ***  * **   *  * *  ********  ***      **** ********* ***   ***     ***  *   ****  ** *  printf(" %d",i);
*  *  *** ** **  * ** **** *  *   * * *  * ***  * *** ** *  **    *  *****     ** **   *     *
   **    * **  **** * *     **   * *  **  *   * **

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 **          *    ****
 *    *  * * ***   * 
  *    **  *** *  *** *   *

int main()
{
int i,n,m;
*  **  ** * ** ** ****    *       
  ** * *****  **  * *  * *  
 **    * *  *** ** 

{



* ** * *  ***  ** * *   
{
** * * 
  * 
}
 * ** **   *****

 *  *


**  * *    *  ***      


}}
* * 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
***    * * ** ** * 
* *      * ***** * *  * ** 
* * ***    **   *   ***

int main()
{
int i,n,m;
 *      **   **   * ** **   
**** * *** *** * *    
 *******   *  * ** * **

{



 *      *  ** *****
{
*  * **
  * 
}
* **  **   * 

****


* **  * ** *    *** *   * ****


}}
   * 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
**** *** **  * ** *    *  *      ** ****** %d",&a ,&b );

  *  ***   * * *   *** * *** i=a;i<=b;i++){
****  **  *** *      * *  ** ** *  **  ** *** *  *   **    ** j=2;j<=b;j++){
* **    **  * **    *  **** * *      *  ******* * *  *  ** * *   *** * * * *  *   *  *   * ** && i%j==0) break;
*   ** * **   *  ******** ****  *** * * * ******* * *   **  ** * *   ** *    ***    if(i==j){
 * * **  *    ***   *    ***  ****  * ******  **  **  **  *** **   *  *  *  ***       *** *  * ** **** ** *  ***  *  *  
******* ***  *     **  * *  **   *   * *  *  * * * ******  * * **   ***** *  * **  **** *  *   *  * * ** ***  *   *   ** *  * ** ** *     *  *
   * * ** ***  **  ***       * ***** ** *  * ** * ** * **  *   * ** * ***   **  * **** * **  ** *** ** ** *  ** ** **    *       * ***    *** *  **  
******* *    * *  *   *** ** ** * ** *    ** *  * *****  *   ****  **   * ****     *  ** *   * * **       **  *
  **** *     *  ***   *   **** **** * * ** ** * *  *  *    *  **   * *  **    *    **** ******* * * ***  * *   *   **  * printf(" %d",i);
  **  * ** *  **     **   **  *** ****    ***  **   *   ** **  ***  ** *    ** 
  ***    *  *   * ******  *    * **    ***** **    **  * **** 

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
 * **    **   *      * *   **  a,b;
   ***  * *  *  ***  * * * *  ******  %d",&a ,&b );

** ** *       * ***  *** **  *     i=a;i<=b;i++){
  *    *  * **   * **   **   * *** ** * ** *  * **** **  j=2;j<=b;j++){
*    ***  * *  *    *** ***   ** **        * * ** ****   **    *  **    *  ** **    *  ** * * && i%j==0) break;
  ***    ******   ****       *** * ******       ** *  ** *  * * *    *  ****** *    if(i==j){
******   ** * * *** ** ** *   *     * * **   *  ** *   ***** *****   * *  *** *    ****** *****  ***   *  * ** * **  * ",i);
*  * * ** * * * **** * ***  *   *   *** *    * * * * **** **** * * *  *  * *  ** 
 *** ***  *    * **  *   ** ** *  *****    *     **  *  ** **

*   *  *        * * ****     
*  *    ** * **  ** **  ****  0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 * * * ***   ****  *
   **    * ** *  
int main(){
  *  ***  **        **      *    a,b;
*** *     * **   **** * ***     **** ******    * ,&b );

* *  *****   ***    * *   **  **  i=a;i<=b;i++){
  * *    *** ** * *** **** **      ** *** *** * *** *       j=2;j<=b;j++){
*  *** *  * ***  *    * ** * **   * *      ****** *   **** **   ***  ***** *    *** * * && i%j==0) break;
    * *  *   *** ** ***     **   *    **  * *  * **     * ** *  ** **    *    if(i==j) printf("%d ",i);
  **   **** * *   ***   * * ***  *  *  *** ** ***    
    **** *   * ******* ** **
  ***  * **    * *  *  * ** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* * * *******     ****     **  m, n, divider, prime[100], cnt=0, i=0;

*    ***  *  * ***     **  **  *    ** ** *  %d", &m, &n);

