10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
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int main (void)
{
int ** *  ** *    
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f2=2;
else if * ** 
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else f2=4;
******  *   **   *  ***      
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
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    }

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 *  *  *    **      ** * ** * **   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
***   ** * ** *   
int main()
{
   *   *  *   *   *   * n,digits = 0,sum = 0;
  ****   * ***  ***  *  ***   ***  * * *   *** *  
* * *   *    ******** ** * ** {
* ** * *   *** *  * * **  *  * * **** **  *  *   ** = sum + n%10;
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   ********  ** ***** *   *   while (n > 0);
* *** *** ** *  * ****** * ** *** *   **  d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include   * *  ****     * 

int     *  **  * *    **    *  *
int d=1000;

int main(){
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        ****            *  ** *    ****   * ****  ** ***** ** = sum + currentdigit;
*  **** *  ** *   *   *** ** ***  *** *  ***  * *  *  *  = a - (currentdigit * d);
*     * *   ** *  ******   * *  *   * ** *  **    **  * ***** 

 *  ****    * *      * *  * ***  **   * * * * *  ****         ** %d\n", numdigits, sum);

*  **   * *** ***  ** *   * * 
 ***  ***   *   *****       * ** ** ** %d", numdigits, sum);
****** * *  *    *****   **** * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
* *   **  *****   ****** *  ** n,digits = 0,sum = 0;
   **  * *** *** ***   *        * * *  *** *       * ***** * 
 ****** * * ** *     **  * * * {
******  ** **   ******   *  * ** *** *        *    * * *   *  = sum + n%10;
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 * ******* *    ***  *  *  while (n > 0);
 * * *** ******* * *** **   ***** *** ** *  ** * * 
   *  *  * * ***  *  ** *  *  *  * ** *** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
 ******     * *****  ** a,digits=0,sum=0;
    *   *** * *    *    * *  *** *** *   **    * ** 
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   **  *  *  **** **    *  * 
 *  *** *   *    **** **   ***   (a>0);

 *  ** *****  *** ** **  *    **** * %d",digits,sum);
 * **   * * ** *   *  *   **   ***   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
* * *  *  * ***** ***
int main  *** 
{
int  ** *     
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else if  * * 
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else f2=4;
* *   *   * * **   **** ** *
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
* ***   * **    *** * ***  * n,digits = 0,sum = 0;
    ****  **  * * * *  **    * *  **   *  **   *** * *  
 **    *  **    **   ****** {
***  *  ** *** ****  ***    *        **** ** *  **    * * *  = sum + n%10;
    ** * *** *  **    *    *    *    *******   *  * *  
   **     *  *     **** *  **   * ***  * * *** * **  **** * *
 *  ** *****     *    ** *  while (n > 0);
 ***   ****  **    *** * *  **  *** *         **  ***  *
**   * * **   ***  *   ** *      * ****  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
**** **  *  * *** * ****    ****  a=1,b,c,d,e,f,g;
*****   ***  * *    **** ** ***     * *   ***  * * 
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    }
**  * * ***** * **** *   *  *  **   *
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******  *   *     **  * *   *  *  
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  ***   *  ****** *  *   *    ******* *  %d %d %d\n",c,d,e,f);
**  * ******* *****   ***  *   *    * * %d",a,c+d+e+f);
  * ** **  *  **  *   * ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
  *   ****** ****  * ** ***  *  *   ** num,digits,sum=0;
   ** ** * *** *** **  * *** ** **   **  **  ** * ***    *  
******* * * ******      *   ** *  ****  * * * ***  * **      * * *     *  *  *  * ***   &num);
**** ****  *** * * * **  *  *   ***    ** *
 * **  *   ** * *** *   *   
    ** * **   *      ***     * *   **   ******  *  *  **   ** *** ** * *** *   += num % 10;
***      * *****   *****  ***  *     *   * ****  **  ** **  ** *  *  * = num / 10;
** * ***    ***   **    *** *** ** *      * ** * * ** *     **  * *  ** *     * 
    }
*** *  * ***  ***  *    * * * **   *  **  ** %d", digits,sum);

   *  ***  ** *****     * *  * ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output