 ** ***    *  **  *  ** ****** = m + 1; m < n; m++)
 * *** ***    *  *  ** * *  *
****  **   * * **  **** ** *    *    * **  ****      ** = 2; divider < m; divider++)
     *  *   *  *  *  *         * **** * *  *     **  * 
***   *  * * *   *  ****     * ** *    * **  ***   *  ****    * *******    **   ***  % divider == 0)
 * ** * ***   ** *  *    * *  * **  **    *** * **  **  * **  * *  *   **   *  * **  *   * *   *  * *   
** ** *** * *   *   * *  **    * * *** *  * *  * **
* *  *  *  *  * *    ***  ** **   * * ** ** * **   ** * * == divider)
   ***   **      ** *****   *******  * *   ** *   *   * *** *
*   *****    * *  ** **     ** *  ** *     ** * **    ******  ******* * ** **    *  *  = m;
 ****** ******  **** *    ** *** * *          *    
 **** *   **  ** *  *  * ** 
*  *** *   *  ** **  * *  **   i<cnt;i++)
**   *  ***    * **    *   **  **
 ** *  *  **  **   **  *  ***      *    **  * **  ** *  * ** **  *         ***  prime[i]);
 *   **  * *  **  * *  ***   ***   *   * ***  ****     *  +1 < cnt)
  * * * * ***** *  **  * **** ** * *** ****   **  **  **  * ** *    *  ****     *       *  ");
    }

   *   ** ** *  *     * * **   0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 0
Nice haha
commented by (12.1k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
    int n,m,i,j,k;
    scanf("%d %d",&n,&m);
  *       **** *  *  *  *  *** * ** ** ***
 * ***  ***** * * ***  * * **     ***** **      **      ***  ** *   * 
  *  *    *  ** *****   * *      * **  ** ****  ***      * *   ** * *   **  ** ** **** **
* *    ** *  * * **** ***  *  * **   *  *  *    * **  ** *** * * *** *****  * *    *** * **    **
**    **  ***   ** **   *  ** ** * *** * **  ***  *  * *    * *** *  **    ***  ***   *  *  *
*** * * * *  *** ** * **  ** * * **  ****  *   **      * ***** **  **  *  * * ***  * ***** **  *  **** ***  ****     *  **** *  ** ",i);
***   *    **** ***       *** * **  ** **   ** ** *    ***** *     ***       *  **  ***   ** **  * * ****
** **   *  * *    **** * ********    ** ***   **  *   ***  *  ******  * ** *
 ** ** *    ***       **** **** *  *** ** **   * * *** **** *** ** ***     ** *   ** if(k==0){
  * **  *  * ***  **  **  **  *  ***    **** ** * * **    ** *  *****  * ** *  **** *    *     *** *** ** * * *** *
 * ** ****  *         *** *  *   *  ****    **** * **   *** ***  ****  **   ***** * *** * 
    ***** *** **      *  *****  **** ******** * * *
    }
    return 0;
}
answered by (54 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main(){
int i, a , b;
int flag;
scanf("%d    * *  * * *  ** ,&b);

for **  * *   ** **  
{
 *  **  *   *     *  * * ** ** *** **   is testing\n",i);
***  ** * **** *  ***** *  * * j=0;
 * **** **     * ***  **  *  = 1;
 *  *  ********** *** *   *  * * (j=2;j<i;j++)
* *   ****  * * *    *   *   * * 
  **   *  ** *   **  *   * *  **     * * *     ** * *  * *   **   %d is mode\n",j);
  ** ** **   ****   *** *  * * * *** ** *  *  ****  * reminder=i%j;
  *    * * ** **  ** *******  *** *  ** ** **  ***  *  (reminder == 0)
 ***  *  *  ** *  *   * ** *  **     ***** ****  **  **
**   **  **  **** **   *     *** **** ** ** *   *** ** ***** * *  *  ***    *** * ******  ***    **      *  ** * *** * * * ***
 *****  * *** ** * ** * ** *** *****  *** *    ***     * ***** * ***  ***  ** **  **
** ***** *  ***  *   **    * ****** **      *  *******  * *  * ***     * *  **** * *
   *** *  **   **  * **      * ****  *     **  * *  *  **
*   * *** * ****  ***  *** **
   * **    ****  **  *  *   ** (flag==1)
 ** ** * *   *** *** ****       *** ** ** **  *  **** *  ***     * ",i);
}

return 0;
}
answered by (-141 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.184
©2016-2024

Related questions

0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 2.4k views
0 like 0 dislike
93 answers
11-01 Exercise 3: Fibonacci numbers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 2.9k views
12,783 questions
183,443 answers
172,219 comments
4,824 users